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If the average of 20 numbers is zero, how many numbers may be greater than zero?

A.

49

B.

50

C.

19

D.

25

Answer with explanation

Answer: Option CExplanation

Average of 20 numbers = 0.

Sum of 20 numbers = (0 x 20) = 0.

So, it is quite possible that 19 of these numbers may be positive and if their sum is “X” then 20th number will be (-X).

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A grocer has a sale of Rs 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs 6500?

A.

4991

B.

5467

C.

5987

D.

6453

Answer with explanation

Answer: Option AExplanation

Total sale for 5 months = Rs. (6435 + 6927 + 6855 + 7230 + 6562) = Rs. 34009.

Required sale = Rs.[(6500 x 6) – 34009] = Rs. (39000 – 34009) = Rs. 4991.

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A.

35

B.

65

C.

88

D.

25

Answer with explanation

Answer: Option DExplanation

39x = 5 + 12 + 15 + 19 + (x – 4)44

x = 25

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A car owner buys petrol at Euro 7.50, Euro 8 and Euro 8.50 per litre for three successive years. What approximately is the average cost per litre of petrol if he spends Euro 4000 each year?

A.

Euro 7.98

B.

Euro 8

C.

Euro 8.50

D.

Euro 9

Answer with explanation

Answer: Option AExplanation

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The average mark of a class in a science test is 75.75. Geetha was the topper with 9696 marks. If her mark was wrongly entered as 69,69, the average of the class decreases by 11. Find the number of students in the class?

A.

18

B.

27

C.

36

D.

96

Answer with explanation

Answer: Option BExplanation

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In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?

A.

6.25

B.

0.23

C.

4.56

D.

6.59

Answer with explanation

Answer: Option AExplanation

Runs scored in the first 10 overs = 10 × 3.2 = 32

Total runs = 282

Remaining runs to be scored = 282 – 32 = 250

Remaining overs = 40

Run rate needed = 250/40=6.25

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A team of eight entered for a shooting competition. The best marks man scored 85 points. If he had scored 92 points, the average scores for. The team would have been 84. How many points altogether did the team score?

A.

685

B.

524

C.

458

D.

665

Answer with explanation

Answer: Option DExplanation

8 * 84 = 672 – 7 = 665

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The avergae of weight of 8 persons increases by 2.5 kg when a new person comes in place of one of them weighing 65 kg.What might be the weight of new person?

A.

55 kg

B.

95 kg

C.

85 kg

D.

105 kg

Answer with explanation

Answer: Option CExplanation

Let Average of the 7 people who are same be ‘X’

The person who is replaced is of 65kg.

Then, given problem is:

`(‘X’ + 65)/8 + 2.5 = (‘X’ + ‘New Person’)/8`

`(‘X’ + 85)/8 = (‘X’ + ‘New Person’)/8`

Therefore, ‘New Person’ = 85;

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The average of Sohan’s marks in 6 subjects is 74. If his average in five subjects excluding science is 70, how many marks he obtained in science?

A.

90

B.

94

C.

85

D.

100

Answer with explanation

Answer: Option BExplanation

Total marks obtained in 6 subjects = 6 ∗ 74 = 444

Total marks in 5 subjects excluding science = 5 ∗ 70 = 350

Therefore, marks obtained in science would be = 444 – 350 = 94

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A.

67 kg

B.

53 kg

C.

69 kg

D.

85 kg

Answer with explanation

Answer: Option AExplanation

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The mean weight of a group of seven boys is 56 kg. The individual weights (in kg) of six of them are 52, 57, 55, 60, 59 and 55. Find the weight of the seventh boy.

A.

34 kg.

B.

44 kg.

C.

52 kg.

D.

54 kg.

Answer with explanation

Answer: Option DExplanation

Mean weight of 7 boys = 56 kg.

Total weight of 7 boys = (56 × 7) kg = 392 kg.

Total weight of 6 boys = (52 + 57 + 55 + 60 + 59 + 55) kg

= 338 kg.

Weight of the 7th boy = (total weight of 7 boys) – (total weight of 6 boys)

= (392 – 338) kg

= 54 kg.

Hence, the weight of the seventh boy is 54 kg.

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The average height of 30 boys was calculated to be 150 cm. It was detected later that one value of 165 cm was wrongly copied as 135 cm for the computation of the mean. Find the correct mean.

A.

121 cm

B.

141 cm

C.

155 cm

D.

151 cm

Answer with explanation

Answer: Option DExplanation

Calculated average height of 30 boys = 150 cm.

Incorrect sum of the heights of 30 boys

= (150 × 30)cm

= 4500 cm.

Correct sum of the heights of 30 boys

= (incorrect sum) – (wrongly copied item) + (actual item)

= (4500 – 135 + 165) cm

= 4530 cm.

Correct mean = correct sum/number of boys

= (4530/30) cm

= 151 cm.

Hence, the correct mean height is 151 cm

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The aggregate monthly expenditure of a family was $ 6240 during the first 3 months, $ 6780 during the next 4 months and $ 7236 during the last 5 months of a year. If the total saving during the year is $ 7080, find the average monthly income of the family.

A.

7485

B.

7225

C.

7422

D.

7425

Answer with explanation

Answer: Option DExplanation

Total expenditure during the year

= $[6240 × 3 + 6780 × 4 + 7236 × 5]

= $ [18720 + 27120 + 36180]

= $ 82020.

Total income during the year = $ (82020 + 7080) = $ 89100.

Average monthly income = (89100/12) = $7425.

Hence, the average monthly income of the family is $ 7425.

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The average of 52 numbers is 45. if two numbers, namely, 55 & 45 are discarded from the set of number, then find average of the remaining numbers.

A.

43

B.

44

C.

44.2

D.

44.8

Answer with explanation

Answer: Option DExplanation

The sum of remaining 50 number ( i. e 52 – 2 )

52 x 45 – 45 – 55 = 2340 – 100 = 2240

The average of remaining numbers = 2240 / 50 = 44.8

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The average of ten numbers is 15. If each number is multiplied by 12, then find the average of the new set of numbers.

A.

150

B.

160

C.

170

D.

180

Answer with explanation

Answer: Option DExplanation

When we multiply each number by ” X “, the average would also get multiplied by “X”.

Hence the average of new set of numbers = 15 x 12 = 180.

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