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The ratio of the ages of Mahesh and Nilesh is 5 : x. Mahesh is 18 years younger to Ramesh. After nine years Ramesh will be 47 years old. If the difference between the ages of Mahesh and Nilesh is same as the age of Ramesh, what is the value of x?

A.

14.5

B.

11.5

C.

13.3

D.

15.6

Answer with explanation

Answer: Option AExplanation

Let the present ages of Mahesh, Nilesh and Ramesh be k, l and m respectively.

k/l = 5/x —— (1)

k = m – 18 —— (2)

m + 9 = 47 —— (3)

k – l = m —– (4)

(3) => m = 47 – 9 = 38 years

(2) => k = 38 -18 = 20 years

(1) => 20/l = 5/x => l = 4x

(4) => 4x – 20 = 38

=> 4x = 58 => x = 14.5

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The age of father 10 years ago was thrice the age of his son. Ten years hence, father’s age was five times the age of the son. After 6 years, son’s age will be

A.

13:4

B.

9:2

C.

5:2

D.

7:3

Answer with explanation

Answer: Option DExplanation

Let the age of father and son 10 years ago be 3x and x years respectively.

Then, (3x + 10) + 10 = 2[(x + 10) + 10]

3x + 20 = 2x + 40 => x = 20.

Required ratio = (3x + 10):(x + 10) = 70:30 = 7:3

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My brother is 33 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, then what was the age of my father when my brother was born?

A.

32 years

B.

34 years

C.

36 years

D.

38 years

Answer with explanation

Answer: Option AExplanation

Let my age =x

Then,

My brother’s age =x+3

My mother’s age =x+26

My sister’s age =(x+3)+4=x+7

My father’s age =(x+7)+28=x+35

Age of my father when my brother was born

=x+35−(x+3)=32

**(Or)**

Father’s age was 28 years when my sister was born.

My sister’s age was 4 years when my brother was born.

Therefore, father’s age was 28+4=32 years when my brother was born.

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A father said to his son, “I was as old as you are at present at the time of your birth.” If the father’s age is 38 years now, the son’s age five years back was:

A.

38 years

B.

19 years

C.

14 years

D.

34 years

Answer with explanation

Answer: Option CExplanation

Let the son’s present age be x years.

Then, (38 – x) = x

2x = 38

=> x = 19

Son’s age 5 years back = (19 – 5) = 14 years.

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The ratio of ages of three persons is 4:7:9, Eight years ago, the sum of their ages was 56. Find their present ages.

A.

16,28,36

B.

16,28,27

C.

16,35,36

D.

12,28,36

Answer with explanation

Answer: Option AExplanation

Let the present ages are 4x, 7x, 9x.

=> (4x-8) + (7x-8) + (9x-8) = 56

=> 20x = 80

=> x = 4

So their present ages are: 16,28,36

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The proportion of Yuvaraj’s age to Ganguly’s age is 4:3. Yuvaraj will be 26 years old after 6 years. What is the age of Ganguly now?

A.

13 years

B.

15 years

C.

17 years

D.

19 years

Answer with explanation

Answer: Option BExplanation

Current ages of Yuvaraj = 4A and Ganguly = 3A

So that 4A + 6 = 26

=> A = 5

Current age of Ganguly = 3A

=> 3 x 5 = 15 years

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A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is

A.

24 years

B.

23 yaers

C.

22 years

D.

21 years

Answer with explanation

Answer: Option CExplanation

Let’s Son age is x, then Father age is x+24.

=> 2(x+2) = (x+24+2)

=> 2x+4 = x+26

=> x = 22 years

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Sobha’s father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?

A.

3 years

B.

4 years

C.

5 years

D.

6 years

Answer with explanation

Answer: Option DExplanation

Let Sobha’s age = x and

her brother’s age = x−4

Sobha’s father’s age = x+38

Sobha’s mother’s age = (x−4) + 36 = x+32

====>>>> Sobha’s father’s age – Sobha’s mother’s age

====>>>>(x+38) − (x+32) = 6

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A person’s present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?

A.

36 years

B.

40 years

C.

38 years

D.

36 years

Answer with explanation

Answer: Option BExplanation

Let the mother’s present age be *x* years.

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The ratio of the age of a man and his wife is 4:3. At the time of marriage, the ratio was 5:3 and After 4 years this ratio will become 9:7. How many years ago were they married?

A.

8 years

B.

12 years

C.

11 years

D.

10 years

Answer with explanation

Answer: Option BExplanation

Let the present age of the man and his wife be 4x and 3x respectively.

After 4 years this ratio will become 9:7

⇒ (4x+4) : (3x+4)= 9:7

⇒ 7(4x+4) = 9(3x+4)

⇒ 28x+28 = 27x+36

⇒ x = 8

The present age of the man = 4x =>> 4×8 = 32

The present age of his wife = 3x =>> 3×8 = 24

Assume that they got married before t years. Then,

⇒ (32−t) : (24−t) = 5:3

⇒ 3(32−t) = 5(24−t)

⇒ 96−3t = 120−5t

⇒ 2t = 24

⇒ t = 24/2 =12

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The ages of two persons differ by 20 years. If 5 years ago, the elder one be 5 times as old as the younger one, their present ages (in years) are respectively

A.

30,10

B.

20,20

C.

25,15

D.

20,10

Answer with explanation

Answer: Option AExplanation

Let their ages be x and (x + 20) years.

5 (x – 5) = (x + 20 – 5) or 4x = 40 or x = 10.

Their present ages are 30 years and 10 years

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The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person?

A.

40

B.

20

C.

30

D.

10

Answer with explanation

Answer: Option CExplanation

Let the present age of the elder person = x and

the present age of the younger person =x−16⇒ (x−6)=3(x−16−6)

⇒ x−6 = 3x−66

⇒ 2x = 60

⇒ x = 60/2 = 30

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The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. what is the age of the youngest child?

A.

8

B.

4

C.

10

D.

6

Answer with explanation

Answer: Option BExplanation

Let x = the youngest child. Each of the other four children will then be x+3, x+6, x+9, x+12.

We know that the sum of their ages is 50.

so, x+(x+3)+(x+6)+(x+9)+(x+12) = 50

=====>>>>> x= 4

The youngest child is 4 years old.

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Sachin is younger than Rahul by 7 years. If the ratio of their ages is 7:9, find the age of Sachin

A.

12.5

B.

14.5

C.

24.5

D.

23.5

Answer with explanation

Answer: Option CExplanation

If Rahul age is x, then Sachin age is x-7,

so (x-7)/x = 7/9

=> 9x-63 = 7x

=> 2x = 63

=> x = 31.5

So Sachin age is 31.5 – 7 = 24.5

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The ratio of Rohan’s age 4 years ago and Rahul’s age after 4 years is 1:1. If at present, the ratio of their ages is 5 : 3, then find the ratio between Rohan’s age 4 years hence and Rahul’s age 4 years ago.

A.

4 : 3

B.

1 : 3

C.

3 : 4

D.

3 : 1

Answer with explanation

Answer: Option DExplanation

** **If ages in the numerical are mentioned in ratio A : B, then A : B will be Ax and Bx

1. At present*: *Ratio of their ages = 5 : 3. Therefore, 5 : 3 will be 5x and 3x.

=====>>>> Rohan’s age 4 years ago = 5x – 4

=====>>>> Rahul’s age after 4 years = 3x + 4

2. Ratio of Rohan’s age 4 years ago and Rahul’s age after 4 years is 1 : 1

Therefore,

Solving, we get x = 4

3. We are asked to find the ratio between Rohan’s age 4 years hence and Rahul’s age 4 years ago.

Rohan’s age : (5x + 4)

Rahul’s age: (3x – 4)

Ratio of Rahul’s age and Rohan’s age

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