A Learning Portal from Recruitment India

You are Here :
Home » Aptitude » Permutations & Combinations

A question paper consists of three sections 4,5 and 6 questions respectively. Attempting one question from each section is compulsory but a candidate need not attempt all the questions. In how many ways can a candidate attempt the questions?

A.

119

B.

29295

C.

209

D.

(4!-1) × (5!-1) × (6!-1)

Answer with explanation

Answer: Option BExplanation

At least 1 question from each section is compulsory, so from the 1^{st} section the candidate can attempt 1 or 2 or 3 or 4 questions.

In each section each question can be dealt with in 2 ways, i.e. either he attempts it or leaves it.

So far 4 question there are 2 × 2 × 2 × 2 ways to attempt.

As he has to attempt at least 1 question, the total number of ways in which he can attempt questions from 1st section is 2^{4} – 1

Similarly for the 2^{nd} section there are 2^{5} – 1 ways in which he can attempt and for the 3^{rd} section there are 2^{6} – 1 ways.

The ways in which the attempts one or more questions in any section is independent of the number of ways in which he attempts one or more questions from the other sections.

Thus, total number of ways in which he can attempt questions in that paper:

= (2^{4} – 1)(2^{5} – 1)(2^{6} – 1)

= 15 × 31 × 63

= 29295

Workspace

## Discuss about the question