There are four hotels in a town. If 3 men check into the hotels in a day then what is the probability that each checks into a different hotel? A. 3/4 B. 1/4 C. 4/7 D. 3/8 Answer Workspace Report Discuss Answer with explanation Answer: Option D Explanation Total no.on ways to stay in a hotel without any condition = 4 x 4 x 4 = 64 ways. Bcoz, every person have 4 choices Now, if every person has to stay in the different hotels then no.of ways = 4×3×2 = 24 ways. Required probability =24/64 = 3/8 (or) Total cases of checking in the hotels = 4 x 4 x 4 = 64 ways. Cases when 3 men are checking in different hotels = 4×3×2 = 24 ways. Required probability =24/64 = 3/8 Workspace
Saran Harika says January 21, 2020 at 6:18 pm Total no.on ways to stay in a hotel without any condition = 4 x 4 x 4 = 64 ways. Bcoz, every person have 4 choices Now, if every person has to stay in the different hotels then no.of ways = 4×3×2 = 24 ways. Required probability =24/64 = 3/8 Reply
give me the proper explanation
Total no.on ways to stay in a hotel without any condition = 4 x 4 x 4 = 64 ways.
Bcoz, every person have 4 choices
Now, if every person has to stay in the different hotels then no.of ways = 4×3×2 = 24 ways.
Required probability =24/64 = 3/8