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If Feb 12th,1986 falls on Wednesday then Jan 1st,1987 falls on which day?

A.

B.

Wednesday

C.

Thursday

D.

Saturday

Answer with explanation

Answer: Option CExplanation

The number of days more than the complete weeks are called odd days in a given period.

1 ordinary year ≡ 365 days ≡ (52 weeks + 1 day)

Hence the number of odd days in 1 ordinary year= 1.

1 leap year ≡ 366 days ≡ (52 weeks + 2 days)

Hence the number of odd days in 1 leap year= 2.

100 years ≡ (76 ordinary years + 24 leap years )

= (76 x 1 + 24 x 2) odd days = 124 odd days.

=> (17 weeks + 5 days)

≡ 5 odd days.

Hence the number of odd days in 100 years = 5.

Number of odd days—->Day of the week

==>0—->Sunday

==>1—->Monday

==>2—->Tuesday

==>3—->Wednesday

==>4—->Thursday

==>5—->Friday

==>6—->Saturday

last day of a century cannot be Tuesday or Thursday or Saturday.

because 100 century consists 5 odd days, means Friday is the last day.

200 century consists 3 odd days, means Wednesday is the last day.

300 century consists 1 odd day, means Monday is the last day.

400 century doesn’t consist any odd day.

the cycle continues, hence proof.

Solution: First, we count the number of odd days for the leftover days in the given period.

Here,given period is 12.2.1986 to 1.1.1987

Feb Mar Apr May June July Aug Sept Oct Nov Dec Jan

16 31 30 31 30 31 31 30 31 30 31 1 (left days)

2 + 3 + 2 + 3 + 2 + 3 + 3 + 2 + 3 + 2 + 3 + 1(odd days) = 1 odd day

So,given day Wednesday + 1 = Thursday is the required result.

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GAURANG says

How?

bhavika says

how??

jeni says

how??

usmanabdulla.T says

how is it?