Let the total distance be ‘d’.
WKT, Speed = Distance/Time
Given, first ant cover 8% of distance in 3 hours.
So, the speed of first ant = 8d/(100*3) = 8d/300 feet/hr

Also given, second ant covers 7/120 of distance in 2 hours 30 minutes.
Here, time = 2 hr 30 minutes = 2 (1/2) hr = 5/2 hr
So, speed of second ant = (7d*2)/(120*5) = 7d/300 feet/hr

If the first ant travelled 800 feet and meet the second ant ,
WKT, Time = Distance/Speed
Time taken by first ant = Time taken by second ant
800/ (8d/300) = (d -800)/ (7d/300)
(800*300)/8d = [(d – 800)*300]/7d
800/8 = (d – 800)/7
100 = (d – 800)/7
700 = d – 800
d = 1500 feet
Speed of second ant = 7d/300 = 7(1500)/300 = 35 feet/hr.