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The calendar for the year 2007 will be the same for the year:

A.

2018

B.

2016

C.

2014

D.

2012

Answer with explanation

Answer: Option AExplanation

Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.

Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017 Odd day : 1 2 1 1 1 2 1 1 1 2 1

Sum = 14 odd days 0 odd days.

Calendar for the year 2018 will be the same as for the year 2007.

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How many leap years do 300 years have?

A.

72

B.

73

C.

74

D.

75

Answer with explanation

Answer: Option AExplanation

Given year is divided by 4, and the quotient gives the number of leap years.

Here, 300%4 = 75.

But, as 100,200 and 300 are not leap years => 75 – 3= 72 leap years.

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Today is 5^{th} August. The day of the week is Wednesday. This is a leap year. What will be the day of the week on this date after 3 years?

A.

Tuesday

B.

Saturday

C.

Thursday

D.

Sunday

Answer with explanation

Answer: Option BExplanation

This is a leap year.

So none of the next 3 years will be leap years.

Each ordinary year has one odd day, so there are 3 odd days in next 3 years.

So the day of the week will be 3 odd days beyond Wednesday i.e. it will be Saturday

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What will be the day on week 4th April 2001?

A.

Friday

B.

Sunday

C.

Monday

D.

Wednesday

Answer with explanation

Answer: Option DExplanation

April 4th 2001 =(2000 years+Period of 1.1.2001 to 4.4.2001)

Odd days in 2000 years = 0 days

From January to April 4

Total no.of.days: 31+28+31+4=94 days =(13 weeks +3 days)=3 odd days

So the day will be Wednesday

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What will be the day of the week 15^{th} August 2010?

A.

Monday

B.

Friday

C.

Sunday

D.

Tuesday

Answer with explanation

Answer: Option CExplanation

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 = 4 odd days.

Jan. Feb. Mar. Apr. May. Jun. Jul. Aug.

(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days = (32 weeks + 3 days) = 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 = 0 odd days.

Given day is Sunday

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Today is Monday. After 61 days, it will be:

A.

Monday

B.

wednesday

C.

Friday

D.

Saturday

Answer with explanation

Answer: Option DExplanation

Each day of the week is repeated after 7 days.

So, after 63 days, it will be Monday.

∴ After 61 days, it will be Saturday.

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If 1^{st} Jan 2005 is Saturday then what will be 1^{st} Jan 2008?

A.

Monday

B.

Tuesday

C.

Saturday

D.

Sunday

Answer with explanation

Answer: Option BExplanation

On 31st December it was Friday.Number of Odd days between 2006 and 2008 = (1+1)=2days

Then December 31st 2007 will be Monday then 1st Jan 2008 will be Tuesday.

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On what dates of April 2009 did Thursday fall

A.

4,11,18,25

B.

1,8,15,22,29

C.

2,9,16,23,30

D.

3,10,17,24

Answer with explanation

Answer: Option CExplanation

We first find the day of the week on 1^{st} April 2009.

1^{st} April 2009 means, 2008 years 3 months and 1 day

= 2000 years + 8 years + January + February + March + 1^{st} April

= 0 odd days + 2 leap years + 6 ordinary years + 31 days + 28 days +31 days + 1 day

= 0+ 4 odd days + 6 odd days + 3 odd days + 0 odd days +3 odd days + 1 odd day

=17 odd days = 3 odd days

From the date in the above problem, when number of days is 3, the day of the week becomes Wednesday.

Thus, first Thursday falls on 2^{nd} April.

In that month, Thursday falls on 2nd, 9th, 16^{th}, 23^{rd}, and 30^{th}.

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What was the day of the week on 26-January-1950?

A.

Tuesday

B.

Wednesday

C.

Thursday

D.

Sunday

Answer with explanation

Answer: Option CExplanation

Formula:-(Date + Month code + No.of years + No.of leap year + Century code)/7

= (26 + 1 + 50 + 12 + 0)/7 = 89/7 = 12

= Thursday

Day Codes:-

Sat = 0

Sun = 1

Mon = 2

Tue = 3

Wed = 4

Thu = 5

Fri = 6

Month Codes:-

Jan = 1

Feb = 4

Mar = 4

Apr = 0

May = 2

Jun = 5

Jul = 0

Aug = 3

Sep = 6

Oct = 1

Nov = 4

Dec = 6

Century Codes:-

1500 – 1599 —> 0

1600 – 1699 —> 6

1700 – 1799 —> 4

1800 – 1899 —> 2

1900 – 1999 —> 0

2000 – 2099 —> 6

2100 – 2199 —> 4

2200 – 2299 —> 2

2300 – 2399 —> 0

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What will be the day of the week 15th August, 2010?

A.

Monday

B.

Wednesday

C.

Saturday

D.

Sunday

Answer with explanation

Answer: Option DExplanation

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 = 4 odd days.

Jan. Feb. Mar. Apr. May. Jun. Jul. Aug.

(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days

227 days = (32 weeks + 3 days) 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 = 0 odd days.

Given day is Sunday

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The last day of a century cannot be

A.

Wednesday

B.

Tuesday

C.

Friday

D.

Monday

Answer with explanation

Answer: Option BExplanation

100 years contain 5 odd days.

Last day of 1^{st} century is Friday.

200 years contain (5 x 2) 3 odd days.

Last day of 2^{nd} century is Wednesday.

300 years contain (5 x 3) = 15 1 odd day.

Last day of 3^{rd} century is Monday.

400 years contain 0 odd day.

Last day of 4^{th} century is Sunday.

This cycle is repeated.

Last day of a century cannot be Tuesday or Thursday or Saturday.

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