An inlet pipe fills a tank at the rate of 5 liters of water a minute. An outlet connected to the tank can empty a full tank in 5 hours. Both the pipes are opened together for 30 minutes and then, the outlet is closed. It took another 36 minutes to fill the tank. Find the capacity of the tank.
Let the inlet pipe take X minutes to fill the tank.
Part of the tank filled by the inlet in a minute = (1/x)
Part of the tank emptied by the outlet in a minute = 1/(5*60) = 1/300
Part of the tank filled in the first 30 minutes = 30×[(1/x)-(1/300)] = (300 – X)/10x
Part of the tank filled in the next 36 minutes = 36*(1/x) 1 – [(300 – x)/10x] 36/x
Solving, x = 60 Capacity of the tank = 60 × 5 = 300 liters