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A Learning Portal from Recruitment India

The daily wage is increased by 50% and a person now gets Rs 25 per day. What was his daily wage before the increase ?

A.

Rs 20

B.

Rs 16.6

C.

Rs 18

D.

none of these

Answer with explanation

Answer: Option BExplanation

Let A be the daily wages before the increase,

A ( 1 + x/100) = 25 (Given)

Here, x = 50

Therefore, A( 1 + 50/100) = 25

A = (25 x 100) / (150) = Rs 16.6.

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A.

48.39%

B.

54.68%

C.

62.48%

D.

42.36%

Answer with explanation

Answer: Option AExplanation

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If population of certain city increases at the rate of 5%. If population in 1981 was 138915, then population in 1978 was?

A.

1,20,000

B.

1,10,000

C.

1,00,000

D.

90,000

Answer with explanation

Answer: Option AExplanation

X * (105/100) * (105/100) * (105/100) = 138915

X = 138915/1.157625

X = 120000

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A number is increased by 20% and then decreased by 20%, the final value of the number is?

A.

increase by 2%

B.

decrease by 3%

C.

decrease by 4%

D.

increase by 5%

Answer with explanation

Answer: Option CExplanation

Here, x = 20 and y = – 20

Therefore, the net % change in value

=**x + y + xy100x + y + xy100 %**

= 20 + (−20) + 20 × −2010020 + -20 + 20 × -20100% or – 4%

Since the sign is negative, there is a decrease in value by 4%.

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The salary of a typist was at first raised by 10% and then the same was reduced by 5%. If he presently draws Rs.1045.What was his original salary?

A.

1000

B.

975

C.

950

D.

900

Answer with explanation

Answer: Option AExplanation

X * (110/100) * (95/100) = 1045

X * (11/10) * (1/100) = 11

X = 1000

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The percentage of metal extracted from a mine of lead ore is 50%.Now the percentage of gold is 4/5 % of the metal and the rest is lead. If the mass of ore extracted from the mine is 6000kg, the mass of the lead is

A.

2975kg

B.

2976kg

C.

2973kg

D.

2875kg

Answer with explanation

Answer: Option BExplanation

Given mass of lead ore=6000 kg

Mass of metal is 50% of 6000 = 3000 kg

Mass of gold is 4/5% of 3000 = 24 kg

Mass of lead = 3000 – 24 = **2976 kg**

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Victor gets 92 % marks in examinations. If these are 460 marks, find the maximum marks.

A.

500

B.

400

C.

600

D.

700

Answer with explanation

Answer: Option AExplanation

Let the maximum marks be m

Then 92 % of m = 460

⇒ 92/100 × m = 460

⇒ m = (460 × 100)/92

⇒ m = 46000/92

⇒ m = 500

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A student attempts x number of questions. He answers 15 correctly out of first 20 questions and of the remaining questions, he answers 1/3 correctly. If all questions have same credit and the student gets 50 % marks, then find the value of x.

A.

30

B.

40

C.

45

D.

50

Answer with explanation

Answer: Option DExplanation

Step-by-step explanation:

15+1/3(n-20)=50% of n

15+n/3-20/3=50/100*n

15-20/3=n/2-n/3

25/3=3n-3n÷6

25/3=n/6

n=50

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If 80% of a number added to 80 gives the result as the number itself, then the number is

A.

200

B.

** **320

C.

** **400

D.

** ** 480

Answer with explanation

Answer: Option CExplanation

2nd method:

Let the number be x.

80% of x + 80 = x

=> (80/100 * x) + 80 = x

=> 80x/100 + 80 = x

=> (80x + 8000 )/ 100 = x (LCM)

=> 80x + 8000 = 100 x. (Cross multiplication)

=> 8000 = 100x – 80x

=> 8000 = 20x

x = 8000/20

= 400

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