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The calendar of the year 1897 can be used again in the year?
1908
1903
1901
1926
Answer with explanation
Answer: Option BExplanation
Repetition of leap year ===> Add +28 to the Given Year.
Repetition of non leap year
Step 1 : Add +11 to the Given Year. If Result is a leap year, Go to step 2.
Step 2: Add +6 to the Given Year.
Solution :
Given Year is 1897, Which is a non leap year.
Step 1 : Add +11 to the given year (i.e 1897 + 11) = 1908, Which is a leap year.
Step 2 : Add +6 to the given year (i.e 1897 + 6) = 1903
Therfore, The calendar of the year 1897 can be used again in the year 1903
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Given that on 9th August 2016 is Saturday. What was the day on 9th August 1616 ?
Saturday
Sunday
Friday
Monday
Answer with explanation
Answer: Option AExplanation
We know that, After every 400 years, the same day occurs.
Thus, if 9th August 2016 is Saturday, before 400 years i.e., on 9th August 1616 has to be Saturday.
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How many leap years does 100 years have?
25
24
4
26
Answer with explanation
Answer: Option BExplanation
Given year is divided by 4, and the quotient gives the number of leap years.
Here, 100%4 = 25.
But, as 100 is not a leap year => 25 – 1= 24 leap years.
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On 8th Dec, 2007 Saturday falls. What day of the week was it on 8th Dec, 2006?
Saturday
Friday
Monday
Tuesday
Answer with explanation
Answer: Option BExplanation
The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.
But, 8th Dec, 2007 is Saturday
S0, 8th Dec, 2006 is Friday.
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What was the day of the week on 17th June, 1998 ?
Monday
Tuesday
Wednesday
Friday
Answer with explanation
Answer: Option CExplanation
17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)
Odd days in 1600 years = 0
Odd days in 300 years = 1
97 years has 24 leap years + 73 ordinary years.
Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.
Jan. Feb. March. April. May. June.
(31 + 28 + 31 + 30 + 31 + 17) = 168 days
168 days = 24 weeks = 0 odd day.
Total number of odd days = (0 + 1 + 2 + 0) = 3.
Given day is Wednesday.
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What day of the week will be 8th June 2215?
Tuesday
Wednesday
Monday
Thursday
Answer with explanation
Answer: Option DExplanation
Calculate the number of odd days from starting till 8th June 2215
Step 1:
2000 = 0 odd days
200 = 3 odd days
14 years = 11 ordinary years + 3 leap years = 11 + 6 = 17 odd days = 3 odd days
Jan till June = 4 odd days
8 days = 8 odd days
Step 2:
Add all the odd days
3 + 3 + 4 + 8 = 18 odd days = 4 odd days
Hence, 4 odd days indicates a Thursday (According to reference chart)
Therefore, 8th June 2215 was a Thursday.
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What was the day of the week on 28th May, 2006?
Thursday
Friday
Saturday
Sunday
Answer with explanation
Answer: Option DExplanation
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) = 6 odd days
(31[jan] + 28 [Feb]+ 31[Mar] + 30[April] + 28[May] ) = 148 dayss = (21 weeks + 1 day) = 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 = 0 odd days.
Given day is Sunday
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How many times does the 29th day of the month occur in 400 consecutive years ?
Answer with explanation
Answer: Option AExplanation
Consider a set of every four years (So as to include the leap year with Feb 29). So in 3 years, 29 will occur 11 times, and once it would accur 12 times. So in 4 years, there will be 3*11 + 12 = 45 days in which you will have 29th. So in 400 years, it would be 4500 times.
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If 09/12/2001 happens to be Sunday, then 09/12/1971 would have been at
Answer with explanation
Answer: Option DExplanation
Every year day increase by 1 and if leap year come then by 2
=> leap year increase on day extra
2001 – 1971 = 30 years
so increase of 30 days
Leap years 1972 , 1976 , 1980 , 1984 , 1988 , 1992 , 1996 ( divisible by 4) , 2000 (divisible by 400)
8 Leap years
Total days increase = 30 + 8 = 38 days
38 = 5*7 + 3
3 days increased from 09/12/1971 to 09/12/1971
so it would be Thursday on 09/12/1971
Read more on Brainly.in – https://brainly.in/question/6133112#readmore
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How many times does the 29th day of the month occur in 400 consecutive years?
5012
4497
4126
1237
Answer with explanation
Answer: Option BExplanation
In 400 consecutive years there are 97 leap years. Hence, in 400 consecutive years February has the 29th day 97 times and the remaining eleven months have the 29th day 400 × 11 or 4400 times.
Therefore, the 29th day of the month occurs (4400 + 97) or 4497 times.
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On 2007, What was the date of last Saturday in May month?
25
21
26
22
Answer with explanation
Answer: Option CExplanation
1 – May – 2007
=(1 + 2 + 7 + 1 + 6)/7 = 17/7 = 3 = Tuesday
= May 1st –> Tuesday + 5 days = Saturday = 5th may
5th may + 7 days = Saturday = 12th may
12th may + 7 days = Saturday = 19th may
19th may + 7 days = Saturday = 26th may
= Answer = 26th may
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John was born on Feb 29th of 2012 which happened to be a Wednesday. If he lives to be 101 years old, how many birthdays would he celebrate on a Wednesday?
5
3
1
4
Answer with explanation
Answer: Option DExplanation
Let us do this iteratively. Feb 29th 2012 = Wednesday => Feb 28th 2012 = Tuesday
Feb 28th 2013 = Thursday (because 2012 is a leap year, there will be 2 odd days)
Feb 28th 2014 = Friday, Feb 28th 2015 = Saturday, Feb 28th 2016 = Sunday, Feb 29th 2016 = Monday
Or, Feb 29th to Feb 29th after 4 years, we have 5 odd days.
So, every subsequent birthday, would come after 5 odd days.
2016 birthday – 5 odd days
2020 birthday – 10 odd days = 3 odd days
2024 birthday – 8 odd days = 1 odd day
2028 birthday – 6 odd days
2032 birthday – 11 odd days = 4 odd days
2036 birthday – 9 odd days = 2 odd days
2040 birthday – 7 odd days = 0 odd days. So, after 28 years he would have a birthday on Wednesday
The next birthday on Wednesday would be on 2068 (further 28 years later), the one after that would be on 2096. His 84th birthday would again be a leap year.
Now, there is a twist again, as 2100 is not a leap year. So, he does not have a birthday in 2100. His next birthday in 2104 would be after 9 odd days since 2096, or 2 odd days since 2096, or on a Thursday.
From now on the same pattern continues. 2108 would be 2 + 5 odd days later = 7 odd days later. Or, 2108 Feb 29th would be a Wednesday.
So, there are 4 occurrences of birthday falling on Wednesday – 2040, 2068 and 2096, 2108.
Correct Answer: 4.
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