Let the present ages of Mahesh, Nilesh and Ramesh be k, l and m respectively.
k/l = 5/x —— (1)
k = m – 18 —— (2)
m + 9 = 47 —— (3)
k – l = m —– (4)
(3) => m = 47 – 9 = 38 years
(2) => k = 38 -18 = 20 years
(1) => 20/l = 5/x => l = 4x
(4) => 4x – 20 = 38
=> 4x = 58 => x = 14.5

Let Raju’s age at the time of his marriage = X years

Then from given data

=> X + 8 = 6/5 X

X = 40.

Since got married 8 years ago, his present age  = 48

His sister is 10 years younger => 48 – 10 = 38 years.

Let the son’s present age be x years. Then, man’s present age = (x + 24) years
=> (x + 24) + 2 = 2(x + 2)
=> x + 26 = 2x + 4
So, x = 22

If Rahul age is x, then Sachin age is x – 7,
so, (x-7)/x =7/9
 9x – 63 = 7x
 2x = 63
 x = 31.5

So Sachin age is 31.5 – 7 = 24.5

Let father’s age be 3x and son’s age be x years

Father’s age after 5 years = 3x + 5 = 26 years

Son’s age after 5 years = x + 5 = 12 years

 Ratio of father’s and son’s ages = 26 : 12 = 13 : 6

Let age of the son before $10$ years $=x$ and
age of the father before $10$ years $=3x$

Age of the son at present $=x+10=20+10=30$
Age of the father at present $=3x+10=3\times 20+10=70$

Required ratio $=70:30=7:3$

Let Ayisha’s present age $=x$
Then, her father’s age $=6x$

Given that Ayisha’s father’s age will be twice Shankar’s age after $10$ years.
Therefore, Shankar’s age after $10$ years $=\frac{1}{2}(6x+10)=3x+5$

Also given that Shankar’s eight birthdays was celebrated two years before.
Therefore, Shankar’s age after $10$ years $=8+12=20$

$3x+5=20\Rightarrow x=\frac{\mathrm{15/}}{3}=5$
Therefore, Ayisha’s present age $=$ years

Let the rational between their ages be x

The present ages of Kiran and Shyam are in the ratio 5:4 respectively.

Thus the present age of Kiran and Shyam is 5x and 4x

Three years hence, the ratio of their ages will become 11:9 respectively.

Three years hence their ages 5x + 3 and 4x + 3

The ratio

5x+ 3 / 4x + 3 = 11/9

Cross multiplication

9 (5x + 3) = 11 (4x + 3)

45x + 27 = 44x + 33

45x – 44x = 33 – 27

x = 6

Rational is 6 therefore Kiran age 5x = 5 × 6 = 30 years and Shyam age 4x = 4 × 6 = 24 years

Answer Shyam present age is 24 years.

(A+B) – (B+C) = 12

A – C = 12.

C is younger than A by 12 years.

1) Let age of Rohan be y
2) Rahul is 15 years elder than Rohan = (y + 15). So Rahul’s age 5 years ago = (y + 15 – 5)
3) Rohan’s age before 5 years = (y – 5)
5 years ago, Rahul is 3 times as old as Rohan 
(y + 15 – 5) = 3 (y – 5)
(y + 10) = (3y – 15)
2y = 25
y = 12.5
Rohan’s age = 12.5 years
Rahul’s age = (y + 15) = (12.5 + 15) = 27.5 years

Let Aman’s present age be x
Aman’s age before 10 years = x – 10)
Aman’s age after 20 years = (x + 20)
We are given that, Aman’s age after 20 years (x + 20) is 10 times his age 10 years back (x – 10)
Therefore, (x + 20) = 10 (x – 10)
Solving the equation, we get x + 20 = 10x – 100
9x = 120, x = 13.3 years

10 years ago, age of mother was three times the age of her son. Say, the age of son was x and mother’s age was 3x.
At present: Mother’s age is (3x + 10) and son’s age is (x + 10)
After ten years: Mother’s age will be (3x + 10) +10 and son’s age will be (x + 10) + 10. Given that, mother’s age is twice that of son after ten years.
(3x + 10) +10 = 2 [(x + 10) + 10]
(3x + 20) = 2[x + 20]
Solving the equation, we get x = 20
(3x + 10): (x + 10) = 70: 30 = 7: 3.

Currently, the ratio of their ages is 5: 3. Suppose, their ages are: 5x and 3x.
Sara’s age 4 years ago = 5x – 4
Vaishali’s age after 4 years = 3x + 4
Ratio of Sara’s age 4 years ago and Vaishali’s age after 4 years is 1 : 1
Therefore,
(5x – 4) / (3x + 4) = 1/1
Solving, we get x = 4
We are required to find the ratio between Sara’s age 4 years hence and Vaishali’s age 4 years ago.
Sara’s age: (5x + 4)
Vaishali’s age: (3x – 4)
Putting the value of x, we get:
(5x + 4) / (3x – 4) = 3/1 = 3:1

Let the mother’s present age be x years.

Then, the person’s present age =		2	x		years.
		5

		2	x + 8		=	1	(x + 8)
		5				2

 2(2x + 40) = 5(x + 8)

 x = 40.

Let the present ages of son and father be x and (60 –x) years respectively.

Then, (60 – x) – 6 = 5(x – 6)

 54 – x = 5x – 30

 6x = 84

 x = 14.

 Son’s age after 6 years = (x+ 6) = 20 years..

Let the present ages of Sameer and Anand be 5x years and 4x years respectively.

 9(5x + 3) = 11(4x + 3)

 45x + 27 = 44x + 33

 45x – 44x = 33 – 27

 x = 6.

 Anand’s present age = 4x = 24 years.

Let the ratio 3 : 5 be ‘x’ years ago

(40 – x) / (60 – x) = 3 / 5

=> x = 10

Let present age of Sunil be x years, then Sushma’s present age is 2(x + 2) years.

According to the question,

Father’s present age is (20 + x) years.

Also,

20 + x = 1.5*2(x + 2)

20 + x = 3x + 6

2x = 14

x = 7 years

Mother’s present age = 18 years

Father’s present age = 27 years

Combined age of the family after 5 years,

7 + 5 + 18 + 5 + 27 + 5 = 67 years

Let B’s age = x years.
Then, As age = (x+ 9) years.
(x+9+10)=2(x—10)
hence x=39.
The present age of B = 39 years

Let C’s age be x years.

Let the present age of the person be x years.

Let the present ages of Ajay and Vijay be ‘A’ and ‘V’ years respectively.

=> A – 8 = 4/3 (V – 8) and A + 8 = 6/5 (V + 8)

=> 3/4(A – 8) = V – 8 and 5/6(A + 8) = V + 8

V = 3/4 (A – 8) + 8 = 5/6 (A + 8) – 8

=> 3/4 A – 6 + 8 = 5/6 A + 20/3 – 8

=> 10 – 20/3 = 10/12 A – 9/12 A

=> 10/3 = A/12 => A = 40.