Volume of water = Volume of conical flask = (1/3)πr²h
Now, the water is poured into cylindrical flask.
∴ Volume of cylinder = Volumes of water
⇒ π (mr)² x Height = (1/3)πr²h
∴ Height = h/3m²

Radius of larger ball = 8 cm

So ,

Volume of larger ball = 4/3 * pie * ( 8) ³ cm³

And ,

Radius of smaller ball = 2 cm

Volume of smaller ball = 4/3 * pie * ( 2 ) ³ cm³ .

Let the number of mmaller balls be x .

A / q ,

x * 4/3 * pie * ( 2 ) ³ = 4/3 * pie * ( 8 ) ³

=> x = 4 * 4 * 4

=> x = 64 .

Required number of balls = 64 .

Since the diameters of two cones are equal, their radius will also be the same.
Let the slant height of the two cones be l₁ and l₂ respectively.

Therefore,
l₁ : l₂ = 7 : 4
The curved surface area of the two cones are
πrl₁ and πrl₂
So, the ratio of their curved surface area are
πrl₁/πrl₂
π and r are cancelled.
⇒ l₁/l₂ = 7/4
So, the ratio of the curved surface area of two cones is 7 : 4
Answer.

Volume =4096 cm cube
Volume =side 3
Side=cube root of 4096
Side = 16cm
Therefore surface area =6×side 2=6×16^2
============6×256
============1,536cm

Since the cube has 6 faces divide it by 6.
= 2400 ÷ 6
=400
1 face = 400 area

since the surface of the cube is square and its area is ‘side square’
find the square root of 400

which is 20 cm (side)

The clue given can be put in an equation and solved for the radius. The diameter is then d=2r.  4πr3/3 = 4πr2 r3 – 3r2 = 0 r2(r-3) = 0 Since r>0, we conclude that r=3 cm. Thus the diameter is 6 cm.

Given, thickness of iron =3cm
external diameter = 56cm
Length of tube = 182cm
We know,
volume of hollow cylinder = πh(R²−r²)
∴ internal diameter = external diameter−2×thickness of iron
= 56−2×3
= 56−6
= 50cm

=> Outer radius(R) = 56÷2 = 28cm
inner radius(r) = 50÷2 = 25cm
∴ Volume of hollow cylinder = πh(R²−r²)
= 3.14×182(28²−25²)
= 3.14×82×159
= 90865.32cm³

slant height = sqrt (12^2+9^2) = 15

Tota perimeter of the cone = 2*22/7*9+15+15+18 = 56.57+48=104.57

paper perimeter = 2(L+10)= 104.57

L=52.28-10 = 42.28

Given, thickness of iron =3cm
external diameter = 56cm
Length of tube = 182cm
We know,
volume of hollow cylinder = πh(R²−r²)
∴ internal diameter = external diameter−2×thickness of iron
= 56−2×3
= 56−6
= 50cm

=> Outer radius(R) = 56÷2 = 28cm
inner radius(r) = 50÷2 = 25cm
∴ Volume of hollow cylinder = πh(R²−r²)
= 3.14×182(28²−25²)
= 3.14×82×159
= 90865.32cm³

Let the radii be 2x and 3x
let the height be 5y and 3y

so,
ratio of volume =r²h/R²H =(2x)²×5y/(3x)²×3y =20x²y/27x²y =20/27

ratio of CSA =rh/RH =2x×5y/3x×3y =10xy/9xy =10/9

Let the radii be 2x and 3x
let the height be 5y and 3y

so,
ratio of volume =r²h/R²H =(2x)²×5y/(3x)²×3y =20x²y/27x²y =20/27

ratio of CSA =rh/RH =2x×5y/3x×3y =10xy/9xy =10/9

Clearly, l = (48 – 16)m = 32 m,

b = (36 -16)m = 20 m,

h = 8 m.

 Volume of the box = (32 x 20 x 8) m³ = 5120 m³.

1 hectare = 10,000 m^2
Area = (1.5 x 10000) m^2 = 15000 m^2.
Depth = 5/100 m=1/20 m
Volume = (Area x Depth)
=15000 x1/20 m^3
= 750 m^3