In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples ? A. 6/7 B. 19/21 C. 7/31 D. 5/21 Answer Workspace Report Discuss Answer with explanation Answer: Option C Explanation Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ x ⁶C₁) As remaining person can be any one among three couples left. Required probability = (⁵C₂ x ⁶C₁)/¹⁰C₅ = (10 x 6)/252 = 5/21 Workspace
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