A boat takes half time in moving a certain distance downstream than upstream. What is the ratio between the rate in still water and rate of current?
Answer with explanationAnswer: Option B
Let the speed of the boat in still water be 4 km/hr and speed of the current be u km/hr.
Rate downstream = (u + v) km/hr.
Rate upstream = (u- v)km/hr
Let the distance covered in each case be x km.
Then 2x/(u + v) = x / (u – v)
=> 2 (u – v) = ( u + v)
=> u =3v
=> u/v =3/1
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