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A Learning Portal from Recruitment India

Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are

A.

42,30

B.

41,32

C.

D.

41,30

Answer with explanation

Answer: Option CExplanation

Let mark of one student = X

Then, mark of another student = x + 9

Given, x+9 = (56/100) (x+9+ x)

=> 25(x + 9) = 14(2x + 9)

=> 25x + 225 = 28x + 126

=> 28x – 25x = 225 – 126

=>3x = 99

x = 33 which is the mark of one student.

Mark of another student = x + 9

= 33 + 9 =42

So, their marks are 42 and 33

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If 25% of a number is subtracted from a second number, the second number reduces to its four-sixth. What is the ratio of the first number to the second number?

A.

4:3

B.

2:3

C.

3:2

D.

5:3

Answer with explanation

Answer: Option AExplanation

Let the numbers be p & q

q-p/4 = 4q/6

=> q-4q/6 = p/4

=> 2q/6 = p/4

=> p/q = 4/3

Workspace

In a library 60% of the books are in Hindi, 60% of the remaining books are in English rest of the books are in Malayalam. If there are 4800 books in English, then the total number of books in Malayalam are?

A.

3400

B.

3500

C.

3100

D.

3200

Answer with explanation

Answer: Option DExplanation

Let there are X books in the library.

Hindi books = 60% of X = 60X /100 = 0.6X

Remaining Books = X – 0.6X = 0.4X

English books = 40% of reaming books = 60% of 0.4X = 0.24X.

Malayalam Books = X-0.6X -0.24X = 0.16X

Given,

0.24X = 4800

X = 4800/0.24 = 20000

Malayalam Books = 0.16X = 0.16*20000 = 3200.

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In a survey it was found that 80% of those surveyed owned a car while 60% of those surveyed owned a mobile phone, if 55% owned both a car and a Mobile phone, What percent of those surveyed owned a car or a mobile phone or both?

A.

65%

B.

85%

C.

80%

D.

97.5%

Answer with explanation

Answer: Option BExplanation

Given that percentage of car owners = 80%

Percentage of mobile phone owners = 60%

Percentage of people having both car and mobile phone = 55%

Percentage of people having only car = 80 -55 = 25%

Percentage of people having only mobile phone = 60 -55 =5%

Percentage of people having car or mobile phone or both = 55% + 25% + 5% = 85%

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In a class of 60 students, each student got sweets that are 15 % of the total number of students. How many sweets were there?

A.

560

B.

520

C.

540

D.

580

Answer with explanation

Answer: Option CExplanation

Given: Total number of students = 60

No. of sweets that each student got =15 % of 60

= (15 / 100) * 60

= 9 sweets

Total No. of sweets = 9 x 60 = 540

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Three candidates, Ajay, Bijoy & Chandu contested an election and received 1800, 3300 and votes 3900 respectively. What percent of the total votes did A get?

A.

70%

B.

45%

C.

40%

D.

20%

Answer with explanation

Answer: Option DExplanation

Total no. of votes polled = (1800 + 3300 + 3900) = 9000.

Required percentage = (1800/9000 * 100)% = 20%.

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A number is decreased by 10% and then increased by 10%. The number so obtained is 10 less than the original number. What was the oiginal number ?

A.

1000

B.

2000

C.

3000

D.

4000

Answer with explanation

Answer: Option AExplanation

Let the original number be x.

Final number obtained = 110% of (90% of x) =(110/100 * 90/100 * x) = (99/100)x.

x-(99/100)x=10

=> x =1000

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The price of a fan is decreased by 20%.as a result of wh ich the sale increased by 40%.What will be the effect on the total revenue of the shop?

A.

10%

B.

12%

C.

20%

D.

30%

Answer with explanation

Answer: Option BExplanation

Original revenue=100×100=10000.

After 20% decrease=80×140=11200.

Hence [(11200-10000)/10000] ×100=[1200/10000] ×100

=12%

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The base of triangle is increased by 10%. To keep the area unchanged the height of the triangle is to be decreased by

A.

9(1/11)%

B.

2/3%

C.

4/5%

D.

8/6%

Answer with explanation

Answer: Option AExplanation

Let the number be 100.

When 10% is increased = 100 x (110/100) = 110

Now, to keep area unchaged we should have = [(110 -100)/110] x 100

= (10/110) x 100

= 100/11

= 9(1/11)% (mixed fraction of 100/11)

Therefore, the height of the triangle is to be decreased by 9(1/11)%.

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In an examination, 25% candidates failed in English and 35 % students failed in Math.If 15 % candidates failed in both, what is the percentage of candidates who passed in both the subjects?

A.

65%

B.

75%

C.

55%

D.

98%

Answer with explanation

Answer: Option CExplanation

Apply formula: = 100 – (x + y – z)

x = 25%

y = 35 %

z = 15 %

∴ Required percentage of candidates = 100 – (25 + 35 – 15)

= 100 – 45 = 55%

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75 g of sugar solution has 30% sugar in it. Then, the quantity of sugar that should be added to the solution to make the quantity of the sugar 70% in the solution, is

A.

120g

B.

150g

C.

100g

D.

250g

Answer with explanation

Answer: Option CExplanation

Sugar in original solution = (75 x 30) / 100 = 22.5 g

Let x g of sugar be mixed

According to the question

{(22.5 + p)/(75 + p)} x 100 = 70

2250 + 100p = 75 × 70 + 70p

2250 + 100p = 5250 + 70p

30p = 5250 – 2250= 3000

=> p = 3000/30 = 100g

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