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Arun is twice efficient as Bala and together they do the same work in as much time as Chitra and David together. If Chitra and David can complete the work in 20 and 30 days respectively, working alone, then in how many days A can complete the work individually?

A.

12 days

B.

30 days

C.

24 days

D.

18 days

Answer with explanation

Answer: Option DExplanation

1/x + 1/2x = 1/20 + 1/30

3/2x = 1/12

Number of days taken by Arun = 18 days

Workspace

Ram decided to plough a farmland in 50 days. He employed 50 men in the beginning and 50 more after 35 days and completed the construction in stipulated time. If he had not employed the additional men, how many days behind schedule would it have been finished?

A.

10 days

B.

16 days

C.

15 days

D.

18 days

Answer with explanation

Answer: Option CExplanation

Given that, 50 men employed for 35 days and 50 more men employed for 15 days so that the work could be finished in 50 days.

Thus, the total work=50*35+(50+50)15=3250

Suppose, it takes x days to the finish the whole work, if additional men were not employed.

So, we have an equation here.

50*x=3250

x=65 days

Therefore, it takes 15 days more than stipulated time.

Workspace

A and B can do a piece of work in 30 days, while B and C can do the same work in 24 days and C and A in 20 days. They all work together for 10 days when B and C leave. How many days more will A take to finish the work?

A.

18 days

B.

24 days

C.

30 days

D.

36 days

Answer with explanation

Answer: Option AExplanation

Workspace

A and B can do a piece of work in 4 days, while C and D can do the same work in 12 days. In how many days will A, B, C and D do it together?

A.

4 days

B.

12 days

C.

2 days

D.

3 days

Answer with explanation

Answer: Option DExplanation

A, B, C and D will together take ¼ + 1/12 = 4/12 = 1/3 ⇒ 3 days to complete the work.

Workspace

A.

1800 litres

B.

2400 litres

C.

1200 litres

D.

1500 litres

Answer with explanation

Answer: Option CExplanation

In one minute, 1/20 + 1/30 = 1/12 of the tank can be filled.

The whole can be filled in 12 minutes.

Outlet tap is taking 12 minutes to empty half tank at the speed of 50 litres per minute.

Volume of half tank = 50 x 12 = 600 liters.

Full tank = 1200 liters.

Workspace

A contractor undertake to finish a certain work in 124 days and employed 120 men. After 64 days, he found that he had already done 2/3 of the work. How many men can be discharged so that the work may finish in time ?

A.

56

B.

64

C.

62

D.

58

Answer with explanation

Answer: Option AExplanation

Days remaining 124 – 64 = 60 days

Remaining work = 1 – 2/3 = 1/3

Let men required men for working remaining days be ‘m’

So men required = (120 x 64)/2 = (m x 60)/1 => m = 64

Men discharge = 120 – 64 = 56 men.

Workspace

A.

20 days

B.

25 days

C.

35 days

D.

30 days

Answer with explanation

Answer: Option DExplanation

Assume the total work to be 600 units. (LCM of all the numbers)

Then Sandeep’s 1 day work = 8 units.

All three’s 1 day work = 40 units.All work together in the first 2 days

Work done in the first 2 days = 40 × 2 = 80 units

Sandeep alone works during the last 40 days

Work done in the last 40 days = 40 × 8 = 320 units

Remaining work = 600 – (320 + 80) = 200 units

This work is done by pradeep and sandeep in 10 days.

Pradeep and Sandeep together’s 1 day work = 20 units

Sekar’s 1 day work = All three 1 day work – Pradeep and Sandeep together’s 1 day work = 40 units – 20 units = 20 units

Sekar can do the work of 600 units in 30 days.

Workspace

A.

24 days

B.

35 days

C.

32 days

D.

22 days

Answer with explanation

Answer: Option BExplanation

30 workers work in pairs, with no same pair of workers working together twice

29[1/w1 + 1/w2 ….. + 1/w30] + 6[1/w1 + 1/w2 ….. + 1/w30] = 1

[1/w1 + 1/w2 ….. + 1/w30] = 1/35

35 days.

Workspace

A.

5 days

B.

8 days

C.

3 days

D.

7 days

Answer with explanation

Answer: Option DExplanation

Workspace

It takes 6 workers a total of 10 hours to assemble a computer, with each working at the same rate. If six workers start at 9.00 am, and one worker per hour is added beginning at 3.00 pm, at what time will the computer assembled?

A.

7.00 PM

B.

4.00 PM

C.

5.00 PM

D.

Answer with explanation

Answer: Option DExplanation

–> 6 workers complete some work in 10 hours.

–> 1 worker completes the same work in 60 hours.

–> Let the total work be equivalent to 60 man-hours.

–> From 9.00 am to 3.00 pm, all 6 workers work together for 6 hours.

–> Amount of work done by 6 workers in 6 hours is 6 * 6 = 36 man-hours

–> From 3.00 pm to 4.00 pm, 7 man-hours of work will be done.

–> From 4.00 pm to 5.00 pm, 8 man-hours of work will be done.

–> From 5.00 pm to 6.00 pm, 9 man-hours of work will be done.

–> Thus, total amount of work done up to 6.00 pm is 36 + 7 + 8 + 9 = 60 man-hours

–> Thus, the computer will be assembled at 6.00 pm.

Workspace

A.

15

B.

20

C.

25

D.

30

Answer with explanation

Answer: Option AExplanation

Combined efficiency of all the three boats = 60 passenger/trip

Now, consider option(a)

15 trips and 150 passengers means efficiency of B1 = 10 passenger/trip

which means in carrying 50 passengers B1 must has taken 5 trips. So the rest trips equal to 5 (10-5 = 5) in which B2 and B3 together carried remaining 250 (300 – 50 = 250) Passengers.

Therefore the efficiency of B2 and B3 = 250/5 = 50 passenger/trip

Since, the combined efficiency of B1, B2 and B3 is 60. Which is same as given in the first statement hence option(a) is correct.

Workspace

A.

21 4/9 Days

B.

21 5/6 Days

C.

21 7/8 Days

D.

21 Days

Answer with explanation

Answer: Option BExplanation

First day = 1/30

Second day = 1/30+1/45

Third day = 1/30+1/60

3 days work = 3/30+1/45+1/60 = 25/180

3*7 = 21 days work = 175/180

Now 1/36 work is left which can be completed by A alone

1/36*30 = 5/6

21+5/6 = 21 5/6 Days

Workspace

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