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Saturday was a holiday for Republic Day. 14th of the next month is again a holiday for Shivratri. What day was it on the 14th?

A.

Sunday

B.

Monday

C.

Tuesday

D.

Thursday

Answer with explanation

Answer: Option DExplanation

As given, Satuday falls on 26th January and we have to find the day on 14th February.

Clearly, 2nd, 9th and 16th February each is a Saturday.

Thus, 14th February was a Thursday.

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Today is 1st April. The day of the week is Wednesday. This is a leap year. The day of the week on this day after 3 years will be:

A.

saturday

B.

friday

C.

monday

D.

Answer with explanation

Answer: Option AExplanation

This being a leap year, none of the next 3 years is a leap year. So, the day of the week will be 3 days beyond Wednesday. The day after 3 years will be Saturday.

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The maximum gap between two successive leap year is?

A.

4

B.

8

C.

10

D.

11

Answer with explanation

Answer: Option BExplanation

This can be illustrated with an example.

Ex: 1896 is a leap year.The next leap year comes in 1904 (1900 is not a leap year).

Explanation : The length of the solar year, however, is slightly less than 365 1/4 days-by about 11 minutes. To compensate for this discrepancy, the leap year is omitted three times every four hundred years.

In other words, a century year cannot be a leap year unless it is divisible by 400. Thus 1700, 1800, and 1900 were not leap years, but 1600, 2000, and 2400 are leap years.

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Second & fourth Saturdays and every Sunday is a holiday. How many working days will be there in a month of 31 days beginning on a Friday ?

A.

24

B.

23

C.

22

D.

25

Answer with explanation

Answer: Option AExplanation

Given that the month begins on a Friday and has 31 days

Sundays = 3rd, 10th, 17th, 24th, 31st

=> Total Sundays = 5

Every second & fourth Saturday is holiday.

2nd & 4th Saturday in every month = 2

Total days in the month = 31

Total working days = 31 – (5 + 2) = 24 days.

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It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

A.

Monday

B.

Friday

C.

Thursday

D.

Saturday

Answer with explanation

Answer: Option BExplanation

On 31 Dec, 2005 it was Saturday.

Number of Odd days for 1 normal year 365/7=1

Number of Odd days for leap year 2

so 2006=1odd day

2007=1odd day

2008leap year 2 odd days

2009=1 odd day

Number of Odd days from the year 2006 to the year 2009 = 1 +1+2+1 =5 On 31st Dec 2009 it was Thursday So, 1st Jan 2010 is Friday

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