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A Learning Portal from Recruitment India

A library has an average of 510 visitors on Sundays and 240 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is :

A.

285

B.

290

C.

297

D.

305

Answer with explanation

Answer: Option AExplanation

Since the month begins with a Sunday,

so there will be five Sundays in the month,

Required average = (510 * 5 + 240 * 25) / 30

8550/30 = 285.

Workspace

In an exam, the average marks for 80 students of Class V is 35. The average of marks in section A of the class is 55 while the average of marks in section B is 30. Find the number of students in section B?

A.

45

B.

50

C.

64

D.

60

Answer with explanation

Answer: Option CExplanation

Total students i.e. Section A + Section B = 80

Section A = (80 – Section B) = 80 – B

∴ 80 x 35 = B x 30 + (80 – B) x 55

2800 = 30B + 4400 – 55B

1600 = 25 B

B = 64

∴ B = 64 = Number of students in section B.

Workspace

A.

66 kg.

B.

67 kg.

C.

69 kg.

D.

68 kg.

Answer with explanation

Answer: Option BExplanation

Workspace

The batting average for 40 innings of a cricket player is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, the average of the remaining 38 innings is 48 runs. The highest score of the player is ?

A.

165

B.

170

C.

172

D.

174

Answer with explanation

Answer: Option DExplanation

Workspace

A.

23 years

B.

24 years

C.

25 years

D.

None of these

Answer with explanation

Answer: Option AExplanation

Let the average age of the whole team by x years.

11x – (26 + 29) = 9(x -1)

11x – 9x = 46

2x = 46

x = 23.

So, average age of the team is 23 years.

Workspace

If we choose four numbers, the average of the first three will be 16 and that of last three is 15. If the last number is 18, the first number will be?

A.

20

B.

21

C.

23

D.

25

Answer with explanation

Answer: Option BExplanation

Sum of Last 3 numbers= 15*3=45

Hence the last number is 18

So, Sum of 2nd & 3rd = 45-18= 27

Again sum of first three numbers =16*3=48

Therefore the 1st number will be

sum of 1st 3 number-sum of 2nd & 3rd number

i.e. 48-27=21

Workspace

Rakshit sold 21 tables in a day. He told his father, “My earnings at end of the day are Rs 400000/-. The average earning from the first 11 tables I sold was Rs 20000/-“. What were his average earnings from the remaining tables?

A.

Rs. 9125

B.

Rs. 9750

C.

Rs. 16,363

D.

Rs. 18,000

Answer with explanation

Answer: Option DExplanation

Workspace

The average weight of 8 person’s increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person?

A.

76 kg

B.

76.5 kg

C.

85 kg

D.

Data inadequate

Answer with explanation

Answer: Option CExplanation

Total weight increased = (8 x 2.5) kg = 20 kg.

Weight of new person = (65 + 20) kg = 85 kg.

Workspace

If the average of 20 numbers is zero, how many numbers may be greater than zero?

A.

49

B.

50

C.

19

D.

25

Answer with explanation

Answer: Option CExplanation

Average of 20 numbers = 0.

Sum of 20 numbers = (0 x 20) = 0.

So, it is quite possible that 19 of these numbers may be positive and if their sum is “X” then 20th number will be (-X).

Workspace

A grocer has a sale of Rs 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs 6500?

A.

4991

B.

5467

C.

5987

D.

6453

Answer with explanation

Answer: Option AExplanation

Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.

Required sale = Rs.[(6500 x 6) – 34009] = Rs. (39000 – 34009) = Rs. 4991.

Workspace

A.

35

B.

65

C.

88

D.

25

Answer with explanation

Answer: Option DExplanation

39x = 5 + 12 + 15 + 19 + (x – 4)44

x = 25

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