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The last day of a century can not be

A.

**Monday **

B.

**Tuesday**

C.

**Wednesday **

D.

**Thursday**

Answer with explanation

Answer: Option CExplanation

From the notes given on this web page, we have

Number of odd days in 100 years (1st century) = 5

So, the last day of 1st century is Friday

Number of odd days in 200 years (2nd century) = 3

So, the last day of 2nd century is Wednesday

Number of odd days in 300 years (3rd century) = 1

So, the last day of 3rd century is Monday

Number of odd days in 400 years (4th century) = 0

So, the last day of 4th century is Sunday

This pattern is repeated

Therefore, the last day of a century can not be Tuesday or Thursday or Saturday.

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Monday falls on 4 th april. 1988. What was the day on 3 rd November 1987?

A.

Monday

B.

Sunday

C.

Tuesday

D.

Wednesday

Answer with explanation

Answer: Option CExplanation

1988 april 4th to 1987 november 3rd we have 27+31+31+29+31+4 = 153 = 153/7 = 21 weeks + 6 odd days.

rnHere is where everyone got confused,As per rules we take

rn[0 -sun 1 -mon 2 -tues 3 -wed 4 – thurs 5 – fri 6 -sat]

rnAs no.of odd days = 6 you may think the answer is saturday…

rnBut here later date is given and former date is asked,so the solution should be something like this..

rnwe have six odd days which means that we are short of one day to get the complete week i.e.., november 2nd would be monday and hence november 3rd is tuesday

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Today is 1 st august. The day of the week is Monday this is a leap year. The day of the week on this day after 3 years will be:

A.

Wednesday

B.

Thursday

C.

Friday

D.

Saturday

Answer with explanation

Answer: Option BExplanation

This being a leap year none of the next 3 years is a leap year. So, the day of the week will be 3 days beyond Monday ie, it will be Thursday.

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What was the day of the week on 4th June, 2002 ?

A.

Tuesday

B.

Wednesday

C.

Thursday

D.

Friday

Answer with explanation

Answer: Option AExplanation

→ 4th June, 2002 = (2001 years + Period from 1.1.2002 to 4.6.2002)

→ Odd days in 1600 years = 0

→ Odd days in 400 years = 0

→ Odd days in 1 ordinary year = 1

→ Odd days in 2001 years = (0+0+1) = 1

→ Jan(31) Feb(28) March(31) April(30) May(31) June(4)

→ (31 + 28 + 31 + 30 + 31 + 4) = 155 days

→ 22 weeks + 1day ≡ 1 odd day

→ Total number of odd days = (1+1) = 2

→ Required day is Tuesday

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Today is Monday. After 61 days it will be :

A.

Tuesday

B.

Wednesday

C.

Saturday

D.

Sunday

Answer with explanation

Answer: Option CExplanation

61 days = 8 weeks 5 days = 5 odd days

Hence if today is Monday, After 61 days, it will be = (Monday + 5 odd days)

= Saturday

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What was the day of the week on 17th June, 1998 ?

A.

Monday

B.

Tuesday

C.

Wednesday

D.

Thursday

Answer with explanation

Answer: Option CExplanation

17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)

Odd days in 1600 years = 0

Odd days in 300 years = 1

97 years has 24 leap years + 73 ordinary years.

Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.

Jan. Feb. March. April. May. June.

(31 + 28 + 31 + 30 + 31 + 17) = 168 days

168 days = 24 weeks = 0 odd day.

Total number of odd days = (0 + 1 + 2 + 0) = 3.

Given day is Wednesday.

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What was the day of the week on 28th May, 2006 ?

A.

Thursday

B.

Friday

C.

Saturday

D.

Sunday

Answer with explanation

Answer: Option DExplanation

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) = 6 odd days

(31[jan] + 28 [Feb]+ 31[Mar] + 30[April] + 28[May] ) = 148 dayss = (21 weeks + 1 day) = 1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7 = 0 odd days.

Given day is Sunday

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What will be the day of the week on 15th August, 2010?

A.

Thursday

B.

Friday

C.

Saturday

D.

Sunday

Answer with explanation

Answer: Option DExplanation

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 x 2 + 7 x 1) = 11 = 4 odd days.

Jan. Feb. Mar. Apr. May. Jun. Jul. Aug.

(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days = (32 weeks + 3 days) = 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 = 0 odd days.

Given day is Sunday

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On what dates of March, 2005 did Friday fall

A.

1st, 8th, 15th, 22nd, 29th

B.

2nd, 9th, 16th, 23rd, 30th

C.

3rd, 10th, 17th, 24th

D.

4th, 11th, 18th, 25th

Answer with explanation

Answer: Option DExplanation

First we find the day on 1.3.2005

→ 1.3.2005 = (2004 years + Period from 1.1.2005 to 1.3.2005)

→ Odd days in 1600 years = 0

→ Odd days in 400 years = 0

→ 4 years = (1 leap year + 3 ordinary years)

→ (1×2+3×1) odd days = 5 odd days

→ Jan(31) Feb(28) March(1)

→ (31 + 28 + 1) = 60 days = (8 weeks + 4 days) ≡ 4 odd days

→ Total number of odd days = (0+0+5+4) = 9 ≡ 2 odd days

→ 1.3.2005 was Tuesday. So, Friday lies on 4.3.2005

→ Hence, Friday lies on 4th, 11th, 18th, and 25th of March, 2005

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What was the day of the week on 16th July, 1776 ?

A.

Monday

B.

Tuesday

C.

Wednesday

D.

Thursday

Answer with explanation

Answer: Option BExplanation

16th July, 1776 = (1775 years + Period from 1st Jan, 1776 to 16th July, 1776)

**Counting of odd days :**

1600 years have 0 odd day.

100 years have 5 odd days.

75 years = (18 leap years + 57 ordinary years) = [(18 x 2) + (57 x 1)] = 93 (13 weeks + 2 days) = 2 odd days

1775 years have (0 + 5 + 2) odd days = 7 odd days = 0 odd day.

Jan Feb Mar Apr May Jun Jul

31 + 29 + 31 + 30 + 31 + 30 + 16 = 198 days= (28 weeks + 2 days)

Total number of odd days = (0 + 2) = 2.

Required day was ‘Tuesday’.

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It was Sunday on Jan 1, 2006. Find the day of the week on Jan 1, 2010 ?

A.

Sunday

B.

Saturday

C.

Friday

D.

Wednesday

Answer with explanation

Answer: Option CExplanation

On 31st December, 2005 it was Saturday.

Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1) = 5 days.

On 31st December 2009, it was Thursday.

Thus, on 1st Jan, 2010 it is Friday

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on Feb 8, 2005. Find the day of the week on Feb 8, 2004 ?

A.

Sunday

B.

Saturday

C.

Friday

D.

Wednesday

Answer with explanation

Answer: Option AExplanation

The year 2004 is a leap year. It has 2 odd days.

The day on 8th Feb, 2004 is 2 days before the day on 8th Feb, 2005.

Hence, this day is Sunday

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If April 11, 1911 was a Tuesday, what was the day on September 17, 1915?

A.

Friday

B.

Thursday

C.

Sunday

D.

Tuesday

Answer with explanation

Answer: Option AExplanation

Firstly in terms of years, the year 1911 to 1912 would give us 2 odd days and 1913, 1914, 1915 would give 1, 1 and 1 odd day respectively.

Now shift the focus on months. If you move one month ahead i.e. from 11th April to 11th May, the month ending in between is April, which gives you 2 days. Now after that the month of May, June, July, and August gives you 3, 2, 3, and 3 odd days respectively.

With this you reach on 11th September 1915. After this, there are 6 more September days (from 11th to 17th September).

The total number of odd days is 2 + 1 + 1 + 1 + 2 + 3 + 2 + 3 + 3 + 6 = 24.

Subtracting 21 (3 full weeks) from this the odd number of days left is 3.

Adding three days to the day given i.e. Tuesday, the answer becomes Friday.

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Pinky was born on 29th, Feb 2016 which happened to be a Monday. If she lives to be till 2099, how many birthdays would she celebrate on a Monday?

A.

1

B.

2

C.

3

D.

4

Answer with explanation

Answer: Option BExplanation

29th Feb, 2016 = Monday => 28th Feb, 2012 = Sunday

28th Feb, 2017 = Tuesday (because 2016 is a leap year, there will be 2 odd days)

Therefore» Feb 28th 2018 (Wednesday), Feb 28th 2019 (Thursday), Feb 28th 2020 (Friday), Feb 29th 2020 (Saturday)

Or, Feb 29th to Feb 29th after 4 years, we have 5 odd days.

So, every subsequent birthday, would come after 5 odd days.

2020 birthday – 5 odd days

2024 birthday – 10 odd days = 3 odd days

2028 birthday – 8 odd days = 1 odd day

2032 birthday – 6 odd days

2036 birthday – 11 odd days = 4 odd days

2040 birthday – 9 odd days = 2 odd days

2044 birthday – 7 odd days = 0 odd days. So, after 28 years, his birthday would fall on Monday.

The next birthday on Monday would be in year 2072 (further 28 years later), the one after that would be in year 2100. But we are told that she lives upto year 2099.

So, there are 2 occurrences of his birthday falling on Monday – 2044 & 2072.

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