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The second day of a month is Friday, What will be the last day of the next month which has 31 days?

A.

Friday

B.

Saturday

C.

Wednesday

D.

Data inadequate

Answer with explanation

Answer: Option DExplanation

We cannot find out the answer because the number of days of the current month is not given.

Fridays of the month are on 2nd,9th,16th 23rdand 30th

On 1st of next month will be Saturday

So Saturdays will be on 8th,15th, 23rd 30th

On 31st it will be Sunday

But if the month is July The next month will have a different day on the last day

Further, if the month is February then also we will have a different answer.

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If it was Wednesday on March 1, 2006, which day was it on March 1, 2002?

A.

Tuesday

B.

Friday

C.

Monday

D.

Sunday

Answer with explanation

Answer: Option BExplanation

Total number of odd days between the years 2002 and 2006 =

(2006 – 2002) + 1 = 5 odd days. The year 2004 is a leap year, it has two odd days. So, one extra odd day is added.

So, if it was Wednesday on March 1, 2006, it would be (Wednesday – 5) Friday on March 1, 2002.

(or)

If a particular date is on a specific date in a year, the same date would have been on the day before in the previous year. However, if the first year is a leap year, the difference in the number of years will be two.

So, if March 01, 2008, was a Saturday (leap year)

March 01, 2007 = Thursday

March 01, 2006 = Wednesday

March 01, 2005 = Tuesday

March 01, 2004 = Monday (leap year)

March 01, 2003 = Saturday

March 01, 2002 = Friday

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January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008?

A.

Monday

B.

Tuesday

C.

Wednesday

D.

sunday

Answer with explanation

Answer: Option BExplanation

The year 2007 is an ordinary year. So, it has 1 odd day.

1^{st} day of the year 2007 was Monday.

1^{st} day of the year 2008 will be 1 day beyond Monday.

Hence, it will be Tuesday.

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Which of the following year is not a leap year?

A.

1200

B.

2000

C.

700

D.

800

Answer with explanation

Answer: Option CExplanation

Remember the leap year rule (Given in the formulas)

1. Every year divisible by 4 is a leap year if it is not a century.

2. Every 4th century is a leap year, but no other century is a leap year.

800,1200 and 2000 come in the category of the 4th century (such as 400, 800, 1200, 1600, 2000, etc).

Hence 800,1200 and 2000 are leap years.

700 is not the 4th century, but it is a century. Hence it is not a leap year

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Second Saturday and every Sunday is a holiday. How many working days will be there in a month of 30 days beginning on a Saturday?

A.

24

B.

28

C.

32

D.

45

Answer with explanation

Answer: Option AExplanation

Mentioned month begins on a Saturday and has 30 days

Sundays = 2^{nd}, 9^{th}, 16^{th}, 23^{rd}, 30^{th}

=> Total Sundays = 5

Every second Saturday is holiday.

1 second Saturday in every month

Total days in the month = 30

Total working days = 30 – (5 + 1) = 24

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Today it is Thursday.After 132 days,it will be

A.

Monday

B.

Sunday

C.

Wednesday

D.

Thursday

Answer with explanation

Answer: Option CExplanation

Since each day of the week is repeated after 7 days.

After 133 days, it will be Thursday.

So one day before that would be Wednesday.

(or)

1 week = 7 days

So, In order to find 132 days after Thursday, we need to find the number of weeks in 132 days

Now if we divide 132 by 7 : Quotient = 18 and Remainder = 6

Here, Quotient shows a number of weeks and the remainder is the number of days. So, If today is Thursday we need to find the day after 18 weeks and 6 days :

So, after 18 weeks it will be Thursday itself and after 6 days of Thursday, It will be Wednesday.

So, Wednesday is the day that comes after 132 days if it is Thursday today.

Hence, Wednesday is the right answer.

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What was the day of the week on June 17, 1991?

A.

Tuesday

B.

Wednesday

C.

Friday

D.

Monday

Answer with explanation

Answer: Option DExplanation

June 17, 1991 = (1990 years + period from 01.01.1991 to 17.06.91)

⇒Odd days in 1600 years = 0

⇒Odd days in the next 300 years = 15 odd days (2 week + 1 odd day) = 1 odd day

90 years have 22 leap years + 68 ordinary years.

⇒Number of odd days in 90 years = 22*2 + 68*1 = 112 odd days (16 weeks + 0 odd day) = 0 odd day

Number of odd days from 01.01.91 to 17.06.91= Jan. (31) + Feb. (28) + March (31) + April (30) + May (31) + June (17) = 168 days

⇒168 days = 24 weeks + 0 odd days

Total number of odd days = 0 + 1 + 0+ 0 = 1 odd day

1 odd day represents Monday, so the given day was Monday.

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On 8^{th} Feb, 2005 it was Tuesday. What was the day of the week on 8^{th} Feb, 2004?

A.

Tuesday

B.

Monday

C.

Sunday

D.

Wednesday

Answer with explanation

Answer: Option CExplanation

The year 2004 is a leap year. It has 2 odd days.

The day on 8^{th} Feb, 2004 is 2 days before the day on 8^{th} Feb, 2005.

Hence, this day is Sunday.

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January 1, 1995 was a Sunday. What day of the week lies on January 1, 1996?

A.

Saturday

B.

Monday

C.

Friday

D.

Sunday

Answer with explanation

Answer: Option BExplanation

The number of days more than the complete weeks are called odd days in a given period.

1 ordinary year = 365 days = (52 weeks + 1 day)

Hence the number of odd days in 1 ordinary year= 1.

1 leap year = 366 days = (52 weeks + 2 days)

Hence the number of odd days in 1 leap year= 2.

100 years = (76 ordinary years + 24 leap years )

= (76 x 1 + 24 x 2) odd days = 124 odd days.

=> (17 weeks + 5 days)

≡ 5 odd days.

Hence the number of odd days in 100 years = 5.

Number of odd days—->Day of the week

==>0—->Sunday

==>1—->Monday

==>2—->Tuesday

==>3—->Wednesday

==>4—->Thursday

==>5—->Friday

==>6—->Saturday

The last day of a century cannot be Tuesday or Thursday or Saturday.

because 100 century consists of 5 odd days, which means Friday is the last day.

200 century consists of 3 odd days, which means Wednesday is the last day.

300 century consists of 1 odd day, which means Monday is the last day.

400 century doesn’t consist of any odd day.

the cycle continues, hence proof.

1995 is an ordinary year, it has 1 odd day. So, the first day of 1996 will be one day beyond Sunday, i.e. it will be Monday.

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Pinky was born on 29th, Feb 2016 which happened to be a Monday. If she lives to be till 2099, how many birthdays would she celebrate on a Monday?

A.

1

B.

3

C.

2

D.

5

Answer with explanation

Answer: Option CExplanation

29th Feb, 2016 = Monday => 28th Feb, 2012 = Sunday

28th Feb 2017 = Tuesday (because 2016 is a leap year, there will be 2 odd days)

Therefore» Feb 28th, 2018 (Wednesday), Feb 28th, 2019 (Thursday), Feb 28th, 2020 (Friday), Feb 29th, 2020 (Saturday)

Or, Feb 29th to Feb 29th after 4 years, we have 5 odd days.

So, every subsequent birthday would come after 5 odd days.

2020 birthday – 5 odd days

2024 birthday – 10 odd days = 3 odd days

2028 birthday – 8 odd days = 1 odd day

2032 birthday – 6 odd days

2036 birthday – 11 odd days = 4 odd days

2040 birthday – 9 odd days = 2 odd days

2044 birthday – 7 odd days = 0 odd days. So, after 28 years, his birthday would fall on Monday.

The next birthday on Monday would be in the year 2072 (further 28 years later), the one after that would be in the year 2100. But we are told that she lives up to the year 2099.

So, there are 2 occurrences of his birthday falling on Monday – 2044 & 2072.

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On what dates of July 2004 did Monday fall?

A.

6th,10th,21st,30th

B.

12th,7th,19th,28th

C.

5th,10th,24th,17th

D.

5th, 12th, 19th, 26th

Answer with explanation

Answer: Option DExplanation

Note: In an ordinary year, there are 365 days, which means 52 x 7 + 1, or 52 weeks and one day. This additional day is called an odd day.

- 1 ordinary year = 365 days = (52 weeks + 1 day.) 1 ordinary year has 1 odd day.
- 1 leap year = 366 days = (52 weeks + 2 days) 1 leap year has 2 odd days.
- 100 years = 76 ordinary years + 24 leap years. = (76 x 1 + 24 x 2) odd days = 124 odd days. = (17 weeks + days) 5 odd days.

Let us find the day on 1st July 2004.

2000 years have 0 odd days. 3 ordinary years have 3 odd days.

Jan. Feb. March April May June July

31 + 29 + 31 + 30 + 31 + 30 + 1

= 183 days = (26 weeks + 1 day) = 1 t .

Total number of odd days = (0 + 3 + 1) odd days = 4 odd days. ‘

:. 1st July 2004 was ‘Thursday’,-,-

Thus, 1st Monday in July 2004 _as on 5th July.

Hence, during July 2004, Monday fell on 5th, 12th, 19th, and 26th…

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** If 18th February, 1997 falls on Tuesday then what will be the day on 18th February, 1999?**

A.

Thursday

B.

Friday

C.

Monday

D.

Tuesday

Answer with explanation

Answer: Option AExplanation

18th February 1997 was Tuesday.

So, 18th February 1998 was Wednesday.

Therefore, 18th February 1999 will be Thursday.

Workspace

The second Saturday and every Sunday is a holiday. How many working days will be there in a month of 30 days beginning on a Saturday?

A.

22

B.

23

C.

24

D.

21

Answer with explanation

Answer: Option CExplanation

The mentioned month begins on a Saturday and has 30 days

Sundays = 2nd, 9th, 16th, 23rd, 30th

=> Total Sundays = 5

Every second Saturday is a holiday.

1 second Saturday in every month

Total days in the month = 30

Total working days = 30 – (5 + 1) = 24

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Which of the following year is not a leap year?

A.

1960

B.

2080

C.

2024

D.

2100

Answer with explanation

Answer: Option DExplanation

The two conditions that decide that a year is a leap year or not is:

• For a year to be a leap year, it should be divisible by 4.

• No century is a leap year unless it is divisible by 400.

Hence, the year 2100 is not a leap year as it is not divisible by 400.

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It was Sunday on Jan 1, 2006. Discover the week’s day on Jan 1, 2010.

A.

Sunday

B.

Saturday

C.

Friday

D.

Wednesday

Answer with explanation

Answer: Option CExplanation

On 31st December,2005 it was Saturday.

Number of odd days frame the year 2006 to the year 2009=(1+1+2+1)=5 days.

∴ On 31st December 2009 , it was Thursday. In this way, on first jan, 2010 it is Friday

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If today is Monday, what will be the day 350 days from now?

A.

Monday

B.

Tuesday

C.

Thurday

D.

Friday

Answer with explanation

Answer: Option AExplanation

350 days, 350/7 = 50, no odd days, so it will be a Monday.

(or)

After 350 days, again there will be Monday.

Because 350 is exactly divisible by 7 and after every 7 days, Monday comes.

(or)

Since 350 is a multiple of 7, we know that in 350 days it will be Monday.

Going backward, 349 days from today will be Sunday,

348 it will be Saturday and, finally,

347 days from now it will be Friday.

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Today is Thursday. The day after 59 days will be?

A.

Sunday

B.

Tuesday

C.

Wednesday

D.

Monday

Answer with explanation

Answer: Option AExplanation

59 days = 8 weeks 3 days = 3 odd days

Hence if today is Thursday, After 59 days, it will be = Thursday + 3 odd days = Sunday.

Workspace

If 5th March, 2005 is Monday, what was the day of the week on 5th March, 2004 ?

A.

Sunday

B.

Monday

C.

Tuesday

D.

Friday

Answer with explanation

Answer: Option AExplanation

The year 2004 is a leap year. So, it has 2 odd days.

But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.

The day of 5th March 2005 will be 1 day beyond the day of 5th March 2004.

Given that, 5th March 2005 is Monday.

5th March 2004 is Sunday (1 day before to 5th March 2005).

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On 8th Feb 2005 it was Tuesday. What was the day of the week on 8th Feb 2004?

A.

Tuesday

B.

Sunday

C.

Monday

D.

Saturday

Answer with explanation

Answer: Option BExplanation

The year 2004 is a leap year. It has 2 odd days.

The day on 8^{th} Feb, 2004 is 2 days before the day on 8^{th} Feb, 2005.

Hence, this day is Sunday.

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On July 2, 1985, it was Wednesday. The day of the week on July 2, 1984 was

A.

Wednesday

B.

Tuesday

C.

Monday

D.

Thursday

Answer with explanation

Answer: Option BExplanation

Let us calculate the number of odd days between these two dates.

July month of 1984 has 29 days left. So odd days are 1.

Now August 1984 to June 1985 ===>> 3 + 2 + 3 + 2 + 3 + 2 + 0 + 3 + 2 + 3 + 2.

Now July 1985 till 2nd July contains 2 odd days.

Total 29 odd days. or 1 odd day.

So July 2, 1984, is 1 day before Wednesday. It is Tuesday.

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On 8th march,2005,wednesday falls what day of the week was it on 8th march,2004?

A.

Monday

B.

Tuesday

C.

Wednesday

D.

Friday

Answer with explanation

Answer: Option BExplanation

As a year contains 365 days with factors of 7(1week) gives 1(day) as a reminder which adjusts one day extra to the next year.

Workspace

How many leap years do 300 years have?

A.

74

B.

75

C.

76

D.

72

Answer with explanation

Answer: Option DExplanation

Given year is divided by 4, and the quotient gives the number of leap years. But, as 100,200 and 300 are not leap years => 75 – 3= 72 leap years.

OR

A 300-year period can have either 72 or 73 leap years. Each 400-year cycle of the Gregorian calendar has 97 leap years, so the average number of leap years for a 300-year period is 72.75.

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If Feb 12th,1986 falls on Wednesday then Jan 1st,1987 falls on which day?

A.

B.

Wednesday

C.

Thursday

D.

Saturday

Answer with explanation

Answer: Option CExplanation

The number of days more than the complete weeks are called odd days in a given period.

1 ordinary year ≡ 365 days ≡ (52 weeks + 1 day)

Hence the number of odd days in 1 ordinary year= 1.

1 leap year ≡ 366 days ≡ (52 weeks + 2 days)

Hence the number of odd days in 1 leap year= 2.

100 years ≡ (76 ordinary years + 24 leap years )

= (76 x 1 + 24 x 2) odd days = 124 odd days.

=> (17 weeks + 5 days)

≡ 5 odd days.

Hence the number of odd days in 100 years = 5.

Number of odd days—->Day of the week

==>0—->Sunday

==>1—->Monday

==>2—->Tuesday

==>3—->Wednesday

==>4—->Thursday

==>5—->Friday

==>6—->Saturday

last day of a century cannot be Tuesday or Thursday or Saturday.

because 100 century consists 5 odd days, means Friday is the last day.

200 century consists 3 odd days, means Wednesday is the last day.

300 century consists 1 odd day, means Monday is the last day.

400 century doesn’t consist any odd day.

the cycle continues, hence proof.

Solution: First, we count the number of odd days for the leftover days in the given period.

Here,given period is 12.2.1986 to 1.1.1987

Feb Mar Apr May June July Aug Sept Oct Nov Dec Jan

16 31 30 31 30 31 31 30 31 30 31 1 (left days)

2 + 3 + 2 + 3 + 2 + 3 + 3 + 2 + 3 + 2 + 3 + 1(odd days) = 1 odd day

So,given day Wednesday + 1 = Thursday is the required result.

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The calendar for 1990 is the same as for

A.

1992

B.

1995

C.

1996

D.

2001

Answer with explanation

Answer: Option DExplanation

For a year to have the same calendar with 1990 ,total odd days from 1990 should be 0.

Take the year 1992 from the given choices.

Total odd days in the period 1990-1991= 2 normal years

≡ 2 x 1 = 2 odd days

Take the year 1995 from the given choices**.**

Number of odd days in the period 1990-1994 = 4 normal years + 1 leap year

≡ 4 x 1 + 1 x 2 = 6 odd days

Take the year 1996 from the given choices.

Number of odd days in the period 1990-1995= 5 normal years + 1 leap year

≡ 5 x 1 + 1 x 2 = 7 odd days ≡ 0 odd days

As we can reduce multiples of 7 from odd days which will not change anything

Though number of odd days in the period 1990-1995 is 0, there is a catch here.

1990 is not a leap year whereas 1996 is a leap year.

Hence calendar for 1990 and 1996 will never be the same.

Take the year 2001 from the given choices.

Number of odd days in the period 1990-2000= 8 normal years + 3 leap years

≡ 8 x 1 + 3 x 2 = 14 odd days ≡ 0 odd days

Also, both 1990 and 2001 are normal years.

Hence 1990 will have the same calendar as that of 2001

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The calendar for the year 1993 will be same for the year

A.

B.

C.

D.

Answer with explanation

Answer: Option AExplanation

**Repetition of leap year ===>** Add +28 to the Given Year.

**Repetition of non leap year**

Step 1 : Add +11 to the Given Year. If Result is a leap year, Go to step 2.

Step 2: Add +6 to the Given Year.

**Solution :**

Given Year is 1993, Which is a non leap year.

Step 1 : Add +11 to the given year (i.e 1993 + 11) = 2004, Which is a leap year.

Step 2 : Add +6 to the given year (i.e 1993 + 6) = 1999

Therfore, The calendar for the year 1993 will be same for the year 1999

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If Mar 18th,1994 falls on Friday then Feb 25th,1995 falls on which day?

A.

B.

C.

D.

Saturday

Answer with explanation

Answer: Option DExplanation

The number of days more than the complete weeks are called odd days in a given period.

1 ordinary year ≡ 365 days ≡ (52 weeks + 1 day)

Hence the number of odd days in 1 ordinary year= 1.

1 leap year ≡ 366 days ≡ (52 weeks + 2 days)

Hence the number of odd days in 1 leap year= 2.

100 years ≡ (76 ordinary years + 24 leap years )

= (76 x 1 + 24 x 2) odd days = 124 odd days.

=> (17 weeks + 5 days)

≡ 5 odd days.

Hence the number of odd days in 100 years = 5.

Number of odd days—->Day of the week

==>0—->Sunday

==>1—->Monday

==>2—->Tuesday

==>3—->Wednesday

==>4—->Thursday

==>5—->Friday

==>6—->Saturday

last day of a century cannot be Tuesday or Thursday or Saturday.

because 100 century consists 5 odd days, means Friday is the last day.

200 century consists 3 odd days, means Wednesday is the last day.

300 century consists 1 odd day, means Monday is the last day.

400 century doesn’t consist any odd day.

the cycle continues, hence proof.

First,we count the number of odd days for the left over days in the given period.Here,given period is 18.3.1994 to 25.2.1995

Month | Mar | Apr | May | Jun | Jul | Aug | Sep | Oct | Nov | Dec | Jan | Feb |
---|---|---|---|---|---|---|---|---|---|---|---|---|

Days | 13 | 30 | 31 | 30 | 31 | 31 | 30 | 31 | 30 | 31 | 31 | 25 |

Odd Days | 6 | 2 | 3 | 2 | 3 | 3 | 2 | 3 | 2 | 3 | 3 | 4 |

Therefore, No. of Odd Days = 6 + 2 + 3 + 2 + 3 + 3 + 2 + 3 + 2 + 3 + 3 + 4 = 36 = 1 odd day

So, given day Friday + 1 = Saturday is the required result.

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If the day after tomorrow is Monday, what day was tomorrow’s day before yesterday?

A.

Saturday

B.

Friday

C.

Thursday

D.

Wednesday

Answer with explanation

Answer: Option CExplanation

The day after tomorrow is Sunday.

Therefore, today is Friday.

The day on tomorrow’s day before yesterday

=Friday – 1 = Thursday

Workspace

Today is Monday. After 61 days it will be

A.

Wednesday

B.

Saturday

C.

Monday

D.

Friday

Answer with explanation

Answer: Option BExplanation

We know, after every 7 days the same day is repeated. So, we must divide 61 by 7 and have to take

the remainder.

the remainder.

Here, after 8 complete weeks again we will get Monday and 5 more days. So, Monday+5=

Saturday

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If 2 January 2019 is Wednesday. Which day of the week will be on 22 January 2019?

A.

Saturday

B.

Friday

C.

Tuesday

D.

Wednesday

Answer with explanation

Answer: Option CExplanation

Since within month ( only date different month and year same), we must count the total day after 2, that is from 3 January to 22 January and then divide by 7. Take remainder as ODD /Extra day. Then add an extra day with the given day. That is, 22-2=20/7, and it will go 2 times and the remainder will be 6. Hence given day +6= Wednesday+6= Tuesday

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