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wo trains 200 m and 150 m long are running on parallel rails at the rate of 40 kmph and 45 kmph respectively. In how much time will they cross each other, if they are sunning the same direction?
72 sec
132 sec
192 sec
252 sec
Answer with explanation
Answer: Option DExplanation


Total distance covered = Sum of lengths of trains = 350 m.  

Workspace
The length of the bridge, which a train 130 meters long and travelling at 45 km/hr can cross in 30 seconds, is:
200m
225 m
245 m
250 m
Answer with explanation
Answer: Option CExplanation


Let the length of bridge be x meters.  

Workspace
A train X starts from Meerut at 4 p.m. and reaches Ghaziabad at 5 p.m. while another trainY starts from Ghaziabad at 4 p.m. and reaches Meerut at 5.30 p.m. The two trains will cross each other at:
4.36 p.m.
4.42 p.m.
4.48 p.m.
4.50 p.m.
Answer with explanation
Answer: Option AExplanation
Suppose, the distance between Meerut and Ghaziabad is x km.  
Time taken by X to cover x km = 1 hour.  




Let them meet y hours after 4 p.m. Then,  


So, the two trains meet at 4.36 p.m.  
Workspace
Two goods train each 500 m long, are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 30 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one
12 sec
24 sec
48 sec
60 sec
Answer with explanation
Answer: Option CExplanation


Distance covered = (500 + 500) m = 1000 m.  

Workspace
A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
320 m
350 m
650 m
500 m
Answer with explanation
Answer: Option BExplanation


Let the length of the platform be x metres  

Workspace
Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:
30 km/hr
45 km/hr
60 km/hr
75 km/hr
Answer with explanation
Answer: Option CExplanation
Let the speed of the slower train be x m/sec.  
Then, speed of the faster train = 2x m/sec.  
Relative speed = (x + 2x) m/sec = 3x m/sec.  



Workspace
A train 800 meters long is running at a speed of 78 km / hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in meters) is:
130
360
500
540
Answer with explanation
Answer: Option CExplanation


Time = 1 minute = 60 sec.  
Let the length of the tunnel be x meters.  

Workspace
A train covers a distance of 12 km in 10 minutes. If it takes 6 seconds to pass a telegraph post, then the length of the train is:
90 m
100 m
120 m
140 m
Answer with explanation
Answer: Option CExplanation


Length of the train = (Speed x Time) = (20 x 6) m = 120 m.  
Workspace
A train of length 150 metres takes 40.5 seconds to cross a tunnel of length 300 metres. What is the speed of the train in km/hr?
13.33
26.67
40
66.67
Answer with explanation
Answer: Option CExplanation

Workspace
A train passes two bridges of length 1000 m and 600 m in 120 seconds and 80 seconds respectively. The length of the train.
500 m
400 m
300 m
200 m
Answer with explanation
Answer: Option DExplanation
Distance covered in 120 second = 1000 + length of train(l)
Distance covered in 80 seconds = 600 + l
So, distance covered in 40 seconds = (1000 + l) – (600 + l)
= 400 m
Speed = 400/40 = 10 m/s
Distance covered in 80 second = 80 x 10 = 800 m
So, 600 + l = 800
Length of the train (l) = 200 m
Workspace
A train reaches from A to B in 5 hours travelling at a speed of 60 km/hr. If its speed is increased by 15 km/hr, then the time of journey is reduced by
4 hour
3 hour
2 hour
1 hour
Answer with explanation
Answer: Option DExplanation
Total distance = speed x time
=60 x 5 = 300 km
If speed increased then new speed= 60 + 15 = 75 km/hr
New time = Total distance/speed
= 300/75= 4 hour
Time reduced by 5 – 4 = 1 hour
Workspace
Two trains 180 m and 120 m long respectively pass each other in 54 seconds when they run in the same direction and in 18 seconds when run in opposite directions. Find the speed of two trains
S_{1} = 10 km/hr
S_{2} = 20 km/hr
S_{1} = 30 km/hr
S_{2} = 20 km/hr
S_{1} = 20 km/hr
S_{2} = 40 km/hr
S_{1} = 40 km/hr
S_{2} = 20 km/hr
Answer with explanation
Answer: Option DExplanation
Let the speed of 1st train is S_{1} and speed of 2nd train is S_{2}
Time = total distance/ relative speed
1) In same direction
54 = (180 + 120) / (S_{1} – S_{2}) * 5/18
(S_{1} – S_{2})54 = (300 * 18)/5
(S_{1} – S_{2}) = 20
2) In opposite direction
9 = (180 + 120) / (S_{1} + S_{2}) * 5/18
(S_{1} + S_{2})18 = (300 * 18)/5
(S_{1} + S_{2}) = 60
from 1 and 2
S_{1} = 40 km/hr
S_{2} = 20 km/hr
Workspace