If a 60 ml of water contains 12% of chlorine, how much water must be added in order to create a 8% chlorine solution? A. 40ml of water B. 50ml of water C. 30ml of water D. 35ml of water Answer Workspace Report Discuss Answer with explanation Answer: Option C Explanation Let x ml of chlorine be present in water. Then, 12/100 = x/60 → x = 7.2 ml Therefore, 7.2 ml is present in 60 ml of water. In order for this 7.2 ml to constitute 8% of the solution, we need to add extra water. Let this be y ml. Then, 8/100 = 7.2/y → y = 90 ml. So in order to get an 8% chlorine solution, we need to add 90-60 = 30 ml of water. Workspace
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