A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
Answer with explanationAnswer: Option C
Let C’s age be x years. Then, B’s age = 2x years. A’s age = (2x + 2) years.
∴ (2x + 2) + 2x + x = 27
⇒ 5x = 25
⇒ x = 5.
Hence, B’s age = 2x = 10 years.
A father said to his son, “I was as old as you are at the present at the time of your birth”. If the father’s age is 38 years now, the son’s age five years back was
Answer with explanationAnswer: Option A
Let the son’s present age be x years. then,
Difference of father’s and son’s present age = Son’s present age
$(38 – x) = x $
So, the son’s age five years back was, x−5=19−5=14 years
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
Answer with explanationAnswer: Option B
Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
⇒ 5x = 20
⇒ x = 4.
∴ Age of the youngest child = x = 4 years.