One year ago a father was four times as old as his son .after 6 year his age exceed than twice of his son age by 9 year. Ratio of their present age is what A. 30 yrs. B. 33 yrs. C. 20 yrs D. 11 yrs Answer Workspace Report Discuss Answer with explanation Answer: Option B Explanation Lets denote the ages of the man and his son as M and S respectively. One year ago their ages were M – 1 and S – 1 respectively. So from the first statement, M – 1 = 4 * (S – 1) or M – 4*S = -3 ← Equation 1 In 6 years time both would be older by 6 years, or M+6 and S+6. From the second statement, M + 6 = 2 * (S +6) + 9, or M – 2*S = 15 ← Equation 2 Subtracting Equation 1 from Equation 2, we get: M – 2*S – (M – 4*S) = 15 – (-3) That is, 2*S = 18 , or S = 9. Therefore the Son’s present age is 9. From Equation 2, M = 15 + 2*S or M = 15 + 18 = 33. Therefore the Father’s present age is 33. Workspace

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