order of first letters is A,B,C,D
in the same way in second letters also

The given series consists of three consecutive letters from the end, then two letters skipped, then again three consecutive letters from the end so on

The given sequence is a combination of two series:
I. M, O, R, V and II. N, L, I, ?

The first letter of the first, second, third, …. terms are respectively moved two, three, four, … steps forward to obtain the first letter of the successive term.
The second letter of the first, second, third…. terms are respectively moved two, three, four, … steps backward to obtain the second letter of the successive terms.

first letter of the term is +1 of the second letter of previous term.

second letter of the term is adding of 0,1,2,3,… to the first letter.

The given sequence is a combination of two series:
I. C, F, I, L, O, ? and II. Z, X, V, T, ?

The number of letters in the terms goes on increasing by 1 at each step.
Each term consists  of letters in alphabetical order.
The last letter of each term and the first letter of the next term are alternate.

The given sequence consists of two series :
I.    Z, W, T, V, Q, ? in which each letter is moved three steps backward to obtain the next term.
II.   S, O, K, G in which each letter is moved four steps backward to obtain the next term

In this series, the third letter is repeated as the first letter of the next segment. The middle letter, A, remains static. The third letters are in alphabetical order, beginning with R.

The series is ADBC ACBD ABED DEBA DBCA CBDA.

Thus, the letters are equidistant from the beginning and the end of series.

Here,

W + 3 = Z

S + 3 = V

O + 3 = R

Similarly,

J + 3 = M

F + 3 = I

B + 3 = E

The pattern of letters in the series is :

MNOM MNOM MNOM MNOM

According to the English alphabetical series:

L – 11 = A

N – 11 = C

P – 11 = E

Q – 11 = F

Similarly,

T – 11 = I

U – 11 = J

X – 11 = M

Y – 11 = N

ABCDEFGHIJKLMNOPQRSTUVWXYZ.

First of all we can take the first two terms,

A C E

G J I

( A+6 ) We get G

( C+7 ) We get J

( E+4 ) We get I

Now taking the third term and follow the same procedure as above,

M Q M

? ? ?

( M+6 ) We get S

( Q+7 ) we get X

( M+4) We get Q

Finally, the next term will be SXQ.

Study the pattern carefully. In the first segment, two letters face right and the next two face left. The first letter in the second segment repeats the last letter of the previous segment. The same is true for the third segment. But the fourth segment changes again; it is the opposite of the first segment, so the last two letters must face right.

Because the letters are the same, concentrate on the number series, which is a simple 2, 3, 4, 5, 6 series, and follows each letter in order.

This is an alternating series. The first and third segments are repeated. The second segment is simply upside down.

The first two letters, PQ, are static. The third letter is in alphabetical order, beginning with R. The number series is in descending order beginning with 5.

This is an alternating series in alphabetical order. The middle letters follow the order ABCDE. The first and third letters are alphabetical beginning with J. The third letter is repeated as the first letter in each subsequent three-letter segment.

Look for opposites in this series of figures. The first and second segments are opposites of each other. The same is true for the third and fourth segments.

This sequence concerns the number of sides on each figure. In the first segment, the three figures have one side, and then two sides, and then three sides. In the second segment, the number of sides increases and then decreases. In the third segment, the number of sides continues to decrease

In this series, the figures increase the amount of shading by one-fourth and, once a square is completely shaded, starts over with an unshaded square. In the second segment, you will notice that the figure goes from completely shaded to completely unshaded.

There are three series to look for here. The first letters are alphabetical in reverse: Z, Y, X, W, V. The second letters are in alphabetical order, beginning with A. The number series is as follows: 5, 4, 6, 3, 7.

In each column let the number at the top be ‘X’ and the one at the bottom by ‘Y’ then Y= x(x-1)

In column 1 6=3(3-1): 6=6

Look carefully at the number of dots in each domino. The first segment goes from five to three to one. The second segment goes from one to three to five. The third segment repeats the first segment.

In this series, the letters remain the same: DEF.

The subscript numbers follow this series:

111, 112, 122, 222, 223, 233, 333, .

This series consists of letters in a reverse alphabetical order.

Each arrow in this continuing series moves a few degrees in a clockwise direction. Think of these arrows as the big hand on a clock. The first arrow is at noon. The last arrow before the blank would be 12:40. Option D, the correct answer, is at 12:45.