You are Here : Home » Aptitude » Permutations & Combinations From a pack of 52 cards, 3 cards are drawn together at random, What is the probability of both the cards are a king? A. 1/5225 B. 1/5525 C. 5525 D. 1/525 Answer Workspace Report Discuss Answer with explanation Answer: Option B Explanation Let S be the sample space n(S) = 52C_{3} = [( 52 x 51 x 50) / (3 x 2 x 1)] = 13600 / 6 = 22100 Let E = event of getting 3 kings out of 4. n(E) = 4C_{3} = [(4 x 3 x 2 x 1) / (3 x 2 x 1)] = 24/6 = 4 therefore, p(E) = [n(E) / n(S)] ==> p(E) = [ 4 / 22100] ==> p(E) = 1/5525 Workspace

Saran Harika says February 12, 2020 at 10:44 am Let S be the sample space n(S) = 52C_{3} = [( 52 x 51 x 50) / (3 x 2 x 1)] = 13600 / 6 = 22100 Let E = event of getting 3 kings out of 4. n(E) = 4C_{3} = [(4 x 3 x 2 x 1) / (3 x 2 x 1)] = 24/6 = 4 therefore, p(E) = [n(E) / n(S)] ==> p(E) = [ 4 / 22100] ==> p(E) = 1/5525 Reply

lokeswari says

explain in detail

lokeswari says

explain it in detail

Saran Harika says

Let S be the sample space

n(S) = 52C

_{3}= [( 52 x 51 x 50) / (3 x 2 x 1)] = 13600 / 6 = 22100Let E = event of getting 3 kings out of 4.

n(E) = 4C

_{3}= [(4 x 3 x 2 x 1) / (3 x 2 x 1)] = 24/6 = 4therefore, p(E) = [n(E) / n(S)]

==> p(E) = [ 4 / 22100]

==> p(E) = 1/5525