Let the number of coins of Rs. 1, Rs. 2 and Rs. 10 be 2x, 5x and 6x respectively.

Therefore, Rs. 1 amounts to 2x

Rs. 2 amounts to 10x

And Rs. 10 amounts to 60x

Since, the total amount is Rs. 360

2x + 10x + 60x = 360

72x = 360 => x = 5

Therefore,

Rs. 1 = 2x = 2 * 5 = 10

Rs. 2 = 10x = 10 * 5 = 50

Rs. 10 = 60x = 60 * 5 = 300

Total no. of Rs. 1 coins = 10/1 = 10

Total no. of Rs. 2 coins = 50/2 = 25

Total no. of Rs. 10 coins = 300/10 = 30

Part of the tank A can fill in 1 hr = 1/12

Let B can fill the tank in x hrs, then according to the question,

1/x + 1/12 = 1/8

x = 24 hrs

Also let C can empty the filled tank in y hrs then according to the question,

1/y – 1/ 12 = 1/15

1/y = 9/60

y = 20/3 hrs

Ratio of efficiencies of A, B and C = 1/12 : 1/24 : 3/20 = 10:5:18 = 20:10:36

assume the quantity of bucket A is 100 litres

And the quantity of bucket B is 400 litres

For bucket A,

Water = 40 L, milk = 60 L, liquid L = 0 litre

For bucket B,

Water = 35 % of 400 =140 L, milk = 40 % of 400 = 160 L, liquid L =25 % of 400 = 100 L

Final mixture,

Water = 180 L, milk = 220, liquid L = 100 L

Ratio of water and milk in new mixture = 180/500 : 200/500

36% : 44%

for alloy A (40g),

Zinc : copper = 6:9

Zinc = 40 X 6/ (6+9) = 16g

Copper = 40 X 9 / (9+6) = 24g

For alloy B (60g),

Zinc : copper = 7:11

Zinc = 60 X 7/(7+11) = 70/3g

Copper = 60 X 11 / (7+11) = 110/3g

So, in alloy C,

Zinc = 16 + 70/3 = 118/3g

Copper = 24 + 110/3 = 182/3g

Therefore the required ratio = 118:182 = 59:91

Let the amounts of Alka, Sudha and Shailja be 3x,4x and 5x respectively.

When 8000 is added, let their amounts be 4k,5k and 6k respectively.

3x + 8000=4k….(1)

4x + 8000=5k….(2)

5x + 8000=6k….(3)

On solving we get x=8000 and k=8000

Thus, Shailja’s amount=5 x 8000=Rs.40,000

Explanation:

If you double the sides of a cube, the ratio of the surface areas of the old and new cubes will be 1: 4. The ratio of the volumes of the old and new cubes will be 1: 8.

Weight is proportional to volume. So, If the first weighs 6 pounds, the second weighs 6×8 pounds =48.

A+B+C = 1170

4A = 3B = 2C = x

A:B:C = 1/4:1/3:1/2 = 3:4:6

6/13 * 1170 = Rs.540

In this type of question, we will first try to calculate the ratio of two persons. Once we get ratio then we can easily get our answer. So let us solve this.

Given,
x = y;
Or, x-y = 0;
Or, (x-y)² = 0;
Or, x²+y²-2xy = 0;
Or, x²+y² = 2xy
It means that, x²+y² varies as xy.

Let the numbers be 3x, 2x and 5x.
Then,
9x + 4x + 25x =1862
⇒ 38x = 1862
⇒ x = 49 ⇒ x = 7.
middle number = 2x = 14

Let us assume 2:3 as 2x : 3x

2x   3x

8x cube + 27x cube = 945

35x cube = 945

x cube = 27 => x = 3

Let C = x. Then A = (x—20) and B = (x—40).
x + x – 20 + x – 40 = 120 Or x=60.
A:B:C = 40:20:60 = 2:1 :3.
B’s share = Rs. 120*(1/6) = Rs. 20

Let present age of A and B be 4x and 5x.
18 years ago their ages;
(4x-18)/(5x-18) = 11/16;
Or, 64x-288 = 55x-198;
Or, 64x-55x = -198+288;
Or, 9x = 90;
Or, x = 90/9 = 10;
Sum of the present ages = 40+50 = 90 years.

Let the third proportion to 9 & 12 be ‘x’.

=> 9:12 = 12 :p

=> p = 12×12/9 = 16.

Given ratio = 7 : 5 : 3 : 4, Sum of ratio terms = 19.

Smallest part =  (76*3/19)  = 12

let x = 1k and y = 3k, so

A/D = (A/B)*(B*C)*(C/D)
= (2/3)*(4/5)*(5/9)
= (2*4*5)/(3*5*9)
= 8/27.

a:b :: c:d

4:5 :: 8:x

=> 4/5 = 8/x
=> x = 40/4
=> x = 10