Explanation

16 July, 1776

= (1775 years + period from 1.1.1776 to 16.7.1776.

Checking of odd days.

No. of odd days in 1600 years =0

No. of odd days in 100 years = 5

75 years= 18 jump years+57 conventional years

= (18*2+57*1) odd days = 93 odd days

= (13 weeks +2 days) = 2 odd days.

∴ 1775 years have= (0+5+2) odd days= 7 days= 0 days

Jan + Feb. + March + April + May + June + July

31 +29 + 31 + 30 + 31 + 30 +16 = 198 days

198 days = (28 weeks+2 days) = 2 odd days

=Total no. of odd days = (0+2) = 2

Thus, the required day is Tuesday.

The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
∴ The day on 6^th March, 2005 will be 1 day beyond the day on 6^th March, 2004.
Given that, 6^th March, 2005 is Monday.
∴ 6^th March, 2004 is Sunday (1 day before to 6^th March, 2005).

Number of days from 26-Jan-1996 to 15-May-1996 (both days included)
= 6(Jan) + 29(Feb) + 31 (Mar) + 30(Apr)+ 15(May)
= 111

Here we have to count the number days from 3^rd February, 2012 to 18^th April 2012 ( both inclusive)
The given year is leap year, So February month has 29 days
From 3^rd to 29^th February = 27 days
In March = 30 days
From 1^st to 18^th April = 18 days
Total number of days = 27 + 30 + 18 = 75 days

Consider a set of every four years (So as to include the leap year with Feb 29).

So in 3 years, 29 will occur 11 times, and once it would occur 12 times.

So in 4 years, there will be 3*11 + 12 = 45 days in which you will have 29th.

So in 400 years, it would be 4500 times.

Any year that is a multiple of 100, will not be a leap year, unless it is also a multiple of 400.

So years like 100,200,300 are not leap years.

So 4500-3 = 4497 Days with date as 29th.

So,the answer is 4497 times.