- « Previous Page
- 1
- …
- 3
- 4
- 5
- 6
- Next Page »

A Learning Portal from Recruitment India

The calendar of the year 1897 can be used again in the year?

A.

1903

B.

1908

C.

1926

D.

1901

Answer with explanation

Answer: Option AExplanation

Given year 1908, when divided by 4 leaves a remainder of 1.

**NOTE:** When remainder is 1, 6 is added to the given year to get the result.

So, 1897 + 6 = 1903

Workspace

A.

Friday

B.

Sunday

C.

Thursday

D.

Tuesday

Answer with explanation

Answer: Option DExplanation

Today is Friday.

Lets solve this problem is reverse order

Then we have day after tomorrow = Sunday.

The before day of the day after tomorrow = Saturday

Three days after the before day of the day after tomorrow = Tuesday

Hence Tuesday is the correct answer

Workspace

A.

May 8, Thursday

B.

May 10, Thursday

C.

Cannot be determined

D.

June 8, Friday

Answer with explanation

Answer: Option AExplanation

Radha: May 8, Thursday

Geeta: May 10, Thursday

Revathi: June 8, Friday

We know that April 1^{st} = Tuesday

⇒ May 1^{st} = Tuesday + Remainder of 30/7 = Tuesday + 2days = Thursday.

Also, May 1^{st} = Thursday

⇒ May 8^{th} = Thursday

Also, June 8^{th} = Thursday + Remainder of 31/7 = Thursday + 3 days = Sunday

⇒ Revathi is wrong.

Also, May 10^{th} = May 8 + 2 days = Thursday + 2 days = Saturday

⇒ Geeta is also wrong.

Hence, only Radha is correct.

Hence, correct date is May 8, Thursday.

Workspace

Today is Thursday. The day after 59 days will be?

A.

Wednesday

B.

Sunday

C.

Monday

D.

Tuesday

Answer with explanation

Answer: Option BExplanation

59 days = 8 weeks 3 days

Every day of the week is repeated after 7 days hence after 56 days it

would be Thursday again .And after 59 day it would be Sunday

Workspace

Prove that any date in March of a year is the same day of the week corresponding date in November that year.

A.

Not same day

B.

Same day

C.

Previous day

D.

Next day

Answer with explanation

Answer: Option BExplanation

We will show that the number of odd days between last day of February and last day of October is zero. .

March April May June July Aug. Sept. Oct.

31 + 30 + 31 + 30 + 31 + 31 + 30 + 31

= 241 days = 35 weeks = 0 odd day. ,Number of odd days during this period = 0.

Thus, 1st March of an year will be the same day as 1st November of that year. Hence, the result follows

Workspace

The calendar for the year 2007 will be the same for the year:

A.

2018

B.

2016

C.

2014

D.

2012

Answer with explanation

Answer: Option AExplanation

Count the number of odd days from the year 2007 onwards to get the sum equal to 0 odd day.

Year : 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 2017 Odd day : 1 2 1 1 1 2 1 1 1 2 1

Sum = 14 odd days 0 odd days.

Calendar for the year 2018 will be the same as for the year 2007.

Workspace

How many leap years do 300 years have?

A.

72

B.

73

C.

74

D.

75

Answer with explanation

Answer: Option AExplanation

Given year is divided by 4, and the quotient gives the number of leap years.

Here, 300%4 = 75.

But, as 100,200 and 300 are not leap years => 75 – 3= 72 leap years.

Workspace

Today is 5^{th} August. The day of the week is Wednesday. This is a leap year. What will be the day of the week on this date after 3 years?

A.

Tuesday

B.

Saturday

C.

Thursday

D.

Sunday

Answer with explanation

Answer: Option BExplanation

This is a leap year.

So none of the next 3 years will be leap years.

Each ordinary year has one odd day, so there are 3 odd days in next 3 years.

So the day of the week will be 3 odd days beyond Wednesday i.e. it will be Saturday

Workspace

What will be the day on week 4th April 2001?

A.

Friday

B.

Sunday

C.

Monday

D.

Wednesday

Answer with explanation

Answer: Option DExplanation

April 4th 2001 =(2000 years+Period of 1.1.2001 to 4.4.2001)

Odd days in 2000 years = 0 days

From January to April 4

Total no.of.days: 31+28+31+4=94 days =(13 weeks +3 days)=3 odd days

So the day will be Wednesday

Workspace

What will be the day of the week 15^{th} August 2010?

A.

Monday

B.

Friday

C.

Sunday

D.

Tuesday

Answer with explanation

Answer: Option CExplanation

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 = 4 odd days.

Jan. Feb. Mar. Apr. May. Jun. Jul. Aug.

(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days = (32 weeks + 3 days) = 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 = 0 odd days.

Given day is Sunday

Workspace

Today is Monday. After 61 days, it will be:

A.

Monday

B.

wednesday

C.

Friday

D.

Saturday

Answer with explanation

Answer: Option DExplanation

Each day of the week is repeated after 7 days.

So, after 63 days, it will be Monday.

∴ After 61 days, it will be Saturday.

Workspace

If 1^{st} Jan 2005 is Saturday then what will be 1^{st} Jan 2008?

A.

Monday

B.

Tuesday

C.

Saturday

D.

Sunday

Answer with explanation

Answer: Option BExplanation

On 31st December it was Friday.Number of Odd days between 2006 and 2008 = (1+1)=2days

Then December 31st 2007 will be Monday then 1st Jan 2008 will be Tuesday.

Workspace

On what dates of April 2009 did Thursday fall

A.

4,11,18,25

B.

1,8,15,22,29

C.

2,9,16,23,30

D.

3,10,17,24

Answer with explanation

Answer: Option CExplanation

We first find the day of the week on 1^{st} April 2009.

1^{st} April 2009 means, 2008 years 3 months and 1 day

= 2000 years + 8 years + January + February + March + 1^{st} April

= 0 odd days + 2 leap years + 6 ordinary years + 31 days + 28 days +31 days + 1 day

= 0+ 4 odd days + 6 odd days + 3 odd days + 0 odd days +3 odd days + 1 odd day

=17 odd days = 3 odd days

From the date in the above problem, when number of days is 3, the day of the week becomes Wednesday.

Thus, first Thursday falls on 2^{nd} April.

In that month, Thursday falls on 2nd, 9th, 16^{th}, 23^{rd}, and 30^{th}.

Workspace

What was the day of the week on 26-January-1950?

A.

Tuesday

B.

Wednesday

C.

Thursday

D.

Sunday

Answer with explanation

Answer: Option CExplanation

Formula:-(Date + Month code + No.of years + No.of leap year + Century code)/7

= (26 + 1 + 50 + 12 + 0)/7 = 89/7 = 12

= Thursday

Day Codes:-

Sat = 0

Sun = 1

Mon = 2

Tue = 3

Wed = 4

Thu = 5

Fri = 6

Month Codes:-

Jan = 1

Feb = 4

Mar = 4

Apr = 0

May = 2

Jun = 5

Jul = 0

Aug = 3

Sep = 6

Oct = 1

Nov = 4

Dec = 6

Century Codes:-

1500 – 1599 —> 0

1600 – 1699 —> 6

1700 – 1799 —> 4

1800 – 1899 —> 2

1900 – 1999 —> 0

2000 – 2099 —> 6

2100 – 2199 —> 4

2200 – 2299 —> 2

2300 – 2399 —> 0

Workspace

What will be the day of the week 15th August, 2010?

A.

Monday

B.

Wednesday

C.

Saturday

D.

Sunday

Answer with explanation

Answer: Option DExplanation

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 = 4 odd days.

Jan. Feb. Mar. Apr. May. Jun. Jul. Aug.

(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days

227 days = (32 weeks + 3 days) 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 = 0 odd days.

Given day is Sunday

Workspace

- « Previous Page
- 1
- …
- 3
- 4
- 5
- 6
- Next Page »

Correct Answer 👍

Wrong Answer 👎

RecruitmentIndia.in is Blog where we will update the information by exploring various online and offline sources of information. Our aim is to provide the latest Education related news as fast as possible to the students for free of cost.

Exams.Recruitmentindia.in is a Preparation portal where you can prepare all the competitive related questions like Aptitude, Reasoning, English Questions and Current affairs for free of cost

You can Contact us at :