A man is standing on the deck of a ship, which is 10m above water level. He observes the angle of elevation of the top of a light house as 600 and the angle of depression of the base of lighthouse as 300. Find the height of the light house. A. 30m B. 40m C. 45m D. 38m Answer Workspace Report Discuss Answer with explanation Answer: Option B Explanation from A is 60 ° Then ∠EAD= 60° & ∠CAE= ∠BCA= 30°. (Alternate ANGLES) Let AD = BC = x m & DE= h m In ∆ ADE tan 60° = Perpendicular / base = DE/AD √3= h/x [tan 60° = √3] h = √3x……..(1) In ∆ ABC tan 30° = AB /BC [ tan30° = 1/√3] 1/√3 = 10/x x= 10√3 m.. …………..(2) Substitute the value of x from equation (2) in equation (1), we have h = √3x h= √3× 10√3= 10 × 3= 30 m h = 30 m The height of the hill is CE= CD+ DE= 10 +30= 40 m Hence, the height of the hill is 40 m & the Distance of the hill from the ship is 10√3 m. Read more on Brainly.in – https://brainly.in/question/1001119#readmore Workspace
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