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Ratio of the ages of Mahesh and Nilesh is 5 : x. Mahesh is 18 years younger to Ramesh. After nine years Ramesh will be 47 years old. If the difference between the ages of Mahesh and Nilesh is same as the age of Ramesh, what is the value of x ?

A.

11.8

B.

12.9

C.

13.7

D.

14.5

Answer with explanation

Answer: Option DExplanation

Let the present ages of Mahesh, Nilesh and Ramesh be k, l and m respectively.

k/l = 5/x —— (1)

k = m – 18 —— (2)

m + 9 = 47 —— (3)

k – l = m —– (4)

(3) => m = 47 – 9 = 38 years

(2) => k = 38 -18 = 20 years

(1) => 20/l = 5/x => l = 4x

(4) => 4x – 20 = 38

=> 4x = 58 => x = 14.5

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Raju got married 8years ago. His present age is 6/5 times his age at the time of his marriage Raju’s sister was 10years younger to him at the time of his marriage. The present age of Raju’s sister is ?

A.

30

B.

32

C.

38

D.

none

Answer with explanation

Answer: Option CExplanation

Let Raju’s age at the time of his marriage = X years

Then from given data

=> X + 8 = 6/5 X

X = 40.

Since got married 8 years ago, his present age = 48

His sister is 10 years younger => 48 – 10 = 38 years.

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A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is

A.

20

B.

21

C.

22

D.

23

Answer with explanation

Answer: Option CExplanation

Let the son’s present age be x years. Then, man’s present age = (x + 24) years

=> (x + 24) + 2 = 2(x + 2)

=> x + 26 = 2x + 4

So, x = 22

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Sachin is younger than Rahul by 7 years. If the ratio of their ages is 7:9, find the age of Sachin

A.

24.5

B.

25.5

C.

26.5

D.

27.5

Answer with explanation

Answer: Option AExplanation

If Rahul age is x, then Sachin age is x – 7,

so, (x-7)/x =7/9

9x – 63 = 7x

2x = 63

x = 31.5

So Sachin age is 31.5 – 7 = 24.5

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The ratio of the father’s age to the son’s age is 3 : 1. The product of their ages is 147. The ratio of their ages after 5 years will be?

A.

14 : 6

B.

12 : 6

C.

15 : 6

D.

13 : 6

Answer with explanation

Answer: Option DExplanation

Let father’s age be 3x and son’s age be x years

Father’s age after 5 years = 3x + 5 = 26 years

Son’s age after 5 years = x + 5 = 12 years

Ratio of father’s and son’s ages = 26 : 12 = 13 : 6

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The ratio of the age of a man and his wife is 4:34:3. At the time of marriage the ratio was 5:35:3 and After 44 years this ratio will become 9:79:7. How many years ago were they married?

A.

8 years

B.

10 years

C.

11 years

D.

12 years

Answer with explanation

Answer: Option DExplanation

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Present age of a father is 33 years more than three times the age of his son. Three years hence, father’s age will be 1010 years more than twice the age of the son. What is father’s present age?

A.

30 years

B.

31 years

C.

32 years

D.

33 years

Answer with explanation

Answer: Option DExplanation

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The age of father 1010 years ago was thrice the age of his son. Ten years hence, father’s age will be twice that of his son. What is the ratio of their present ages?

A.

7:3

B.

3:7

C.

9:4

D.

4:9

Answer with explanation

Answer: Option AExplanation

Let age of the son before 1010 years =x=x and

age of the father before 1010 years =3x=3x

(3x+20)=2(x+20)⇒x=20

Age of the son at present =x+10=20+10=30

Age of the father at present =3x+10=3×20+10=70

Required ratio =70:30=7:3

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My brother is 33 years elder to me. My father was 2828 years of age when my sister was born while my mother was 2626 years of age when I was born. If my sister was 44 years of age when my brother was born, then what was the age of my father when my brother was born?

A.

35 years

B.

43 years

C.

44years

D.

32 years

Answer with explanation

Answer: Option DExplanation

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Ayisha’s age is 1/6th of her father’s age. Ayisha’s father’s age will be twice Shankar’s age after 1010 years. If Shankar’s eight birthdays was celebrated two years before, then what is Ayisha’s present age.

A.

10 years

B.

12 years

C.

5 years

D.

4 years

Answer with explanation

Answer: Option CExplanation

Let Ayisha’s present age =x

Then, her father’s age =6x

Given that Ayisha’s father’s age will be twice Shankar’s age after 1010 years.

Therefore, Shankar’s age after 1010 years =12(6x+10)=3x+5

Also given that Shankar’s eight birthdays was celebrated two years before.

Therefore, Shankar’s age after 1010 years =8+12=20

3x+5=20⇒x=15/3=5

Therefore, Ayisha’s present age = 5 years

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The present ages of Kiran and Shyam are in the ratio 5:4 respectively. Three years hence, the ratio of their ages will become 11:9 respectively. What is Shyam’s present age in years?

A.

24

B.

26

C.

27

D.

28

Answer with explanation

Answer: Option AExplanation

Let the rational between their ages be x

The present ages of Kiran and Shyam are in the ratio 5:4 respectively.

Thus the present age of Kiran and Shyam is 5x and 4x

Three years hence, the ratio of their ages will become 11:9 respectively.

Three years hence their ages 5x + 3 and 4x + 3

The ratio

5x+ 3 / 4x + 3 = 11/9

Cross multiplication

9 (5x + 3) = 11 (4x + 3)

45x + 27 = 44x + 33

45x – 44x = 33 – 27

x = 6

Rational is 6 therefore Kiran age 5x = 5 × 6 = 30 years and Shyam age 4x = 4 × 6 = 24 years

**Answer Shyam present age is 24 years.**

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Father is aged three times more than his son Sunil. After 88 years, he would be two and a half times of Sunil’s age. After further 88 years, how many times would he be of Sunil’s age?

A.

4 times

B.

5 times

C.

2 times

D.

3 times

Answer with explanation

Answer: Option CExplanation

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Rahul is 15 years elder than Rohan. If 5 years ago, Rahul was 3 times as old as Rohan, then find Rahul’s present age.

A.

32.5 years

B.

27.5 years

C.

25 years

D.

24.9 years

Answer with explanation

Answer: Option BExplanation

1) Let age of Rohan be y

2) Rahul is 15 years elder than Rohan = (y + 15). So Rahul’s age 5 years ago = (y + 15 – 5)

3) Rohan’s age before 5 years = (y – 5)

5 years ago, Rahul is 3 times as old as Rohan

(y + 15 – 5) = 3 (y – 5)

(y + 10) = (3y – 15)

2y = 25

y = 12.5

Rohan’s age = 12.5 years

Rahul’s age = (y + 15) = (12.5 + 15) = 27.5 years

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What is Aman’s present age, if after 20 years his age will be 10 times his age 10 years back?

A.

6.2 years

B.

7.7 years

C.

13.3 years

D.

10 years

Answer with explanation

Answer: Option CExplanation

Let Aman’s present age be x

Aman’s age before 10 years = x – 10)

Aman’s age after 20 years = (x + 20)

We are given that, Aman’s age after 20 years (x + 20) is 10 times his age 10 years back (x – 10)

Therefore, (x + 20) = 10 (x – 10)

Solving the equation, we get x + 20 = 10x – 100

9x = 120, x = 13.3 years

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Ten years ago, the age of mother was three times the age of her son. After ten years, mother’s age will be twice that of his son. Find the ratio of their present ages.

A.

11 : 7

B.

9 : 5

C.

7 : 4

D.

7 : 3

Answer with explanation

Answer: Option DExplanation

10 years ago, age of mother was three times the age of her son. Say, the age of son was x and mother’s age was 3x.

At present: Mother’s age is (3x + 10) and son’s age is (x + 10)

After ten years: Mother’s age will be (3x + 10) +10 and son’s age will be (x + 10) + 10. Given that, mother’s age is twice that of son after ten years.

(3x + 10) +10 = 2 [(x + 10) + 10]

(3x + 20) = 2[x + 20]

Solving the equation, we get x = 20

(3x + 10): (x + 10) = 70: 30 = 7: 3.

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The ratio of Sara’s age 4 years ago and Vaishali’s age after 4 years is 1: 1. Presently, the ratio of their ages is 5: 3. Find the ratio between Sara’s age 4 years hence and Vaishali’s age 4 years ago.

A.

1 : 3

B.

3 : 1

C.

4 : 3

D.

3 : 4

Answer with explanation

Answer: Option BExplanation

Currently, the ratio of their ages is 5: 3. Suppose, their ages are: 5x and 3x.

Sara’s age 4 years ago = 5x – 4

Vaishali’s age after 4 years = 3x + 4

Ratio of Sara’s age 4 years ago and Vaishali’s age after 4 years is 1 : 1

Therefore,

(5x – 4) / (3x + 4) = 1/1

Solving, we get x = 4

We are required to find the ratio between Sara’s age 4 years hence and Vaishali’s age 4 years ago.

Sara’s age: (5x + 4)

Vaishali’s age: (3x – 4)

Putting the value of x, we get:

(5x + 4) / (3x – 4) = 3/1 = 3:1

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A person’s present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present?

A.

32 years

B.

36 years

C.

40 years

D.

48 years

Answer with explanation

Answer: Option CExplanation

Let the mother’s present age be *x* years.

Then, the person’s present age = | 2 | x |
years. | ||

5 |

2 | x + 8 |
= | 1 | (x + 8) |
|||

5 | 2 |

2(2*x* + 40) = 5(*x* + 8)

*x* = 40.

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The sum of the present ages of a father and his son is 60 years. Six years ago, father’s age was five times the age of the son. After 6 years, son’s age will be:

A.

12 years

B.

14 years

C.

18 years

D.

20 years

Answer with explanation

Answer: Option DExplanation

Let the present ages of son and father be *x* and (60 –*x*) years respectively.

Then, (60 – *x*) – 6 = 5(*x* – 6)

54 – *x* = 5*x* – 30

6*x* = 84

*x* = 14.

Son’s age after 6 years = (*x*+ 6) = 20 years..

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Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand’s present age in years?

A.

24

B.

27

C.

40

D.

Cannot be determined

Answer with explanation

Answer: Option AExplanation

Let the present ages of Sameer and Anand be 5*x* years and 4*x* years respectively.

Then, | 5x + 3 |
= | 11 |

4x + 3 |
9 |

9(5*x* + 3) = 11(4*x* + 3)

45*x* + 27 = 44*x* + 33

45*x* – 44*x* = 33 – 27

*x* = 6.

Anand’s present age = 4*x* = 24 years.

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Hiranya is 40 years old and Ramanya is 60. When was the ratio of their ages 3 : 5?

A.

8 years ago

B.

12 years ago

C.

10 years ago

D.

None of these

Answer with explanation

Answer: Option CExplanation

Let the ratio 3 : 5 be ‘x’ years ago

(40 – x) / (60 – x) = 3 / 5

=> x = 10

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Sushma’s present age is 2 times the age his son Sunil will attain two years later. Sunil who is 20 years younger to his father, who in present times is 1.5 times the age of Sushma, is a teen. What will be the combined age of the family after 5 years?

A.

52 years

B.

67 years

C.

55 years

D.

51 years

Answer with explanation

Answer: Option BExplanation

Let present age of Sunil be x years, then Sushma’s present age is 2(x + 2) years.

According to the question,

Father’s present age is (20 + x) years.

Also,

20 + x = 1.5*2(x + 2)

20 + x = 3x + 6

2x = 14

x = 7 years

Mother’s present age = 18 years

Father’s present age = 27 years

Combined age of the family after 5 years,

7 + 5 + 18 + 5 + 27 + 5 = 67 years

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In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is

A.

36 years

B.

43 years

C.

39 years

D.

41 years

Answer with explanation

Answer: Option CExplanation

Let B’s age = x years.

Then, As age = (x+ 9) years.

(x+9+10)=2(x—10)

hence x=39.

The present age of B = 39 years

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A is two years older than B who is twice as old as C. If the total of the ages of A, B, and C be 27, then how old is B?

A.

6 years

B.

10 years

C.

11 years

D.

9 years

Answer with explanation

Answer: Option BExplanation

Let C’s age be x years.

Then, B’s age = 2x years.

A’s age = (2x + 2) years.

(2x + 2) + 2x + x = 27

5x = 25

=> x = 5

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A person was asked to state his age in years. His reply was, “Take my age three years hence, multiply it by 3 and then subtract three times my age three years ago and you will know how old I am.” What was the age of the person?

A.

14 years

B.

20 years

C.

18 years

D.

22 years

Answer with explanation

Answer: Option CExplanation

Let the present age of the person be x years.

Then, 3(x + 3) – 3(x – 3) = x

3x + 9 – 3x + 9 = x

=> x = 18

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Eight years ago, Ajay’s age was 4/3 times that of Vijay. Eight years hence, Ajay’s age will be 6/5 times that of Vijay. What is the present age of Ajay?

A.

32 years

B.

40 years

C.

43 years

D.

37 years

Answer with explanation

Answer: Option BExplanation

Let the present ages of Ajay and Vijay be ‘A’ and ‘V’ years respectively.

=> A – 8 = 4/3 (V – 8) and A + 8 = 6/5 (V + 8)

=> 3/4(A – 8) = V – 8 and 5/6(A + 8) = V + 8

V = 3/4 (A – 8) + 8 = 5/6 (A + 8) – 8

=> 3/4 A – 6 + 8 = 5/6 A + 20/3 – 8

=> 10 – 20/3 = 10/12 A – 9/12 A

=> 10/3 = A/12 => A = 40.

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