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Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand’s present age in years?

A.

24

B.

27

C.

40

D.

none of these

Answer with explanation

Answer: Option AExplanation

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A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?

A.

11

B.

8

C.

10

D.

11

Answer with explanation

Answer: Option CExplanation

Let C’s age be x years. Then, B’s age = 2x years. A’s age = (2x + 2) years.

∴ (2x + 2) + 2x + x = 27

⇒ 5x = 25

⇒ x = 5.

Hence, B’s age = 2x = 10 years.

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A father said to his son, “I was as old as you are at the present at the time of your birth”. If the father’s age is 38 years now, the son’s age five years back was

A.

14 years

B.

38 years

C.

19 years

D.

33 years

Answer with explanation

Answer: Option AExplanation

Let the son’s present age be x years. then,

Difference of father’s and son’s present age = Son’s present age

$(38 – x) = x $

⇔2x=38

⇔x=19

So, the son’s age five years back was, x−5=19−5=14 years

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The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?

A.

8 years

B.

4 years

C.

10 years

D.

none of these

Answer with explanation

Answer: Option BExplanation

Solution:

Let the ages of children be *x*, (*x* + 3), (*x* + 6), (*x* + 9) and (*x* + 12) years.

Then, *x* + (*x* + 3) + (*x* + 6) + (*x* + 9) + (*x* + 12) = 50

⇒ 5*x* = 20

⇒ *x* = 4.

∴ Age of the youngest child = *x* = 4 years.

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