A pipe can empty a tank in 12 minutes and another pipe can empty it in 16 minutes. If both the pipes are opened simultaneously, find the time in which a full tank is emptied?
Pipes A and B can fill the tank in 12 and 16 hours respectively. Therefore,
part filled by pipe A in 1 hour = 1/12
part filled by pipe B in 1 hour = 1/16
the quantity filled if all the pipes are opened together = 1/12 + 1/16
how 66/7comes
Pipes A and B can fill the tank in 12 and 16 hours respectively. Therefore,
part filled by pipe A in 1 hour = 1/12
part filled by pipe B in 1 hour = 1/16
the quantity filled if all the pipes are opened together = 1/12 + 1/16
==> [(16+12)/ 192] ( L. C. M of 16 & 12)
==> (28 / 192)
==> (7 / 48)
Required time = 48 / 7 = 6 6/7
plzz repeat sir
Pipes A and B can fill the tank in 12 and 16 hours respectively.
Therefore,part filled by pipe A in 1 hour = 1/12
part filled by pipe B in 1 hour = 1/16
the quantity filled if all the pipes are opened together = 1/12 + 1/16
==> [(16+12)/ 192] ( L. C. M of 16 & 12)
==> (28 / 192)
==> (7 / 48)
Required time = 48 / 7 = 6(6/7)
mam here it is saying about emptying the tank in mins.. I don’t get it !!
Pipes A and B can empty the tank in 12 and 16 hours respectively.
Therefore,part empty by pipe A in 1 hour = 1/12
part empty by pipe B in 1 hour = 1/16
the quantity empty if all the pipes are opened together = 1/12 + 1/16
==> [(16+12)/ 192] ( L. C. M of 16 & 12)
==> (28 / 192)
==> (7 / 48)
Required time = 48 / 7 = 6(6/7)
s it is in min
yes. the answer is in minutes
Need the answer plz
the answer is 6(6/7). none of these check it once