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A Learning Portal from Recruitment India

A train Express A leaves Delhi at 5 a.m and reaches Mumbai at 9 a.m.Another train Express B leaves Mumbai at 7 a.m and reaches Delhi at 10.30 a.m.At what time do they cross each other after 7 a.m ?

A.

50m

B.

52m

C.

56m

D.

54m

Answer with explanation

Answer: Option CExplanation

Speed of Express A = x/4kmph

Speed of Express B = 2x/7kmph =>(t=3.30 = 3(1/2) = 7/2)

Trains will meet T hours after 7 a.m

(x/4)(y+2) + (2x/7)y = x

(y+2)/4 + (2y/7) = 1

(7y+14+8y)/28 = 1

15y = 28-14

Y =(14/15)×60 = 56 min

Workspace

A.

9

B.

6

C.

7

D.

8

Answer with explanation

Answer: Option AExplanation

The second car overtake the first car in x hours

Distance covered by the first car in x hours = Distance covered by the second car in x hours

10x = x/2[2a + (x-1)d]

10x = x/2[2*8 + (x-1)1/2]

x = 40 -31 = 9

Workspace

A.

1

B.

2

C.

3

D.

4

Answer with explanation

Answer: Option BExplanation

First person speed = 25 m/s * 18/5 = 90 kmph

Second person speed = 35 m/s * 18/5 = 126 kmph

First person covers 90 * 10 = 900km

900/450 = 2

Workspace

A thief is spotted by a policeman from a distance of 200 metre. When the policeman starts chasing , the thief also starts running. If the speed of the thief be 16kmph and that of policeman be 20kmph, how far the thief will have run before he is overtaken?

A.

750 m

B.

650 m

C.

700 m

D.

800 m

Answer with explanation

Answer: Option DExplanation

d = 200 m, a = 16kmph = 40/9 m/s, b = 20kmph = 50/9 m/s

Required Distance D = d*(a/b-a)b= 200*(40/9/10/9) = 800m

Workspace

Mr.Kavin walks at 4/5 of his normal speed and takes 60 minutes more than the usual time. What will be the new time taken by Mr. Kavin?

A.

300 minutes

B.

220 minutes

C.

235 minutes

D.

260 minutes

Answer with explanation

Answer: Option AExplanation

4/5 of speed = 5/4 of original time

5/4 of original time = original time + 60 minutes;

1/4 of original time = 60 minutes;

Thus, original time = 60*4 = 240 minutes = 240 + 60 = 300 minutes

Workspace

A bus leaves the stop 30 minutes before the scheduled time. The driver decreases its speed by 30km/hr. At the next bus stop 180 km away, the bus reached on time. Find the original speed of the bus?

A.

130km/hr

B.

120km/hr

C.

140km/hr

D.

None of these

Answer with explanation

Answer: Option BExplanation

Distance = 180km, actual speed = x and actual time = t

180 = x*t

180 = (x – 30)*(t +1/2)

Solve both equation, we will get x = 120km/hr

Workspace

A train 300 metres long is running at a speed of 90 km/hr. How many seconds will it take to cross a 200 metres long train running in the same direction at a speed of 60 km/hr?

A.

70 sec

B.

** **50 sec

C.

60 sec

D.

None of these

Answer with explanation

Answer: Option CExplanation

Workspace

A.

3560 sec

B.

3600 sec

C.

3576 sec

D.

can’t be determined

Answer with explanation

Answer: Option CExplanation

Workspace

A fast train takes 3 hours less than the slow train for a journey of 600km. If the speed of the slow train is 10km/hr less than the fast train the speed of the slow train is

A.

30km/hr

B.

35km/hr

C.

40km/hr

D.

45km/hr

Answer with explanation

Answer: Option CExplanation

Workspace

A truck covers a distance of 376 km at a certain speed in 8 hours. How much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 14 km more than that travelled by the truck?

A.

6 hours8 hours

B.

8 hours

C.

4 hours

D.

5 hours

Answer with explanation

Answer: Option AExplanation

Speed of the truck = Distance/time

= 376/8 = 47 kmph

Now, speed of car = (speed of truck + 18) kmph

= (47 + 18) = 65 kmph

Distance travelled by car = 376 + 14 = 390 km

Time taken by car = Distance/Speed

= 390/65

= 6 hours

Workspace

In a kilometer race, A beats B by 100 meters. B beats C by 100 meters. By how much meters does A beat C in the same race?

A.

200 meters

B.

180 meters

C.

190 meters

D.

210 meters

Answer with explanation

Answer: Option CExplanation

⇒ While A covers 1000 meters, B can cover 900 meters

⇒ While B covers 1000 meters, C can cover 900 meters

⇒ Lets assume that all three of them are running same race. So when B runs 900 meters, C can run 900 × 9/10 =810

⇒ So A can beat C by 190 meters

Workspace

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