Let the present ages of Mahesh, Nilesh and Ramesh be k, l and m respectively.
k/l = 5/x —— (1)
k = m – 18 —— (2)
m + 9 = 47 —— (3)
k – l = m —– (4)
(3) => m = 47 – 9 = 38 years
(2) => k = 38 -18 = 20 years
(1) => 20/l = 5/x => l = 4x
(4) => 4x – 20 = 38
=> 4x = 58 => x = 14.5

Let the age of father and son 10 years ago be 3x and x years respectively.

Let my age $=x$
Then,
My brother’s age $=x+3$
My mother’s age $=x+26$
My sister’s age $=(x+3)+4=x+7$
My father’s age $=(x+7)+28=x+35$

Age of my father when my brother was born
$=x+35-(x+3)=32$

(Or)

Father’s age was $28$ years when my sister was born.

My sister’s age was $4$years when my brother was born.

Therefore, father’s age was $28+4=32$ years when my brother was born.

Let the son’s present age be x years.

Let the present ages are 4x, 7x, 9x.
=> (4x-8) + (7x-8) + (9x-8) = 56
=> 20x = 80
=> x = 4

So their present ages are: 16,28,36

Current ages of Yuvaraj = 4A and Ganguly = 3A
So that 4A + 6 = 26
=> A = 5

Current age of Ganguly = 3A
=> 3 x 5 = 15 years

Let’s Son age is x, then Father age is x+24.
=> 2(x+2) = (x+24+2)
=> 2x+4 = x+26
=> x = 22 years

Let Sobha’s age $=x$ and
her brother’s age $=x-4$

Sobha’s father’s age $=x+38$
Sobha’s mother’s age $=(x-4)+36=x+32$

====>>>> Sobha’s father’s age – Sobha’s mother’s age
$====>>>>(x+38)-(x+32)=6$

=====>>>>>(A + B) – (B + C) = 12

Let the mother’s present age be x years.

Let the present age of the man and his wife be $4x$ and $3x$ respectively.

After $4$ years this ratio will become $9:7$

$\Rightarrow (4x+4):(3x+4)=9:7$

$\Rightarrow 7(4x+4)=9(3x+4)$

$\Rightarrow 28x+28=27x+36$

$\Rightarrow x=8$

The present age of the man $=4x=>>4\times 8=32$
The present age of his wife $=3x=>>3\times 8=24$

Assume that they got married before  years. Then,

$\Rightarrow$

$\Rightarrow 3(32-t)=5(24-t)$

$\Rightarrow 96-3t=120-5t$

$\Rightarrow 2t=24$

$\Rightarrow t=\frac{\mathrm{24/}}{2}=12$

Let their ages be x and (x + 20) years.
5 (x – 5) = (x + 20 – 5) or 4x = 40 or x = 10.
Their present ages are 30 years and 10 years

Let the present age of the elder person $=x$ and

the present age of the younger person $=x-16$$\Rightarrow$

$\Rightarrow x-6=3x-66$

$\Rightarrow 2x=60$

$\Rightarrow x=\frac{\mathrm{60/}}{2}=30$

Let x = the youngest child. Each of the other four children will then be x+3, x+6, x+9, x+12.

We know that the sum of their ages is 50.

so, x+(x+3)+(x+6)+(x+9)+(x+12) = 50

=====>>>>>  x= 4

The youngest child is 4 years old.

If Rahul age is x, then Sachin age is x-7,
so (x-7)/x = 7/9
=> 9x-63 = 7x
=> 2x = 63
=> x = 31.5

So Sachin age is 31.5 – 7 = 24.5

 If ages in the numerical are mentioned in ratio A : B, then A : B will be Ax and Bx

1. At present: Ratio of their ages = 5 : 3. Therefore, 5 : 3 will be 5x and 3x.

=====>>>> Rohan’s age 4 years ago = 5x – 4
=====>>>> Rahul’s age after 4 years = 3x + 4

2. Ratio of Rohan’s age 4 years ago and Rahul’s age after 4 years is 1 : 1
Therefore,

Solving, we get x = 4

3. We are asked to find the ratio between Rohan’s age 4 years hence and Rahul’s age 4 years ago.
Rohan’s age : (5x + 4)
Rahul’s age: (3x – 4)
Ratio of Rahul’s age and Rohan’s age