Let C’s age be x years. Then, B’s age = 2x years. A’s age = (2x + 2) years.
∴ (2x + 2) + 2x + x = 27
⇒ 5x = 25
⇒ x = 5.
Hence, B’s age = 2x = 10 years.

Let the son’s present age be $x$ years. then,

Difference of father’s and son’s present age = Son’s present age

$(38 – x) = x $

$\iff$$2x=38$

$\iff$$x=19$

So, the son’s age five years back was, $x-5=19-5=14$ years

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.
Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50
⇒ 5x = 20
⇒ x = 4.
∴ Age of the youngest child = x = 4 years.

S+R+D+T = 78 – (i)
S = R + 4 – (ii)
D = T + 2 – (iii)
S = 7T – (iv)
7T = R+4
R= 7T – 4
h+w+d+s = 78 – (i)
7T+7T-4+T+2+T = 78
16T = 80
T = 5
d = T+2 = 5+2 = 7

X – mother; y-daughter

x – y = 30

y = x – 30

After 4 Years

x + 4 = 4 (y + 4)

x + 4 = 4 (x – 30 + 4)

x + 4 = 4x – 120 + 16

4 + 104 = 4x – x

3x = 108

X = 36 years

Let the present age of Nithya be, x

∴ the present age of Priya = x -8 and Divya = x – 2

According to the question,

(x-8) / (x-2) = 3/4

4x – 32 = 3x -6

x =26

Hence, the present age of Divya = 26 – 2 = 24 years

one year from now, D+d=s
two years after that, D+2+d+2=s+2
D+d-s=2-4=-2

Let Anuj’s age be X
Gopal is 2 years younger than Mohan, so Gopal is 3 years (i.e 5 – 2 = 3)
If Arun had born 6 years before, his age would had been X – 6. As per the question, X – 6 should be 18 times as that of Gokul’s age.
i.e. (X – 6) /18= 3
X-6 =3 x 18
x = 60

Let the age of Pranav be 7x and Praveen be 15x

According to the question,

15x-7x = 16

8x= 16

x= 2

Age of Pranav = 7*2 = 14 years

Age of Praveen= 15 * 2= 30 years

Amit’s age= 3*2= 6 years

Amit’s father age = 6* 4 = 24 years

When Karthik was born, his mother’s age was 28 years and his brother is 4 yrs elder to Karthik.

∴ Karthik mother’s age (at his brother’s birth) = 28 – 4 = 24 years

Karthik father was 30 years old when his sister was born. Karthik’s sister is 5 years elder to his brother.

∴ The age of Karthik father (at his brother’s birth) = 30 + 5 = 35 years

Hence, the age of Karthik mother and father was 24yrs and 35yrs

Given
The family consists of two grandparents, two parents and three grandchildren
The average age of two grandparents = 67 years.
=> Total age of two grandparents = (67 * 2) = 134 years

The average age of two parents = 35 years
=> Total age of two parents = (35 * 2) = 70 years

The average age of three grand children = 6 years.
=> Total age of three grand children = (6 * 3) = 18 years.

Required Average age of the family = Total age of (two grandparents + two parents + three grand children) / Total members in the family
= ( 134 + 70 + 18 ) / (2 + 2 + 3)
= 222 / 7
= 31 (5 / 7) years

Let, father’s current age is A years.
Then, Man’s current age =[ (2/5)A ]years.
Therefore, [ (2/5)A + 8 ]= (1/2)(A + 8)
2(2A + 40) = 5(A + 8)
A = 40

et the present ages of son and father be x and (60 – x) years respectively.

Let the current age of Ajay and Vijay be 7x and 4x respectively.

`(7x – 6) / (4x + 6) = 1/1`

7x – 6 = 4x + 6
3x = 12
x = 4
Therefore, `(7x + 12) / (4x – 12) = (7**4 + 12) / (4 ** 4 -12) = 40/4 = 10/1`

Let the present age of Ravi = r
Then we have R= 10 + 3 = 13 years as Ravi’s 10th Birthday was three years ago
Now we have Ravi’s age after 10 years = r + 10
=> 13 + 10
=> 23
Let the present age of Atif And Kayyum will be a and k
k + 10 = 2 * ( 10 + r )
=> k + 10 = 2 * 23
=> k = 46 -10
= 36.
Hence, Age of Atif = k / 6
=> 36 / 6
=> 6 years.

Let two years ago, the ages of Naresh and Suresh was 3X and 2X.

So one year hence, the ages of Naresh and Suresh would be 3X+3 and 2X+3 respectively.

As per question;

3x+3/2x+3=7/5

15X + 15= 14X + 21

X = 6

Present age of Naresh =3*6 + 2 = 20 years

Present age of Suresh = 2*6 + 2 = 14 years

∴Sum of their present ages = 20 + 14 = 34 years

Let 5 years age, the age of ashok, Anil and Ajay were 3x, 4x and 5x years. Then, their present ages are ( 3x + 5), (4x + 5) abd ( 5x + 5) years.
Now, 3x +5 + 4x +5 + 5x + 5 = 75 => 12x = 60 x = 5
Hence, present age of Anil = 4x + 5 = 4 x 5 + 5 = 25 years.

My brother was born 6 years after my sister was born and 3 years before I was born.
Age of father during my brother’s birth = (30 + 6) = 36 years.
Age of mother during my brother’s birth = (38 – 3) = 35 years.
Hence, during the birth of my brother, my father was 36 years old and my mother was 35 years old.

Let, Tanya age 16 years ago = x,
Grandfather’s age 16 years ago = 8x.

8 years from now, 3(x+16+8) = (8x+16+8)
=> x = 48/5

8 years ago Ratio was:
=> x + 8 / 8x + 8
=> 48 / 5 +( 8 ) / 8 * (48 / 5 ) + 8
=> 88 / 424
=> 11 / 53
the correct answer is 11 / 53=11:53

Let the present age of the father is 7X and present age of son is 2X.

As per question, ten years ago;

(7X – 10)+ (2X – 10) = 34

7X – 10 + 2X – 10= 34

9X = 34 + 20

9X = 54

X = 6

∴Present age of son = 2 * 6= 12 years

Let the age of Rahul, Sagar and Purav be x, y and z respectively
According to the given information
Age of Sagar – Age of Rahul = Age of Rahul – Age of Purav

Also y + z = 66 years
From (i) x = 33 years
Also as per equation (i) we have Purav’s age + Sagar age = 66 years
by going through option (A) given Purav = 18,

And also Rahul = 33 years, Sagar = 48 years
Difference between Rahul’s and Purav’s age = 18 years

Let A’s age 10 years ago = x years.
Then, B’s age 10 years ago = 2x years.
(x + 10) / (2x+ 10) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.

Let the present ages of Sameer and Anand be 5xyearsand4x5xyearsand4x years. respectiely

Then , 5x+34x+35x+34x+3  = 119119 ⇔⇔  9(5x+3)= 11(4x+3)9(5x+3)= 11(4x+3)    ⇔⇔    xx= 6

∴∴  Anand’s present age  = 4x4x  = 24 years.

Mother’s age when Virat’s brother was born = 36 years
Father’s age when Virat’s brother was born = (38 + 4) = 42 years
So, the difference between his parent’s age = (42 – 36) = 6 years