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A vendor sells 60 percent of apples he had and throws away 15 percent of the remainder. Next day he sells 50 percent of the remainder and throws away the rest. What percent of his apples does the vendor throw?

A.

17

B.

23

C.

77

D.

55

Answer with explanation

Answer: Option BExplanation

Let the number of apples be 100.

On the first day he sells 60% apples i.e.,60 apples. Remaining apples =40.

He throws 15% of the remaining i.e., 15% of 40 = 6.Now he has 40−6=3440−6=34 apples

The next day he throws 50% of the remaining 34 apples i.e., 17.

Therefore in total he throws 6+17=6+17= **23 apples**.

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The difference between two numbers is 1550. If 8 % of one number is 10 % of the other number, then find the two numbers

A.

4973, 6523

B.

5450, 7000

C.

6200, 7750

D.

6500, 4950

Answer with explanation

Answer: Option CExplanation

Let two numbers be x and y.

It is given that, 8 % of x = 10 % of y

Therefore,

x = | 10 | y = | 5 | y |

8 | 4 |

Difference between two numbers (x – y)= 1550

Substituting the value of x, we get

5 | – y = 1550 |

4 |

y | = 1550 |

4 |

y=1550×4=6200

x = | 5 | × 6200 = 7750 |

4 |

The two numbers whose difference is 1550 are 6200 and 7750.

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The value of lathe machine depreciates at the rate of 10 % per annum. If the cost of machine at present is Rs. 160,000, then what will be its worth after 2 years?

A.

Rs. 122,365

B.

Rs. 153,680

C.

Rs. 129,600

D.

Rs. 119,900

Answer with explanation

Answer: Option CExplanation

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The price of diesel increases by 50 %. Find by how much percent a truck owner must reduce his consumption in order to maintain the same budget?

A.

11.11 %

B.

22.22 %

C.

33.33 %

D.

44.44 %

Answer with explanation

Answer: Option CExplanation

** **If the price of goods increases by R %, then the reduction in consumption so as not toincrease the expenditure can be calculated using the formula:

R | × 100 | % | ||

(100 + R) |

= | 50 | × 100 | % | ||

(100 + 50) |

= 33.33 %

The truck owner must reduce its consumption in order to maintain the same budget by 33.33 %

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A student attempts x number of questions. He answers 15 correctly out of first 20 questions and of the remaining questions, he answers 1/3 correctly. If all questions have same credit and the student gets 50 % marks, then find the value of x.

A.

30

B.

35

C.

45

D.

50

Answer with explanation

Answer: Option DExplanation

Student attempts x questions.

2) Out of 20 questions he answers 15 correctly and of (x – 20) questions he answered 1/3 correctly.

3) The student gets 50 % marks.

Therefore,

15 + | 1 | (x – 20) = 50% of x |

3 |

15 + | 1 | (x – 20) = | 50 | × x |

3 | 100 |

15 + | 1 | (x – 20) = | x |

3 | 2 |

90+2 (x-20)=3x

Solving this equation, we get

x=50

Hence, the number of question attempted by the students = 50

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A student multiplied a number by 3/5 instead of 5/3, What is the percentage error in the calculation ?

A.

54 %

B.

64 %

C.

74 %

D.

84 %

Answer with explanation

Answer: Option BExplanation

Let the number be x.

Then, ideally he should have multiplied by x by 5/3. Hence Correct result was x * (5/3)= 5x/3.

By mistake he multiplied x by 3/5 . Hence the result with error = 3x/5

Then, error = (5x/3 – 3x/5) = 16x/15

Error % = (error/True vaue) * 100 = [(16/15) * x/(5/3) * x] * 100 = 64 %

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405 sweets were distributed equally among children in such a way that the number of sweets received by each child is 20% of the total number of children. How many sweets did each child recieve ?

A.

9

B.

10

C.

11

D.

12

Answer with explanation

Answer: Option AExplanation

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1100 boys and 700 girls are examined in a test; 42% of the boys and 30% of the girls pass. The percentage of the total who failed is :

A.

58

B.

62 *2/3

C.

64

D.

67

Answer with explanation

Answer: Option BExplanation

Total number of students = 1100 + 700 = 1800.

Number of students passed = (42% of 1100 + 30% of 700) – (462 + 210) = 672.

Number of failues = 1800-672 = 1128.

Percentage failure = (1128/1800 * 100 )% = 62 * 2/3 %.

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