In how many different ways can six players be arranged in a line such that two of them, Ajeet and Mukherjee are never together?
Answer with explanationAnswer: Option D
As there are six players, So total ways in which they can be arranged = 6!ways =720.
A number of ways in which Ajeet and Mukherjee are together = 5!x2 = 240.
Therefore, Number of ways when they don’t remain together = 720 -240 =480.