Given 376  438  476  389  567

After interchanging 1st and 2nd digits

736  348  746  839  657

Now, arranging in descending order 839  746  736  657  348

Here in second place 746

Therefore, 476 is the answer.

8 x 1 – 2 = 6

6 x 2 – 3 = 9

9 x 3 – 4 = 23

23 x 4 – 5 = 87

87 x 5 – 6 = 429 .

In this simple subtraction series, each number decreases by 0.4.

The given numbers are cubes of consecutive natural numbers, in increasing order starting with 4, i.e, 4³ = 64. 64,

The given numbers are alternate prime numbers in decreasing order, starting with 97. Hence, the next number in the series is 47.

Sol: Let 120 divides with 5 i.e., 120÷5=24,

Now with 4 (descending order from 5) => 24÷4=6

Continue this with 6÷3=2

==> 2÷2=1

==> 1÷1=1

The answer is: 1

Difference +1², 2², 3², 4², 5²

4*0.5+1= 3

3*1+1.5= 4.5

4.5*1.5+2=8.75

8.75*2+2.5= 20

20*2.5+3 = 53

8 x 1 – 2 = 6
6 x 2 – 3 = 9
9 x 3 – 4 = 23
23 x 4 – 5 = 87
87 x 5 – 6 = 429 …

1² + (2 * 3) = 7

2² + (3 * 4) = 16

3² + (4 * 5) = 29

4² + (5 * 6) = 46

5² + (6 * 7) = 67

6² + (7 * 8) = 92

Therefore, 92 should be in place of 95.

Explanation:

In this series, 5 is added to the previous number; the number 70 is inserted as every third number.

8*1+1 = 9

9*1.5+1.5 = 15

15*2+2 = 32

32*2.5+2.5 = 82.5

82.5*3+3 = 250.5

Solution:

Logic is 4 × 1.5 = 6, 6 × 2 = 12, 12 × 2.5 = 30, 30 × 3 = 90, 90 × 3.5 = 315, 315 × 4 = 1260. Thus the wrong number is 312.50, it should be 315.