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Atif’s age is 1/6th of his father’s age. Atif’s father, Kayyum’s age will be twice the age of Ravi’s age after 10 years. If Ravi’s tenth birthday was celebrated three years before, then what is Atif’s present

A.

B.

C.

D.

Answer with explanation

Answer: Option DExplanation

Let the present age of Ravi = r

Then we have R= 10 + 3 = 13 years as Ravi’s 10th Birthday was three years ago

Now we have Ravi’s age after 10 years = r + 10

=> 13 + 10

=> 23

Let the present age of Atif And Kayyum will be a and k

k + 10 = 2 * ( 10 + r )

=> k + 10 = 2 * 23

=> k = 46 -10

= 36.

Hence, Age of Atif = k / 6

=> 36 / 6

=> 6 years.

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