If the area of the trapezium, whose parallel sides are 6 cm and 10 cm is 32 sq. cm, what will be the distance between the parallel sides? A. 2 cm B. 4 cm C. 5 cm D. 8 cm Answer Workspace Report Discuss Answer with explanation Answer: Option B Explanation Parallel sides of a trapezium = 6 cm, and 10 cm Area of trapezium =1/2 ( sum of the parallel sides ) × distance between the parallel sides 32=1/2 ( 6+10 ) × distance 32=8 × distance Distance = 32/8 = 4 cm So, the distance between the parallel lines of trapezium = 4 cm. Height = 4 cm Step-by-step explanation: Parallel sides = 6 cm and 10 cm Area of trapezium = 32 cm² ⇒ *(sum of || sides)* h = 32 ⇒ * (6 + 10) * h = 32 ⇒ 16 / 2 * h = 32 ⇒ 8 * h = 32 ⇒ h = 32 / 8 ⇒ h = 4 Workspace
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