Pipe A and B can fill a Tank alone in 48 Hours and 24 Hours respectively. Another Pipe C can empty the same Tank alone in 36 Hours. In an empty Tank for the First hour, Pipe A is opened alone, Second Hour pipe B is opened alone, Third Hour pipe C is opened alone. This process is continued until the Tank is filled. Then Pipe B is opened for How many Hours?
3 Hours work = (1/48+1/24-1/36) = 5/144
28* 3hours = 140/144
remaining part = 4/144 = 1/36
Now it’s A turn = 1/36-1/48
= 1/144 left
Now it’s B turn = 1/144*24 = 1/6 hour = 10 min
Total B = 28 Hours + 10 Min