The ratio of ages ,

=> 3:1

Let the age of raju be 3x .

And age of biju be x.

From the question,

=> x=15.

So, The age of raju is 3×15 =45years.

The age of biju=> 15.

Let the number of boys in school be b

Let the number of girls in school be g.

Therefore , According to Question , 10% of boys is equal to 1/4 of girls→

10b/100 = 1g/4

or, 4×10b = 100×g

or, 40b = 100g

or, b/g = 100/40

or, b:g = 5:2

Let 2A = 3B = 4C = x

So, A = x/2 B = x/3 C = x/4

The L.C.M of 2, 3 and 4 is 12

Therefore, A : B : C = x/2 × 12 : x/3 × 12 : x/4 = 12

= 6x : 4x : 3x

= 6 : 4 : 3

Therefore, A : B : C = 6 : 4 : 3

Let the first and the third parts be 3x and 5x.

Second part = 1/4 of third part.

= (1/4) × 5x

= 5x/4

Therefore, 3x + (5x/4) + 5x = 370

(12x + 5x + 20x)/4 = 370

37x/4 = 370

x = (370 × 4)/37

x = 10 × 4

x = 40

Therefore, first part = 3x

= 3 × 40

= $120

Second part = 5x/4

= 5 × 40/4

= $50

Third part = 5x

= 5 × 40

= $ 200

Let the third proportional of 16 and 20 be x.

Then 16, 20, x are in proportion.

This means 16 : 20 = 20 : x

So, 16 × x = 20 × 20

x = (20 × 20)/16 = 25

Therefore, the third proportional of 16 and 20 is 25.

Total quantity of mixture = 13 liters

3 litres of mixture is removed from the container – So, let’s forget this altogether!
Now, you are left with only 10 litres of mixture in 3:2 ratio.

We add 3 litres milk to this.

So, milk in new mix is = 6 liters + 3 litres = 9 litres
Water= 4 litres

Ratio of milk : water = 9 : 4

Assume that the daily wages of man, women and daughter are Rs 5x, Rs. 4x, Rs 3x respectively.
Multiply (no. of days) with (assumed daily wage) of each person to calculate the value of x.
[3 x (5x)] + [2 x (4x)] + [4 x (3x)] = 105
[15x + 8x + 12x] = 105
35x = 105
x = 3
Hence, man’s daily wage = 5x = 5 x 3 = Rs. 15
Wife’s daily wage = 4x = 4 x 3 = Rs. 12
Daughter’s daily wage = 3x = 3 x 3 = Rs. 9

Let the value of one rupee, 50 paise and 25 paise be 11x, 9x, 5x respectively.

No. of 1 rupee coins = (11x / 1) =11x
No. of 50 paise coins = (9x / 0.5) = 18x
No. of 25 paise coins = (5x / 0.25) = 20x

11x + 18x + 9x = 342
38x = 342
x = 9

Therefore, no. of 1 rupee coins = 11 x 9 = 99 coins
No. of 50 paise coins = 18 x 9 = 162 coins
No. of 25 paise coins = 20 x 9 = 180 coins

Let salary of
A = 2k,
B = 3k,
C = 5k

=>A’s new salary = 115/100 of 2k = 115/100 x 2k = 23k/13

=>B’s new salary = 110/100 of 3k = 110/100 x 3k = 33k/10

=>C’s new salary = 120/100 of 5k = 120/100 x 5k = 6k

Hence,new ratio = 23k/13 : 33k/10 : 6k = 23 : 33 : 60

Milk:Water (Initial Ratio) = 5:1 i.e. 5 parts of milk out of 6 (5 + 1) parts of the mixture

Milk:Water (Final Ratio) = 5:2 i.e. 5 parts of milk out of 7 (5 + 2) parts of the mixMilkture

On comparing, 1 part of the mixture has been added (5 litres of water is added). So, 1 part of the mixture = 5 litres

Quantity of milk in the original mixture = 5 parts i.e. 5*5 = 25 litres

Let the share of c be X
then b gets 1/4 of c
so
B = X/4
& a gets two third of B
then
A = 2/3*X/4 = X/6

Now

=> X +X/4 +X/6 = 680

=> take LCM

=>( 12x+3x+2x)/12 = 680

=> 17x = 680×12

=> X = 680*12/15

=> X = 40*12

=> X = 480

so

c got = 480Rs

B got = 480/4 = 120 Rs

A got = 480/6 = 80 Rs

Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.

Then, sum of their values = Rs.		25x	+	10 x 2x	+	5 x 3x		= Rs.	60x
		100		100		100			100

	60x	= 30	x =	30 x 100	= 50.
	100			60

Hence, the number of 5 p coins = (3 x 50) = 150.

Let the three parts be A, B, C. Then,

A : B = 2 : 3 and B : C = 5 : 8 =		5 x	3		:		8 x	3		= 3 :	24
			5					5			5

A : B : C = 2 : 3 :	24	= 10 : 15 : 24
	5

B =

98 x

15

= 30.

Quantity of milk =		60 x	2	litres = 40 litres.
			3

Quantity of water in it = (60- 40) litres = 20 litres.

New ratio = 1 : 2

Let quantity of water to be added further be x litres.

Then, milk : water =		40		.
		20 + x

Now,		40		=	1
		20 + x			2

 20 + x = 80

 x = 60.

 Quantity of water to be added = 60 litres.

A                   B                 C

3x                 4x                5x

(3x+x)          2x               (5x+x)         (B Gives 1/4 to A and 1/4 to C)

=4x              2x                 6x

(4x+x)          2x                 5x              ( C Gives 1/6 to A)

=5x              2x                 5x

Therefore, 5 : 2 : 5