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How many kg of wheat at Rs.54 per kg must be mixed with 30 kg of wheat at Rs.40 per kg, so that on selling the mixture at Rs.48.4 per kg, there will be a profit of 10%?

A.

15

B.

12

C.

18

D.

22

Answer with explanation

Answer: Option AExplanation

Let number of kg of Rs. 54/kg wheat be ‘X’.

SP of mixture = Rs. 48.4/kg

Profit =10%

WKT,CP = SP[100/(100 + profit)]

Therefore, CP of mixture = 48.4[100/(100 + 10)]

= 48.4[100/110]

= Rs. 44/kg

As per the question,

Total CP of Rs.54/kg wheat + Total CP of Rs.40/kg wheat = Total CP of Rs.44/kg mixture

X(54) + 30(40) = (X + 30)44

54X + 1200 = 44X + 1320

54X – 44X = 1320 – 1200

10X = 120

x = 12

Hence,12 kg of Rs.54/kg wheat is mixed.

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‘A’ sold an article to ‘B’ at a profit of 20%. ‘B’ sold the same article to ‘C’ at a loss of 25% and ‘C’ sold the same article to ‘D’ at a profit of 40%. If ‘D’ paid Rs 252 for the article, then find how much did ‘A’ pay for it?

A.

Rs.196

B.

Rs.210

C.

Rs.200

D.

Rs.235

Answer with explanation

Answer: Option CExplanation

Let the article costs ‘X’ to A

Cost price of B = 1.2X

Cost price of C = 0.75(1.2X) = 0.9X

Cost price of D = 1.4(0.9X) = 1.26X = 252

Amount paid by A for the article = Rs. 200.

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A man bought a horse for a certain sum and sold it, at a loss of 8 % on his outlay. If he had received Rs. 1800 more, he would have gained 14½ % on his outlay. What did the horse cost?

A.

Rs. 6500

B.

Rs. 8,000

C.

Rs. 5,000

D.

Rs. 3,500

Answer with explanation

Answer: Option BExplanation

CP = (Difference in SP) ÷ (% Difference in profit) CP of the horse = 1800×100/14.5-(-8) = 1800×100/22.5 ⇒ CP = 8000.

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Mr. Richard bought two pens which together cost him Rs.440. He sold one of the watches at a loss of 20% and the other one at a gain of 40%. The selling price of both watches are same. Then find out the cost price of both watches.

A.

Rs.160 and Rs.280

B.

Rs.170 and Rs.270

C.

Rs.140 and Rs.300

D.

Rs.150 and Rs.290

Answer with explanation

Answer: Option AExplanation

80/100 * x = 140/100 * y

x = 7/4y

x + y = 440

7/4 y + y = 440

y = 160 ; x = 280

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A.

Rs.2000

B.

Rs.1200

C.

Rs.1600

D.

Rs.1500

Answer with explanation

Answer: Option AExplanation

Profit = 25% = 1/4

Let CP of Mukesh’s article = 4x & Profit = x; SP = 4x + x = 5x

Let CP of Rakesh’s article = 4y = 5x —(1)[Selling price of Mukesh’s article = Cost Price of Rakesh’s article]

x – y = 100—-(2)

y = 500

Selling price = 5x = 4y = 2000

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A and B, there are two companies, selling the packs of cold-drinks. For the same selling price A gives two successive discounts of 10% and 25%. While B sells it by giving two successive discounts of 15% and 20%. What is the ratio of their marked price?

A.

143 : 144

B.

136 : 135

C.

73 : 77

D.

19 : 11

Answer with explanation

Answer: Option BExplanation

A = 90/100*75/100

= .675

B = 85/100*80/100

= .68

680:675

136:135

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The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, find out the value of x

A.

13

B.

14

C.

15

D.

16

Answer with explanation

Answer: Option DExplanation

We have 3 elements here CP-cost price, SP-selling price, and profit percentage Profit%.

So the** equations** relating them are:

- Profit=SP-CP (for loss its CP-SP)
- Profit%=((SP-CP)/CP)*100

**Solution:**

Since we don’t know the cost of the article it is ok to assume a value initially.

Let the CP of each article =1 unit.

CP of 20 articles =20 units

SP of x articles=CP of 20 articles= 20 units

SP of 1 article = 20/x

using formula Profit%=((SP-CP)/CP)*100 for 1 article as profit% is a constant for each article.

25=[(20-x)/x)]*100

=> 25x/100 = 20-x

=> x/4 = 20-x

=> 5x=80

solving we get **x=16 units**.

(OR)

Profit%= (purchased qty – selleing qty)/selling qty × 100

25=(20-x)/x *100

1/4=(20-x)/x

x=80–4x

5x=80

x=16

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By selling a house for Rs.45000, it was found that 1/8 of the outlay was gained, what ought the selling to price to have been in order to have lost 5 p.c?

A.

Rs.38750

B.

Rs.38000

C.

Rs.40000

D.

Rs 42000

Answer with explanation

Answer: Option BExplanation

Let the original cost of the house be = x

Selling price of the house = ₹ 45,000

The man gained 1/8 of the outlay, his gain was =(1/8)x

That is equal to 45,000.

(1/8)x= 45,000

x = 360,000

The original price of the house was ₹360,000.

If he sells the house in order to have loss 5%, the amount would be

= 360,000-(5% of 360,000)

= 360,000 – 18,000

= ₹ 342,000

The selling price would be ₹ 342,000 in order to have loss 5%

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A seller marked up her product by 25% and then gives a discount of 25%. Besides he cheats customer by 200g , i.e., He gave 800g instead of 1000g. What is his net profit percentage?(rounded off to two decimal points)

A.

12.61%

B.

22.36%

C.

14.26%

D.

None of these

Answer with explanation

Answer: Option DExplanation

Let cost price =100,

Marked price = 125,

Discount of 25%, so Sp = 125*(75/100) = 93.75

Net profit percentage = (93.75/800)*1000

=> 122.1875

=> 122.1875 – 100

=> 22.19%

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