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A Learning Portal from Recruitment India

Arun went for a movie nine days ago. He goes to watch movies only on Thursdays. What day of the week is today?

A.

Wednesday

B.

Thursday

C.

Friday

D.

Saturday

Answer with explanation

Answer: Option DExplanation

Clearly it can be understood from the question that 9 days ago was a Thursday Number of odd days in 9 days = 2 (As 9 – 7 = 2, reduced perfect multiple of 7 from total days)

Hence today = (Thursday + 2 odd days) = Saturday

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2.12.91 is the first Tuesday. Which is the fourth Thursday of December 91?

A.

22.12.91

B.

25.12.91

C.

24.12.91

D.

23.12.91

Answer with explanation

Answer: Option BExplanation

Given that 2.12.91 is the first Tuesday

Hence we can assume that 4.12.91 is the first Thursday

If we add 7 days to 4.12.91, we will get second Thursday

If we add 14 days to 4.12.91, we will get third Thursday

If we add 21 days to 4.12.91, we will get fourth Thursday

=> fourth Thursday = (4.12.91 + 21 days) = 25.12.91.

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Saturday was a holiday for Republic Day. 14th of the next month is again a holiday for Shivratri. What day was it on the 14th?

A.

Sunday

B.

Monday

C.

Tuesday

D.

Thursday

Answer with explanation

Answer: Option DExplanation

As given, Satuday falls on 26th January and we have to find the day on 14th February.

Clearly, 2nd, 9th and 16th February each is a Saturday.

Thus, 14th February was a Thursday.

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Today is 1st April. The day of the week is Wednesday. This is a leap year. The day of the week on this day after 3 years will be:

A.

saturday

B.

friday

C.

monday

D.

Answer with explanation

Answer: Option AExplanation

This being a leap year, none of the next 3 years is a leap year. So, the day of the week will be 3 days beyond Wednesday. The day after 3 years will be Saturday.

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The maximum gap between two successive leap year is?

A.

4

B.

8

C.

10

D.

11

Answer with explanation

Answer: Option BExplanation

This can be illustrated with an example.

Ex: 1896 is a leap year.The next leap year comes in 1904 (1900 is not a leap year).

Explanation : The length of the solar year, however, is slightly less than 365 1/4 days-by about 11 minutes. To compensate for this discrepancy, the leap year is omitted three times every four hundred years.

In other words, a century year cannot be a leap year unless it is divisible by 400. Thus 1700, 1800, and 1900 were not leap years, but 1600, 2000, and 2400 are leap years.

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Second & fourth Saturdays and every Sunday is a holiday. How many working days will be there in a month of 31 days beginning on a Friday ?

A.

24

B.

23

C.

22

D.

25

Answer with explanation

Answer: Option AExplanation

Given that the month begins on a Friday and has 31 days

Sundays = 3rd, 10th, 17th, 24th, 31st

=> Total Sundays = 5

Every second & fourth Saturday is holiday.

2nd & 4th Saturday in every month = 2

Total days in the month = 31

Total working days = 31 – (5 + 2) = 24 days.

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It was Sunday on Jan 1, 2006. What was the day of the week Jan 1, 2010?

A.

Monday

B.

Friday

C.

Thursday

D.

Saturday

Answer with explanation

Answer: Option BExplanation

On 31 Dec, 2005 it was Saturday.

Number of Odd days for 1 normal year 365/7=1

Number of Odd days for leap year 2

so 2006=1odd day

2007=1odd day

2008leap year 2 odd days

2009=1 odd day

Number of Odd days from the year 2006 to the year 2009 = 1 +1+2+1 =5 On 31st Dec 2009 it was Thursday So, 1st Jan 2010 is Friday

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If Monday falls on 5th of month, then which day will fall three days after the 26th?

A.

Monday

B.

Tuesday

C.

Wedenesday

D.

Thursday

Answer with explanation

Answer: Option DExplanation

5th is Monday, then 12, 19, 26th also Monday

Then 3 days after is 29th, which is Thursday

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What is the year next to 1990 which will have the same calendar as that of the year 1990?

A.

1992

B.

2001

C.

D.

1996

Answer with explanation

Answer: Option BExplanation

For a year to have the same calendar with 1990, total odd days from 1990 should be 0. Take the year 1992 from the given choices.

Total odd days in the period 1990-1991 = 2 normal years

⇒ 2 x 1 = 2 odd days Take the year 1995 from the given choices.

Number of odd days in the period 1990-1994 = 4 normal years + 1 leap year

⇒ 4 x 1 + 1 x 2 = 6 odd days Take the year 1996 from the given choices.

Number of odd days in the period 1990-1995 = 5 normal years + 1 leap year

⇒ 5 x 1 + 1 x 2 = 7 odd days = 0 odd days

(As we can reduce multiples of 7 from odd days which will not change anything) Though number of odd days in the period 1990-1995 is 0, there is a catch here.

1990 is not a leap year whereas 1996 is a leap year.

Hence calendar for 1990 and 1996 will never be the same.Take the year 2001 from the given choices. Number of odd days in the period 1990-2000 = 8 normal years + 3 leap years

⇒ 8 x 1 + 3 x 2 = 14 odd days = 0 odd days

Also, both 1990 and 2001 are normal years.

Hence 1990 will have the same calendar as that of 2001

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If it was Thursday on Aug 15, 2012, then what was the day on June 11, 2013?

A.

Wednesday

B.

Monday

C.

Saturday

D.

Tuesday

Answer with explanation

Answer: Option AExplanation

First, we count the number of odd days for the left over days in the given period.

Here, given period is from 15.8.2012 to 11.6.2013

Aug Sept Oct Nov Dec Jan Feb Mar Apr May Jun

16 30 31 30 31 31 28 31 30 31 11(left days)

Therefore, 2 + 2 + 3 + 2 + 3 + 3 + 0 + 3 + 2 + 3 + 4 (odd days) = 6 odd days

So, the given day Thursday + 6 = Wednesday.

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If every second Saturday and all Sundays are hoildays in a 30 days month beginning on Saturday, then how many working days are there in that month?

A.

15

B.

18

C.

23

D.

25

Answer with explanation

Answer: Option CExplanation

Since the month begins on Saturday, so 2nd, 9th, 16th, 23rd, 30th days are Sundays.

While 8th and 22nd days are second Saturdays.

Thus, there are 7 holidays in all.

Therefore number of working days = 30 – 7 = 23.

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If the first day of the year 1991 was Tuesday, what day of the week must have been on 1st January, 1998?

A.

thursday

B.

sunday

C.

friday

D.

monday

Answer with explanation

Answer: Option AExplanation

Total number of odd days from 1st Jan, 1991 to 1st Jan, 1998

Year 1991 1992 1993 1994 1995 1996 1997

Odd days I + 2 + 1 + 1 + 1 + 2 + 1 = 9 odd days

2 odd days

The day is 2 days beyond the day on 1st Jan, 1991.

i.e. The required day must be Thursday.

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