A Learning Portal from Recruitment India
A 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
320 m
350 m
650 m
500 m
Answer with explanation
Answer: Option BExplanation


Let the length of the platform be x metres  

Workspace
Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:
30 km/hr
45 km/hr
60 km/hr
75 km/hr
Answer with explanation
Answer: Option CExplanation
Let the speed of the slower train be x m/sec.  
Then, speed of the faster train = 2x m/sec.  
Relative speed = (x + 2x) m/sec = 3x m/sec.  



Workspace
A train 800 meters long is running at a speed of 78 km / hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in meters) is:
130
360
500
540
Answer with explanation
Answer: Option CExplanation


Time = 1 minute = 60 sec.  
Let the length of the tunnel be x meters.  

Workspace
A train covers a distance of 12 km in 10 minutes. If it takes 6 seconds to pass a telegraph post, then the length of the train is:
90 m
100 m
120 m
140 m
Answer with explanation
Answer: Option CExplanation


Length of the train = (Speed x Time) = (20 x 6) m = 120 m.  
Workspace
A train of length 150 metres takes 40.5 seconds to cross a tunnel of length 300 metres. What is the speed of the train in km/hr?
13.33
26.67
40
66.67
Answer with explanation
Answer: Option CExplanation

Workspace
A train passes two bridges of length 1000 m and 600 m in 120 seconds and 80 seconds respectively. The length of the train.
500 m
400 m
300 m
200 m
Answer with explanation
Answer: Option DExplanation
Distance covered in 120 second = 1000 + length of train(l)
Distance covered in 80 seconds = 600 + l
So, distance covered in 40 seconds = (1000 + l) – (600 + l)
= 400 m
Speed = 400/40 = 10 m/s
Distance covered in 80 second = 80 x 10 = 800 m
So, 600 + l = 800
Length of the train (l) = 200 m
Workspace
A train reaches from A to B in 5 hours travelling at a speed of 60 km/hr. If its speed is increased by 15 km/hr, then the time of journey is reduced by
4 hour
3 hour
2 hour
1 hour1 hour
Answer with explanation
Answer: Option DExplanation
Total distance = speed x time
=60 x 5 = 300 km
If speed increased then new speed= 60 + 15 = 75 km/hr
New time = Total distance/speed
= 300/75= 4 hour
Time reduced by 5 – 4 = 1 hour
Workspace
Two trains 180 m and 120 m long respectively pass each other in 54 seconds when they run in the same direction and in 18 seconds when run in opposite directions. Find the speed of two trains
S_{1} = 10 km/hr
S_{2} = 20 km/hr
S_{1} = 30 km/hr
S_{2} = 20 km/hr
S_{1} = 20 km/hr
S_{2} = 40 km/hr
S_{1} = 40 km/hr
S_{2} = 20 km/hr
Answer with explanation
Answer: Option DExplanation
Let the speed of 1st train is S_{1} and speed of 2nd train is S_{2}
Time = total distance/ relative speed
1) In same direction
54 = (180 + 120) / (S_{1} – S_{2}) * 5/18
(S_{1} – S_{2})54 = (300 * 18)/5
(S_{1} – S_{2}) = 20
2) In opposite direction
9 = (180 + 120) / (S_{1} + S_{2}) * 5/18
(S_{1} + S_{2})18 = (300 * 18)/5
(S_{1} + S_{2}) = 60
from 1 and 2
S_{1} = 40 km/hr
S_{2} = 20 km/hr
Workspace
If the speed of the boat in still water is 5 km/hr and the speed of the current is 10 km/hr, then find the time taken by the boat to travel 125 km with the current.
2 hour
3 hour
4 hour
5 hour
Answer with explanation
Answer: Option DExplanation
Relative speed = 15 + 10
=25 km/hr
Time = Distance/speed
= 125/25
= 5 hour
Workspace
Speed of motorboat in still water is 35 kmph. If the motorboat travels 100 km along the stream in 2 hour 30 min, then the time taken by it to cover the same distance against the stream is
4 hour 20 min
1 hour 20 min
2 hour 20 min
3 hour 20 min
Answer with explanation
Answer: Option DExplanation
The speed of the motorboat in still water is 35 km/hr.
let the speed of the strem = x km/hr
Downstream speed = Distance/time
= 100 / 2.5
= 40 km/hr
Speed of stream = 35 + x = 40
x = 5 km/hr
Upstream speed = 35 – 5 = 30 km/hr
Time taken in upstream = 100/30 = 3 hour 20 min
Workspace
Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer with explanation
Answer: Option AExplanation
Workspace
Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
Answer with explanation
Answer: Option CExplanation
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
27x + 17y  = 23  
x+ y 
27x + 17y = 23x + 23y
4x = 6y
x:y = 3 : 2
Workspace
A train speeds past a pole in 15 seconds and a platform 100 m long in 25seconds. Its length is:
Answer with explanation
Answer: Option BExplanation
Let the length of the train be x metres and its speed be y m/sec.
Then, (x/y)= 15 y =(x/15)
(x+100)/25 = x/15
=> 15(x + 100) = 25x
=> 15x + 1500 = 25x
=> 1500 = 10x
=> x = 150 m.
Workspace
A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Answer with explanation
Answer: Option BExplanation
Speed of train relative to man = (60 + 6) km/hr = 66 km/hr.
(66*5/18) m/sec = 55/3 m/sec
Time taken to pass the man = (110*3/55)m/sec = 6 sec.
Workspace
RecruitmentIndia.in is Blog where we will update the information by exploring various online and offline sources of information. Our aim is to provide the latest Education related news as fast as possible to the students for free of cost.
Exams.Recruitmentindia.in is a Preparation portal where you can prepare all the competitive related questions like Aptitude, Reasoning, English Questions and Current affairs for free of cost
You can Contact us at :