In the first row, 72 ÷ (²⁴/₂) = 72 ÷ 12 = 6. In the second row, 96 ÷ (¹⁶/₂) = 96 ÷ 8 = 12. Let the missing number in the third row be y. Then, 108 ÷ (^y/₂) = 18  or  ^y/₂ = ¹⁰⁸/₁₈ = 6  or  y = 12.

Clearly, (3rd column)² + (2nd column)² = (1st column)² In the first row, 5² + 12² = 13². In the second row, 8² + 15² = 17². Let the missing number in the third row be y. Then y² + 24² = 25² or y² + 576 = 625 or y² = 49 or y = 7.

In the first column, 2 x 1 + 1 = 3. In the second column, 14 x 7 + 7 = 105. Let the missing number in the third column be y. Then, y x 9 + 9 = 117 or  9y = 108  or  y = 12.

Numbers on opposite sides of the central box are equal in magnitude but opposite in sign

In the above figure, the numbers are related as from 1^st and 2^nd figure that 5 + 3 = 8 = 2315, similarly answer can be found as 34 + 11 = 45 = 90 – 45. Therefore missing number is 45.

In the first column, 12 × ( 18 ÷ 3) = 72.

In the third column, 16 × ( 32 ÷ 4) = 128

Let the missing number be x. Then, in the second column, we have :

14 × ( 24 ÷ x) = 112 ⟺ 24 ÷ x = 8 ⟺ x = 3.

In the first column, ³√3 x 6 x 12 = ³√216 = 6.
In the second column, ³√2 x 20 x 25 = ³√1000 = 10.
.’. In the third column, missing number = ³√2 x 4 x 64 = ³√512 = 8.

In the first column, 11² – 1² = 121 – 1 = 120.
In the second column, 7² – 2² = 49 – 4 = 45.
.’. In the third column, missing number = 5² -3²= 25 – 9 = 16.

In the first column, 13 + 7 x 2 = 27.
In the second column, 54 + 45 x 2 = 144.
Let the missing number in the third column be y.
Then, y + 32 x 2 = 68 or y = 68 – 64 = 4.

In the first row, 11 x 2 + 6/₂ = 25,
In the second row, 6 x 2 + ⁸/₂ = 16.
.’.  In the third row, missing number = 5 x 2 + ¹²/₂ = 10 + 6 = 16.

434 – 4^2 = 418

418 – 5^2 = 393

393 – 6^2 = 357

357- 7^2 =308

308- 8^2 = 244

84/1.2 = 70 + 2 = 72

72/1.2= 60 + 6 = 66

66/1.2 = 55 + 10 = 65

65/1.2 = 54.17 + 14 = 68.17

156 + 11 = 167

167 + 22 =189

189 + 33 =222

222 + 44 = 266

266 + 55 = 321