If a 60 ml of water contains 12% of chlorine, how much water must be added in order to create a 8% chlorine solution?
Answer with explanationAnswer: Option C
Let x ml of chlorine be present in water.
Then, 12/100 = x/60 → x = 7.2 ml
Therefore, 7.2 ml is present in 60 ml of water.
In order for this 7.2 ml to constitute 8% of the solution, we need to add extra water. Let this be y ml.
Then, 8/100 = 7.2/y → y = 90 ml.
So in order to get an 8% chlorine solution, we need to add 90-60 = 30 ml of water.
Discuss about the question