There are 2 trains P and Q moving in same direction. They are of equal length and cross a stationary pole in 5 seconds and 6 seconds respectively. In how much time would they cross each other? A. 60 seconds B. 30 seconds C. 11 seconds D. 1 seconds Answer Workspace Report Discuss Answer with explanation Answer: Option A Explanation Length of the train = l meter. Speed of the two trains are l/5 and l/6. Total distance = 2l. In same direction Relative speed is (l/5 – l/6). = l/5 – l/6 = l/30. Required Time = Distance/Speed. = 2l/(l/30) = 60 seconds. Shortcut method: Formula = 2(Product of time taken)/Difference of time taken. = 2(6 * 5)/(6 – 5) = 2 * 30 = 60 seconds. Workspace

chandru says April 10, 2021 at 10:24 am Length of the train = l meter. Speed of the two trains are l/5 and l/6. Total distance = 2l. In same direction Relative speed is (l/5 – l/6). = l/5 – l/6 = l/30. Required Time = Distance/Speed. = 2l/(l/30) = 60 seconds. Shortcut method: Formula = 2(Product of time taken)/Difference of time taken. = 2(6 * 5)/(6 – 5) = 2 * 30 = 60 seconds. Reply

chandru says

Length of the train = l meter.

Speed of the two trains are l/5 and l/6.

Total distance = 2l.

In same direction Relative speed is (l/5 – l/6).

= l/5 – l/6 = l/30.

Required Time = Distance/Speed.

= 2l/(l/30) = 60 seconds.

Shortcut method:

Formula = 2(Product of time taken)/Difference of time taken.

= 2(6 * 5)/(6 – 5) = 2 * 30 = 60 seconds.

Prasanna says

we updated the answer please check it once