L.C.M of two prime numbers x and y (x>y) is 161. The value of 3y-x is : A. -2 B. -1 C. 1 D. 2 Answer Workspace Report Discuss Answer with explanation Answer: Option A Explanation H. C. F of two prime numbers is 1. Product of numbers = 1 x 161 = 161. Let the numbers be a and b . Then , ab= 161. Now, co-primes with product 161 are (1, 161) and (7, 23). Since x and y are prime numbers and x >y , we have x=23 and y=7. Therefore, 3y-x = (3 x 7)-23 = -2 Workspace
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