A Learning Portal from Recruitment India

A.

Rs.50.00

B.

Rs.66.67

C.

Rs.75.00

D.

Rs.150.00

Answer with explanation

Answer: Option AExplanation

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A vendor sells 60 percent of apples he had and throws away 15 percent of the remainder. Next day he sells 50 percent of the remainder and throws away the rest. What percent of his apples does the vendor throw?

A.

17

B.

23

C.

77

D.

55

Answer with explanation

Answer: Option BExplanation

Let the number of apples be 100.

On the first day he sells 60% apples i.e.,60 apples. Remaining apples =40.

He throws 15% of the remaining i.e., 15% of 40 = 6.Now he has 40−6=3440−6=34 apples

The next day he throws 50% of the remaining 34 apples i.e., 17.

Therefore in total he throws 6+17=6+17= **23 apples**.

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The difference between two numbers is 1550. If 8 % of one number is 10 % of the other number, then find the two numbers

A.

4973, 6523

B.

5450, 7000

C.

6200, 7750

D.

6500, 4950

Answer with explanation

Answer: Option CExplanation

Let two numbers be x and y.

It is given that, 8 % of x = 10 % of y

Therefore,

x = | 10 | y = | 5 | y |

8 | 4 |

Difference between two numbers (x – y)= 1550

Substituting the value of x, we get

5 | – y = 1550 |

4 |

y | = 1550 |

4 |

y=1550×4=6200

x = | 5 | × 6200 = 7750 |

4 |

The two numbers whose difference is 1550 are 6200 and 7750.

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The value of lathe machine depreciates at the rate of 10 % per annum. If the cost of machine at present is Rs. 160,000, then what will be its worth after 2 years?

A.

Rs. 122,365

B.

Rs. 153,680

C.

Rs. 129,600

D.

Rs. 119,900

Answer with explanation

Answer: Option CExplanation

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The price of diesel increases by 50 %. Find by how much percent a truck owner must reduce his consumption in order to maintain the same budget?

A.

11.11 %

B.

22.22 %

C.

33.33 %

D.

44.44 %

Answer with explanation

Answer: Option CExplanation

** **If the price of goods increases by R %, then the reduction in consumption so as not toincrease the expenditure can be calculated using the formula:

R | × 100 | % | ||

(100 + R) |

= | 50 | × 100 | % | ||

(100 + 50) |

= 33.33 %

The truck owner must reduce its consumption in order to maintain the same budget by 33.33 %

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A student attempts x number of questions. He answers 15 correctly out of first 20 questions and of the remaining questions, he answers 1/3 correctly. If all questions have same credit and the student gets 50 % marks, then find the value of x.

A.

30

B.

35

C.

45

D.

50

Answer with explanation

Answer: Option DExplanation

Student attempts x questions.

2) Out of 20 questions he answers 15 correctly and of (x – 20) questions he answered 1/3 correctly.

3) The student gets 50 % marks.

Therefore,

15 + | 1 | (x – 20) = 50% of x |

3 |

15 + | 1 | (x – 20) = | 50 | × x |

3 | 100 |

15 + | 1 | (x – 20) = | x |

3 | 2 |

90+2 (x-20)=3x

Solving this equation, we get

x=50

Hence, the number of question attempted by the students = 50

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A student multiplied a number by 3/5 instead of 5/3, What is the percentage error in the calculation ?

A.

54 %

B.

64 %

C.

74 %

D.

84 %

Answer with explanation

Answer: Option BExplanation

Let the number be x.

Then, ideally he should have multiplied by x by 5/3. Hence Correct result was x * (5/3)= 5x/3.

By mistake he multiplied x by 3/5 . Hence the result with error = 3x/5

Then, error = (5x/3 – 3x/5) = 16x/15

Error % = (error/True vaue) * 100 = [(16/15) * x/(5/3) * x] * 100 = 64 %

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405 sweets were distributed equally among children in such a way that the number of sweets received by each child is 20% of the total number of children. How many sweets did each child recieve ?

A.

9

B.

10

C.

11

D.

12

Answer with explanation

Answer: Option AExplanation

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1100 boys and 700 girls are examined in a test; 42% of the boys and 30% of the girls pass. The percentage of the total who failed is :

A.

58

B.

62 *2/3

C.

64

D.

67

Answer with explanation

Answer: Option BExplanation

Total number of students = 1100 + 700 = 1800.

Number of students passed = (42% of 1100 + 30% of 700) – (462 + 210) = 672.

Number of failues = 1800-672 = 1128.

Percentage failure = (1128/1800 * 100 )% = 62 * 2/3 %.

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If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51. What is the original fraction ?

A.

31/25

B.

15/17

C.

14/25

D.

11/16

Answer with explanation

Answer: Option BExplanation

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If the pice of sugar rises from Rs. 6 per kg to Rs. 7.50 per kg, a person, to have no increase in his expenditure on sugar, will have to reduce his consumpion of sugar by

A.

15

B.

20

C.

25

D.

30

Answer with explanation

Answer: Option BExplanation

Let original consumption = 100 kg and new consumption = x kg,

So, 100 * 6 = x * 7.50 => x = 80kg

Reduction in consumption = 20%.

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Of the 1000 inhabitants of a town, 60 % are males of whom 120 % are literate. If, of all the inhabitants, 25% are literate, then what percent of the females of the town are literate ?

A.

32.5 %

B.

43 %

C.

46.6 %

D.

53.2 %

Answer with explanation

Answer: Option AExplanation

Number of males = 60% of 1000 = 600. Number of females = (1000 – 600) = 400.

Number of literates = 25% of 1000 = 250.

Number of literate males = 20% of 600 = 120.

Number of literate females = (250 – 120) = 130.

Required pecentage = (130/400 * 100 ) % = 32.5 %.

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A.

4000

B.

8000

C.

12000

D.

16000

Answer with explanation

Answer: Option BExplanation

Let the number of candidates appeared from each state be x.

In state A, 6% candidates got selected from the total appeared candidates

In state B, 7% candidates got selected from the total appeared candidates

But in State B, 80 more candidates got selected than State A

From these, it is clear that 1% of the total appeared candidates in State B = 80

=> total appeared candidates in State B = 80 x 100 = 8000

=> total appeared candidates in State A = total appeared candidates in State B = 8000

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A fruit seller had some oranges. He sells 30% oranges and still has 140 mangoes. Originally, he had:

A.

288 oranges

B.

300 oranges

C.

672 oranges

D.

200 oranges

Answer with explanation

Answer: Option DExplanation

Suppose originally he had x oranges.

Then, (100 – 30)% of x = 140.

70/100 x = 140

x = (140 x 100)/70 = 200.

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A student erroneously multiplied a number by 2/5 instead of 5/2.What is the percentage error in the calculation?

A.

24%

B.

54%

C.

74%

D.

84%

Answer with explanation

Answer: Option DExplanation

** **Let the number be 100. 2/5 of 100 is 40 while 5/2 of 100 is 250.

Now the difference is 210 on a base of 250. Therefore, percentage difference is 210/250 into 100 = 84%.

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The total population of a village increased from 1,80,00 to 22, 500 in a decade. The average percentage increase of population per year of that village is:

A.

2.37%

B.

2.5%

C.

3. 6%

D.

6.75%

Answer with explanation

Answer: Option BExplanation

Population increase in 10 years = (22500- 18000) = 4500.

Increase% = (4500/18000 x 100)% = 25%

Required average = (25/10)% = 2. 5%

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If in a society of 250, there are 40 % literates and among illiterates, there are 60 % males, then among totality of society, what percentage are illiterate women?

A.

42%

B.

24%

C.

48%

D.

60%

Answer with explanation

Answer: Option BExplanation

As per given statement,

If there are 40% literates, then there will be 60% illiterates => (60/100) * 250 = 150

If among illiterates, there are 60% males, then, there will be 40% females => (40/100) * 150 = 60

Then among totality of society, Percentage of illiterate women will be,

===>>> (60/250) * 100 = 24%.

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There is a certain amount from which A takes 25% then B takes 50% of remaining amount, then C takes 75% of the remaining amount. Now if the amount left is 5,760 then what is the actual sum?

A.

Rs. 58,220

B.

Rs. 59,680

C.

Rs. 60,600

D.

Rs. 61,440

Answer with explanation

Answer: Option DExplanation

Let X be the actual amount.

Then from the question,

75% of 50% of 25% of X = 5760

=> X = (5760 x 100 x 100 x 100)/(75 x 50 x 25) = 61440

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The percentage change of a number when it is first decreased by 10% and then increased by 10% is

A.

0.1% increase

B.

1% decrease

C.

0.1 % decrease

D.

No changes

Answer with explanation

Answer: Option BExplanation

Required percentage change = 10 – 10 – 10 x 10/100 = – 1 i.e. 1 % decrease

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A publisher printed 2000 copies of a book at a cost of Rs. 70,000. He distributes 400 copies free as specimen copies. He gave 30% discount on printed price and the printed price of each book is Rs. 75. What is his gain or loss percentage ?

A.

20% gain

B.

20% loss

C.

10% loss

D.

10% gain

Answer with explanation

Answer: Option AExplanation

According to the question,

C.P of a book = 70000/(2000 – 400) = Rs. 43.75

So, S.P of a book = 75 * (1 – 30/100) = Rs. 52.5

So, gain % = (52.5 – 43.75)/43.75 * 100 = 20% gain

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A watch is listed for Rs.230 and is sold at a discount of 12%, then the sale price of the watch is

A.

Rs.206

B.

Rs.276

C.

Rs.202.4

D.

Rs.257.6

Answer with explanation

Answer: Option CExplanation

According to the question,

Sale price = 230 * (100 – 12)/100 = Rs. 202.4

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