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Two trains are moving in opposite direction having speed in the ratio 5:7. First train crosses a pole in 12 second and second train crosses the same pole n 15 second. Find the time in which they can cross each other completely.

A.

59/4 sec

B.

57/4 sec

C.

55/4 sec

D.

53/4 sec

Answer with explanation

Answer: Option CExplanation

Let the length of first train and second train be a and b meter. Then

a = 5x*12 = 60x and b = 7x*15 = 105x

They are moving in opposite direction, 165x = (12x)*T

T = 165/12 = 55/4 sec

Workspace

A train travels a certain distance by taking 3 stops of 20min each. Considering the period of stoppage, the overall speed of the train comes to 40 km/h. While without consideration of stoppage, it is 45 km/h. How much distance must the train have travelled?

A.

360km

B.

550km

C.

400km

D.

360km

Answer with explanation

Answer: Option AExplanation

45×y=40(y+1)

distance travelled= 45×8=360

Workspace

A train is moving and crossing a man who is running on a platform of 100 m at a speed of 8 kmph in the direction of the train, in 9 sec. If the speed of the train is 74 kmph. Find the length of the train ?

A.

156 mts

B.

165 mts

C.

188 mts

D.

202 mts

Answer with explanation

Answer: Option AExplanation

Let the length of the train = L mts

Relative speed of train and man = 74 – 8 = 66 kmph = 66 x 5/18 m/s

=> 66 x 5/18 = L/9

=> L = 165 mts.

Workspace

The length of a train and that of a platform are equal. If with a speed of 90 k/hr, the train crosses the platform in one minute, then the length of the train (in meters) is:

A.

850

B.

525

C.

550

D.

750

Answer with explanation

Answer: Option DExplanation

Speed = [90 * 5/18] m/sec = 25 m/sec; Time = 1 min. = 60 sec.

Let the length of the train and that of the platform be x meters.

Then, 2x/60 = 25 è x = 25 * 60 / 2 = 750

Workspace

I walk a certain distance and ride the car back taking a total time of 33 Minutes. I could walk both sides in 45 min. How long would it take me to ride both ways?

A.

19 mins

B.

20 mins

C.

21 mins

D.

22 mins

Answer with explanation

Answer: Option CExplanation

Time taken in walking a certain distance from X and Y = 22 `1/2` Min

Time taken in riding the same distance = 33 – 22 `1/2` = 10 `1/2` Min

It will take 21 Min (10 `1/2` * 2) to ride both ways.

Workspace

A train of length 200 meters takes 12 seconds to cross a man who is running at a speed of 10 km/hr in opposite direction of the train. What is the speed of the train?

A.

50 km/hr

B.

55 km/hr

C.

60 km/hr

D.

65 km/hr

Answer with explanation

Answer: Option AExplanation

Workspace

A train sets off at 2 pm at the speed of 70 km/hr, another train starts at 3:30 pm train the same direction at the rate of 85 km/hr. At what time will they meet?

A.

11.30 am

B.

10.30pm

C.

9.40am

D.

5.40 pm

Answer with explanation

Answer: Option BExplanation

Suppose trains meet x hours after 2 pm

First train travels x hours.

Distance covered by first train = 70x

Second train travels (x-1.5) hours.

Distance covered by second train = 85(x-1.5)

Both the distances are same as they meet after x hours

=> 70x = 85(x-1.5)

=> 15x = 127.5

=> x = 8.5 = 8 hour 30 minutes

Therefore, the trains meet 8 hours 30 minutes after 2 pm

i.e., at 10:30 pm

Workspace

A train travelling at 60 kmph crosses a man in 6 seconds. What is the length of the train?

A.

100 meters

B.

150 meters

C.

200 meters

D.

250 meters

Answer with explanation

Answer: Option AExplanation

Speed in m/sec = 60 *(5/18) = 50/3 m/sec

Time taken to cross the man = 6 secs

Therefore, Distance = (50/3)* 6 = 100 metres (i.e. the length of the train)

Workspace

Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:

A.

1:3

B.

3:2

C.

3:4

D.

None of these

Answer with explanation

Answer: Option BExplanation

Let the speeds of the two trains be x m/sec and y m/sec respectively. Then, length of the first train = 27 x meters,

and length of the second train = 17 y meters. (27 x + 17 y) / (x + y) = 23 ==> 27 x + 17 y = 23 x + 23 y ==> 4 x = 6 y ==> x/y = 3/2.

Workspace

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