In a party there are 5 couples. Out of them 5 people are chosen at random. Find the probability that there are at the least two couples ?
Answer with explanationAnswer: Option C
Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ x ⁶C₁)
As remaining person can be any one among three couples left.
Required probability = (⁵C₂ x ⁶C₁)/¹⁰C₅
= (10 x 6)/252 = 5/21
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