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Answer with explanation
Answer: Option AExplanation
Let the age of Rahul, Sagar and Purav be x, y and z respectively
According to the given information
Age of Sagar – Age of Rahul = Age of Rahul – Age of Purav
Also y + z = 66 years
From (i) x = 33 years
Also as per equation (i) we have Purav’s age + Sagar age = 66 years
by going through option (A) given Purav = 18, and Rahul = 33 years, Sagar = 48 years
Difference between Rahul’s and Purav’s age = 18 years
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The years ago A was half of B of age if the ratio of their present ages is 3: 4. What will be the total of their present ages?
8
20
45
35
Answer with explanation
Answer: Option DExplanation
A’s age 10 Years ago = x years
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Present ages of Sameer and Anand are in the ratio of 4 respectively. These years hence, the ratio of their ages will become 11: 9 respectively. What is Anand’s present age in years
27
24
40
None of these
Answer with explanation
Answer: Option BExplanation
Let the present ages of Sameer and Anand be 5xyearsand4x5xyearsand4x years. respectiely
Then , 5x+34x+35x+34x+3 = 119119 ⇔⇔ 9(5x+3)= 11(4x+3)9(5x+3)= 11(4x+3) ⇔⇔ xx= 6
∴∴ Anand’s present age = 4x4x = 24 years.
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Virat’s father was 38 years of age when he was born while his mother was 36 years old when his brother four years younger than to him was born. What is the difference between the ages of his parents?
2
6
4
8
Answer with explanation
Answer: Option BExplanation
Mother’s age when Virat’s brother was born = 36 years
Father’s age when Virat’s brother was born = (38 + 4) = 42 years
So, the difference between his parent’s age = (42 – 36) = 6 years
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The respective ages of father and his son are 41 and 16 years. In how many years will the father be twice as old as his son?
9
19
15
13
Answer with explanation
Answer: Option AExplanation
Suppose x years later the father will be twice as old as his son.
Then, x + 41 = 2 (x + 16)
⇒ x = 41 – 32 = 9 years
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3
5
6
7
Answer with explanation
Answer: Option CExplanation
According to the question,
(36 + n) / (50 + n) = 3/4
⇒ 144 + 4n = 150 + 3n
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Ten years ago, a man was seven times as old as his son. Two years hence, twice his age will be equal to five times the age of his son. What is the present age of the son?
12
13
15
14
Answer with explanation
Answer: Option DExplanation
Let son’s age 10 years ago be x years.
Then, man’s age 10 years ago = 7 years
Son’s present age = (x + 10) years,
Man’s present age = (7x + 10) years
Son’s present age = (x + 10) years
= (4 + 10) years
= 14 years
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Father’s age today is three times as his daughter’s. After 10 years it would be just twice. What is the daughter’s age today?
9
10
12
15
Answer with explanation
Answer: Option BExplanation
Let, today’s age of the daughter = ‘A’ years.
Mom’s age today = 3A years
After 1 decade,
3A + 10 = 29A + 10
=> A = 10 years
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Meena’s present age is three times her son’s present age and two fifth of her father’s present age. The average present age of all of them is 46 years. What is the difference between the Meena’s son’s present age and Meena’s father’s present age?
56
78
64
58
Answer with explanation
Answer: Option BExplanation
The ratio of present age of Meena and her son’s age = 3 : 1 (3x, x)
Meena’s present age = (2/5)*Meena’s father’s present age
Meena’s father’s present age = (15/2)x
According to the question,
x + 3x + (15/2) x = 138
(2x + 6x + 15x)/2 = 138
23x = 138*2
x = 12
Required difference = 90 – 12 = 78 years
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The age of father 1010 years ago was thrice the age of his son. Ten years hence, the father’s age will be twice that of his son. What is the ratio of their present ages?
7:3
3:7
4:9
9:4
Answer with explanation
Answer: Option AExplanation
Let age of the son before 1010 years =x=x and
age of the father before 1010 years =3x=3x
(3x+20)=2(x+20)⇒x=20(3x+20)=2(x+20)⇒x=20
Age of the son at present =x+10=20+10=30=x+10=20+10=30
Age of the father at present =3x+10=3×20+10=70=3x+10=3×20+10=70
Required ratio =70:30=7:3
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The sum of the present ages of father and his son is 60 years. Six years ago, the father’s age was five times the age of the son. After 6 years, the son’s age will be:
12 year
14 years
18 years
20 years
Answer with explanation
Answer: Option DExplanation
Let the present ages of son and father be x and (60 – x) years respectively.
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The ages of 10 students and their teacher are such that the average of first 7 student’s age is 15 years; an average of the last three student’s age is 11 years. The average age of all the students and their teacher together is 15 years. Find the age of the teacher.
24 years
27 years
30 years
33 years
Answer with explanation
Answer: Option BExplanation
Total age of 10 students and their teacher = 11 x 15 = 165 years.
Total age of first 7 students = 7 x 15 = 105 years
Total age of 3 students = 3 x 11 = 33 years
∴ Total age of 10 students = 105 + 33 = 138 years
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Ten years ago A was half of B in age. If the ratio of their present ages is 3: 4, what will be the total of their present ages
15
25
45
35
Answer with explanation
Answer: Option DExplanation
Let A’s age 10 years ago = x years.
Then, B’s age 10 years ago = 2x years.
(x + 10) / (2x+ l0) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.
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The ratio of Sara’s age 4 years ago and Vaishali’s age after 4 years is 1: 1. Presently, the ratio of their ages is 5: 3. Find the ratio between Sara’s age 4 years hence and Vaishali’s age 4 years ago.
3:4
Answer with explanation
Answer: Option BExplanation
Currently, the ratio of their ages is 5: 3. Suppose, their ages are: 5x and 3x.
Sara’s age 4 years ago = 5x – 4
Vaishali’s age after 4 years = 3x + 4
Ratio of Sara’s age 4 years ago and Vaishali’s age after 4 years is 1 : 1
Therefore,
(5x – 4) / (3x + 4) = 1/1
Solving, we get x = 4
We are required to find the ratio between Sara’s age 4 years hence and Vaishali’s age 4 years ago.
Sara’s age: (5x + 4)
Vaishali’s age: (3x – 4)
Putting the value of x, we get:
(5x + 4) / (3x – 4) = 3/1 = 3:1
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The age of father 10 years ago was thrice the age of his son. Ten years hence, the father’s age will be twice that of his son. The ratio of their present ages is:
5: 2
7 : 3
9: 2
13: 4
Answer with explanation
Answer: Option BExplanation
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
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