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A Learning Portal from Recruitment India

On what dates of April 2001 did Tuesday fall?

A.

1st, 8th, 15th, 22nd, 29th

B.

4^{th}, 11^{th}, 18^{th}, 25^{th}

C.

3th, 10th, 17th, 24th

D.

2nd, 9th, 16th, 23rd, 30th

Answer with explanation

Answer: Option CExplanation

The correct answer is 3th, 10th, 17th, 24th

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Today is Tuesday. After 62 days it will be

A.

Sunday

B.

Monday

C.

Wednesday

D.

Friday

Answer with explanation

Answer: Option BExplanation

It will be Monday.

Because –

1 week = 7 days

therefore, 63 days will be 9 weeks

so after 63 days, it will be Tuesday

but if you are asking for 62 days then it will be the day before Tuesday which is Monday.

Because –

1 week = 7 days

therefore, 63 days will be 9 weeks

so after 63 days, it will be Tuesday

but if you are asking for 62 days then it will be the day before Tuesday which is Monday.

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If the day before yesterday was Saturday, What day will fall on the day after tomorrow?

A.

Tuesday

B.

Thursday

C.

Wednesday

D.

Friday

Answer with explanation

Answer: Option CExplanation

Sol.

If day before yesterday was Saturday, then today is Monday.

Thus tomorrow will be Tuesday and day after tomorrow will be Wednesday.

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Mohini went to the movies nine days ago. She goes to the movies only on Thursday. What day of the week is today?

A.

Thursday

B.

Sunday

C.

Saturday

D.

Tuesday’

Answer with explanation

Answer: Option CExplanation

Clearly, Nine days ago, it was Thursday.

.’. Today is Saturday.

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15th august 2010 was which day of the week?

A.

Sunday

B.

Wednesday

C.

Thursday

D.

Friday

Answer with explanation

Answer: Option AExplanation

15th August, 2010 = (2009 years + Period 1.1.2010 to 15.8.2010)

Odd days in 1600 years = 0

Odd days in 400 years = 0

9 years = (2 leap years + 7 ordinary years) = (2 × 2 + 7 × 1) = 11 = 4 odd days.

Jan, Feb, Mar, Apr, May, Jun, Jul, Aug

(31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days = (32 weeks + 3 days) = 3 odd days.

Total number of odd days = (0 + 0 + 4 + 3) = 7 = 0 odd days.

The given day is Sunday.

Hence, the correct answer is Sunday.

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What was the week’s day on sixteenth July, 1776?

A.

Wednesday

B.

Friday

C.

Tuesday

D.

Saturday

Answer with explanation

Answer: Option CExplanation

**Explanation**

16 July, 1776

= (1775 years + period from 1.1.1776 to 16.7.1776.

Checking of odd days.

No. of odd days in 1600 years =0

No. of odd days in 100 years = 5

75 years= 18 jump years+57 conventional years

= (18*2+57*1) odd days = 93 odd days

= (13 weeks +2 days) = 2 odd days.

∴ 1775 years have= (0+5+2) odd days= 7 days= 0 days

Jan + Feb. + March + April + May + June + July

31 +29 + 31 + 30 + 31 + 30 +16 = 198 days

198 days = (28 weeks+2 days) = 2 odd days

=Total no. of odd days = (0+2) = 2

Thus, the required day is Tuesday.

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If 6th March, 2005 is Monday, what was the day of the week on 6th March, 2004?

A.

Saturday

B.

Tuesday

C.

Wednesday

D.

Sunday

Answer with explanation

Answer: Option DExplanation

Solution:

The year 2004 is a leap year. So, it has 2 odd days.

But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.

∴ The day on 6^{th} March, 2005 will be 1 day beyond the day on 6^{th} March, 2004.

Given that, 6^{th} March, 2005 is Monday.

∴ 6^{th} March, 2004 is Sunday (1 day before to 6^{th} March, 2005).

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How many days will there be from 26th January, 1996 to 15th May, 1996 (both days included)?

A.

110

B.

112

C.

111

D.

113

Answer with explanation

Answer: Option CExplanation

Number of days from 26-Jan-1996 to 15-May-1996 (both days included)

= 6(Jan) + 29(Feb) + 31 (Mar) + 30(Apr)+ 15(May)

= 111

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How many days are there from 3rd February, 2012 to 18th April 2012 (both inclusive)?

A.

75 days

B.

55 days

C.

65 days

D.

85 days

Answer with explanation

Answer: Option AExplanation

Here we have to count the number days from 3^{rd} February, 2012 to 18^{th} April 2012 ( both inclusive)

The given year is leap year, So February month has 29 days

From 3^{rd} to 29^{th} February = 27 days

In March = 31 days

From 1^{st} to 18^{th} April = 18 days

Total number of days = 27 + 31 + 18 = 76 days

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How many times does the 29th day of the month occur in 400 consecutive years?

A.

4487 times

B.

4497 times

C.

4487 times

D.

4447 times

Answer with explanation

Answer: Option BExplanation

In 400 consecutive years, there are 97 leap years. Hence, in 400 consecutive years, February has the 29th day 97 times and the remaining eleven months have the 29th day 400 × 11 or 4400 times.

Thus the 29th day of the month occurs

= 4400 + 97

= 4497 times.

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If 25th of August in a year is Thursday, the number of Mondays in that month is

A.

5

B.

9

C.

7

D.

11

Answer with explanation

Answer: Option AExplanation

Given that 25th August = Thursday

Hence 29th August = Monday

So 22nd,15th and 8th and 1st of August also will be Mondays

Number of Mondays in August = 5

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Given that on 18th April 1603 is Thursday. What was the day on 18th April 2003?

A.

tuesday

B.

Wednesday

C.

friday

D.

Thursday

Answer with explanation

Answer: Option DExplanation

After every 400 years, the same day occurs. (Because a period of 400 years has 0 odd days)

Thus, 18th April 1603 is Thursday, After 400 years i.e., on 18th April 2003 has to be Thursday.

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Arun went for a movie nine days ago. He goes to watch movies only on Thursdays. What day of the week is today?

A.

Wednesday

B.

Thursday

C.

Friday

D.

Saturday

Answer with explanation

Answer: Option DExplanation

Clearly it can be understood from the question that 9 days ago was a Thursday Number of odd days in 9 days = 2 (As 9 – 7 = 2, reduced perfect multiple of 7 from total days)

Hence today = (Thursday + 2 odd days) = Saturday

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2.12.91 is the first Tuesday. Which is the fourth Thursday of December 91?

A.

22.12.91

B.

25.12.91

C.

24.12.91

D.

23.12.91

Answer with explanation

Answer: Option BExplanation

Given that 2.12.91 is the first Tuesday

Hence we can assume that 4.12.91 is the first Thursday

If we add 7 days to 4.12.91, we will get second Thursday

If we add 14 days to 4.12.91, we will get third Thursday

If we add 21 days to 4.12.91, we will get fourth Thursday

=> fourth Thursday = (4.12.91 + 21 days) = 25.12.91.

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Saturday was a holiday for Republic Day. 14th of the next month is again a holiday for Shivratri. What day was it on the 14th?

A.

Sunday

B.

Monday

C.

Tuesday

D.

Thursday

Answer with explanation

Answer: Option DExplanation

As given, Satuday falls on 26th January and we have to find the day on 14th February.

Clearly, 2nd, 9th and 16th February each is a Saturday.

Thus, 14th February was a Thursday.

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Today is 1st April. The day of the week is Wednesday. This is a leap year. The day of the week on this day after 3 years will be:

A.

saturday

B.

friday

C.

monday

D.

Answer with explanation

Answer: Option AExplanation

This being a leap year, none of the next 3 years is a leap year. So, the day of the week will be 3 days beyond Wednesday. The day after 3 years will be Saturday.

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The maximum gap between two successive leap year is?

A.

4

B.

8

C.

10

D.

11

Answer with explanation

Answer: Option BExplanation

This can be illustrated with an example.

Ex: 1896 is a leap year.The next leap year comes in 1904 (1900 is not a leap year).

Explanation : The length of the solar year, however, is slightly less than 365 1/4 days-by about 11 minutes. To compensate for this discrepancy, the leap year is omitted three times every four hundred years.

In other words, a century year cannot be a leap year unless it is divisible by 400. Thus 1700, 1800, and 1900 were not leap years, but 1600, 2000, and 2400 are leap years.

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Second & fourth Saturdays and every Sunday is a holiday. How many working days will be there in a month of 31 days beginning on a Friday ?

A.

24

B.

23

C.

22

D.

25

Answer with explanation

Answer: Option AExplanation

Given that the month begins on a Friday and has 31 days

Sundays = 3rd, 10th, 17th, 24th, 31st

=> Total Sundays = 5

Every second & fourth Saturday is holiday.

2nd & 4th Saturday in every month = 2

Total days in the month = 31

Total working days = 31 – (5 + 2) = 24 days.

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It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

A.

Monday

B.

Friday

C.

Thursday

D.

Saturday

Answer with explanation

Answer: Option BExplanation

On 31 Dec, 2005 it was Saturday.

Number of Odd days for 1 normal year 365/7=1

Number of Odd days for leap year 2

so 2006=1odd day

2007=1odd day

2008leap year 2 odd days

2009=1 odd day

Number of Odd days from the year 2006 to the year 2009 = 1 +1+2+1 =5 On 31st Dec 2009 it was Thursday So, 1st Jan 2010 is Friday

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If Monday falls on 5th of month, then which day will fall three days after the 26th?

A.

Monday

B.

Tuesday

C.

Wedenesday

D.

Thursday

Answer with explanation

Answer: Option DExplanation

5th is Monday, then 12, 19, 26th also Monday

Then 3 days after is 29th, which is Thursday

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What is the year next to 1990 which will have the same calendar as that of the year 1990?

A.

1992

B.

2001

C.

D.

1996

Answer with explanation

Answer: Option BExplanation

For a year to have the same calendar with 1990, total odd days from 1990 should be 0. Take the year 1992 from the given choices.

Total odd days in the period 1990-1991 = 2 normal years

⇒ 2 x 1 = 2 odd days Take the year 1995 from the given choices.

Number of odd days in the period 1990-1994 = 4 normal years + 1 leap year

⇒ 4 x 1 + 1 x 2 = 6 odd days Take the year 1996 from the given choices.

Number of odd days in the period 1990-1995 = 5 normal years + 1 leap year

⇒ 5 x 1 + 1 x 2 = 7 odd days = 0 odd days

(As we can reduce multiples of 7 from odd days which will not change anything) Though number of odd days in the period 1990-1995 is 0, there is a catch here.

1990 is not a leap year whereas 1996 is a leap year.

Hence calendar for 1990 and 1996 will never be the same.Take the year 2001 from the given choices. Number of odd days in the period 1990-2000 = 8 normal years + 3 leap years

⇒ 8 x 1 + 3 x 2 = 14 odd days = 0 odd days

Also, both 1990 and 2001 are normal years.

Hence 1990 will have the same calendar as that of 2001

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If it was Thursday on Aug 15, 2012, then what was the day on June 11, 2013?

A.

Wednesday

B.

Monday

C.

Saturday

D.

Tuesday

Answer with explanation

Answer: Option AExplanation

First, we count the number of odd days for the left over days in the given period.

Here, given period is from 15.8.2012 to 11.6.2013

Aug Sept Oct Nov Dec Jan Feb Mar Apr May Jun

16 30 31 30 31 31 28 31 30 31 11(left days)

Therefore, 2 + 2 + 3 + 2 + 3 + 3 + 0 + 3 + 2 + 3 + 4 (odd days) = 6 odd days

So, the given day Thursday + 6 = Wednesday.

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If every second Saturday and all Sundays are hoildays in a 30 days month beginning on Saturday, then how many working days are there in that month?

A.

15

B.

18

C.

23

D.

25

Answer with explanation

Answer: Option CExplanation

Since the month begins on Saturday, so 2nd, 9th, 16th, 23rd, 30th days are Sundays.

While 8th and 22nd days are second Saturdays.

Thus, there are 7 holidays in all.

Therefore number of working days = 30 – 7 = 23.

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If the first day of the year 1991 was Tuesday, what day of the week must have been on 1st January, 1998?

A.

thursday

B.

sunday

C.

friday

D.

monday

Answer with explanation

Answer: Option AExplanation

Total number of odd days from 1st Jan, 1991 to 1st Jan, 1998

Year 1991 1992 1993 1994 1995 1996 1997

Odd days I + 2 + 1 + 1 + 1 + 2 + 1 = 9 odd days

2 odd days

The day is 2 days beyond the day on 1st Jan, 1991.

i.e. The required day must be Thursday.

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Pinky was born on 29th, Feb 2016 which happened to be a Monday. If she lives to be till 2099, how many birthdays would she celebrate on a Monday?

A.

1

B.

2

C.

3

D.

5

Answer with explanation

Answer: Option BExplanation

29th Feb, 2016 = Monday => 28th Feb, 2012 = Sunday

28th Feb, 2017 = Tuesday (because 2016 is a leap year, there will be 2 odd days)

Therefore» Feb 28th 2018 (Wednesday), Feb 28th 2019 (Thursday), Feb 28th 2020 (Friday), Feb 29th 2020 (Saturday)

Or, Feb 29th to Feb 29th after 4 years, we have 5 odd days.

So, every subsequent birthday, would come after 5 odd days.

2020 birthday – 5 odd days

2024 birthday – 10 odd days = 3 odd days

2028 birthday – 8 odd days = 1 odd day

2032 birthday – 6 odd days

2036 birthday – 11 odd days = 4 odd days

2040 birthday – 9 odd days = 2 odd days

2044 birthday – 7 odd days = 0 odd days. So, after 28 years, his birthday would fall on Monday.

The next birthday on Monday would be in year 2072 (further 28 years later), the one after that would be in year 2100. But we are told that she lives upto year 2099.

So, there are 2 occurrences of his birthday falling on Monday – 2044 & 2072.

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January 1, 2007 was Monday. What day of the week lies on Jan. 1, 2008?

A.

Monday

B.

Tuesday

C.

Wednesday

D.

Sunday

Answer with explanation

Answer: Option BExplanation

The year 2007 is an ordinary year. So, it has 1 odd day.

1^{st} day of the year 2007 was Monday.

1^{st} day of the year 2008 will be 1 day beyond Monday.

Hence, it will be Tuesday.

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How many days will there be from 26th January, 1996 to 15th May, 1996(both days included)?

A.

110

B.

111

C.

112

D.

113

Answer with explanation

Answer: Option BExplanation

Number of days = (6 + 29 + 31 + 30 + 15) = 111.

Note : 1988 is a leap year. So, number of days in February = 29.

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What will be the day of the week on 1st Jan 2001?

A.

sunday

B.

friday

C.

monday

D.

tuesday

Answer with explanation

Answer: Option CExplanation

100 years contain 5 odd days.(it includes leap years also)

2000 years contain 20*5=100 odd days

400,800,1200,1600,200 are leap years because these are divisible by 400 so another 5 odd days

whereas 100,200,300,500..etc are not leap years

total of 105 odd days

105/7=0

2000 Dec 31 is Sunday next day is Monday

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On 8^{th} Dec, 2007 Saturday falls. What day of the week was it on 8^{th} Dec, 2006?

A.

Sunday

B.

Monday

C.

Friday

D.

Sunday

Answer with explanation

Answer: Option CExplanation

The year 2006 is an ordinary year. So, it has 1 odd day.

So, the day on 8^{th} Dec, 2007 will be 1 day beyond the day on 8^{th} Dec, 2006.

But, 8^{th} Dec, 2007 is Saturday.

8^{th} Dec, 2006 is Friday.

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